PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Question
Chapter 3, Problem 18P
To determine
The design speed of the curve, the elevation of the
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An equal-tangent sag vertical curve is designed for 100 kph. The lowest point is at elevation 308.0 m. The initial grade is -2% and the final grade is +1%. What is the elevation of the PVC?
An equal-tangent crest vertical curve is designed for 70 mi/h. The high point is at elevation 1011.4 ft. The initial grade is +2% and the final grade is -1%. What is the elevation of the PVT?
3.7 An equal-tangent crest vertical curve is designed
for 65 mi/h. The initial grade is +3.4% and the final
grade is negative. What is the elevation difference
between the PVC and the high point of the curve?
Chapter 3 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- A vertical curve is to be designed. The PVI station and elevation are 360+10 and 625 ft respectively. The curve is 650 ft long curve. The initial and final grades are -3% and +2.5%? (a) Calculate the station and elevations at PVC and PVT (b) Find the station and elevation at the lowest point on the curve (c) Calculate the station and elevation at the curve's midpointarrow_forward2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00 with its elevation of 1,005 ft. Please determine following. a. PVC station b. PVC elevation C. PVT station d. PVT elevation e. The station where the highest elevation is located f. The highest elevation on the road g. The stations where the road elevation is 995 feet. Crest Vertical Curve PVI = 110+00 sta Design Speed: 70 mph Yev= 1,005' PVI Highest elevation PVI 2.5% -2.0% PVC PVT Elevation = 995 ft L=1,115 ftarrow_forwardA vertical curve connects a -3% grade with a 4% grade. The point of the vertical curve is at station 34+70 and the point of vertical intersection at station 38+20. What is the offset at the low point of the curve (in feet)?arrow_forward
- 1. (Crest Vertical Curve) A vertical curve is designed for 55 mi/h and has an initial grade of +2.5% and a final grade of -1.0%. The PVT is at station 114 + 25. It is known that a point on the curve at station 112 + 75 is at elevation 240 ft. What is the stationing and elevation of the PVC? What is the stationing and elevation of the high point on the curve?arrow_forwardA sag vertical curve will connect a -1% grade to a 3% grade with a design speed of 50 mph. Using the three criteria (i.e., not K factors), what is the minimum length of the curve?arrow_forwardAn equal-tangent crest vertical curve is designed for 45 mi/h. The high point is at elevation 380.10 ft. The initial grade is +1.90% and the final grade is -3.10%. What is the elevation of the PVT? You answer must be in ft and rounded to the second digit (e.g., 0.00), if you need to use values from tables, use "design" values (usually last column), not "calculated".arrow_forward
- An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2arrow_forwardA sag vertical curve joins a -6% grade and +5% grades. If the PVI of the grades is at Station 355+50 and at an elevation of 156 ft., determine the station and elevation of the PVC, PVT, and the low point for a design speed of 60 mph. Sketch the curve and label the PVI, PVC, PVT and the low point with their stations and elevations. Note: You should check the stopping sight distance criterion and riding comfort design criteria, using the one that controls. 2.arrow_forwardAn equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110 + 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.arrow_forward
- Highway Engineering: You are designing a highway to AASHTO guidelines on rolling terrain where the design speed will be 65 mi/h. At one section, a +1.25% grade and a -2.25% grade must be connected with an equal-tangent vertical curve. Determine the SSD given the reaction time of 2.5 sec and deceleration of 3.4 m/s^2. Determine also the minimum length of curve.arrow_forwardA 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.arrow_forwardA 1400-ft–long sag vertical curve (equal tangent) has a PVC at station 115 + 00 and elevation 750 ft. The initial grade is -3.5% and the final grade is +6.5%. Determine the elevation and stationing of the low point, PVI, and PVT.arrow_forward
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