PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 3, Problem 26P
To determine
The number of feet below the railway at which the curve PVI should be located.
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2. (Sag Vertical Curve) An existing highway-railway at-grade crossing is being
redesigned as grade separated to improve traffic operations. The railway must
remain at the same elevation. The highway is being reconstructed to travel under
the railway. The underpass will be a sag curve that has an initial grade of -2% and
a final grade of 2%. The PVI of the sag curve will be centered under the railway
(a symmetrical alignment). The sag curve design speed is 45 mi/h. How many feet
below the railway should the curve PVI be located?
A sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of the proposed curve is at elevation 312 ft and the bottom of the overpass is at elevation 329 ft. The curve is being designed to match a -2.3% grade to a 2.5% grade at a design speed of 40 mph. If the curve is positioned to give maximum clearance to the overpass, will it provide at least 15 ft of clearance? Please do all calculations in feet so I can check my answer. Include a sketch of the curve
A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and Elevation 300.00 on a
two-lane highway with a design speed of 45 mph. Assume AASHTO Standards.
1. Determine the minimum length for the curve that is designed to meet passing sight
distance using K-value method
2. Determine the Station and Elevation of the PVC
Chapter 3 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- A crest vertical curve joining a + 3 percent and – 4 percent grade is to be designed for 75 mph. If the tangent intersect at station (345 + 6000) at an elevation of 250 ft, determine the stations and elevations of the PVC and PVT.arrow_forwardQ6. To help improve the safety of at-grade intersection of two roads, the intersection is being redesigned so that the E-W road will pass underneath the N-S road. Currently the vertical alignment of the E-W road consists of a crest vertical curve joining a 4% upgrade to a 3% downgrade. The existing vertical curve is 138 m long, the PVC of this curve is at station 14+47, and the elevation of the PVC is 477 m. The centerline of the N-S road is at station 15+45. Your job is to find the shortest vertical curve that provides 6.0 m of clearance between the new E-W road and the N-S road.arrow_forward1. A crest vertical curve connects a +1.5 % grade with a -2.5 % grade on a two-lane highway. The criterion selected for design is the minimum stopping sight distance for a design speed of 90 km/h based on AASHTO (2004) design criteria. If the grades intersect at station (14+465) at an elevation of 100 m, compute the station and elevation of BVC, EVC, and highest point. Also, compute the elevation of the curve at 50-m intervals. Display all results in a tabular form.arrow_forward
- An equal-tangent vertical curve is to be constructed between grades of -2.0% (initial) and +1.0% (final). The PVI is at station 110 + 00 and at elevation 420 ft. Due to a street crossing the roadway, the elevation of the roadway at station 112 + 00 must be at 424.5 ft. Design the curve.arrow_forwardAn existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is −3% and the elevation of the PVT is 754 ft. The PVC of the curve is at station 134 + 16 and the PVI is at 137 + 32. An overpass is being constructed directly above the PVI. The highway is for cars only (AASHTO minimum and recommended structure clearances do not apply) and the overpass design assumes the driver's eye height is set conservatively to 5 ft and the object height is 2 ft. What is the lowest possible elevation of the bottom of the overpass structure to ensure sufficient stopping sight distance at 60 mi/h? (Use Table 3.3 to determine K-value)arrow_forwardA horizontal curve is being designed for a new four-lane roadway with 11-ft lanes. The PT is located at station 1050+20, the design speed is 45 mph and maximum superelevation of 4%. If the central angle of the curve is 30 degrees, what is the radius of the curve and location of the PC and PI?arrow_forward
- An existing roadway has a crest vertical curve with a PVC at station 94+12.00 at elevation 480.00 and a PVT at station 99+42.00 at elevation 482.50. The incoming grade (at the PVC) is +4.29%. Determine the station and elevation of the PVI and the station and elevation of the high point.arrow_forwardProblem 2. This is a four-part problem. A +2.5% grade intersects with a –1.5% grade at station (735 + 30.75) at an elevation of 475 ft. Part A. If the design speed is 65 mi/h, determine the minimum length, in ft, of vertical curve. Part B. If the design speed is 65 mi/h, determine the elevation, in ft, of the point of vertical tangency also known as end of vertical curve. Part C. If the design speed is 65 mi/h, determine the elevation, in ft, of the highpoint of the curve. Part D. If the design speed is 65 mi/h, determine the distance, in ft, from the point of vertical curvature (also known as the beginning of curve) to the highpoint of the curve.arrow_forwardHighway Engineering: You are designing a highway to AASHTO guidelines on rolling terrain where the design speed will be 65 mi/h. At one section, a +1.25% grade and a -2.25% grade must be connected with an equal-tangent vertical curve. Determine the SSD given the reaction time of 2.5 sec and deceleration of 3.4 m/s^2. Determine also the minimum length of curve.arrow_forward
- An equal-tangent curve connects a +1.0% and a -0.5% grade. The PVC is at station 54+24 and the PVI is at station 56+92. Is this curve long enough to provide passing sight distance for a 60-mi/r design speed? Problem 2 An overpass is being built over the PVI of an existing equal-tangent curve. The curve has a 70- mi/h design speed and G1 = -5%, G2= +3%. Determine the minimum necessary clearance height of the overpass and the resultant elevation of the bottom of the overpass over the PVI. (Ignore the cross-sectional width of the overpass.)arrow_forwardA tangent section of highway has a -1.0% grade and ends at station 4+75 and elevation 82 ft. It must be connected to another section of highway that has a -1% grade and that begins at station 44+12 and elevation 131.2 ft. The connecting alignment should consist of a sag curve, and be designed for a speed of 50 mi/h. What is the lowest grade possible for the constant-grade section that will complete this alignment?arrow_forwardA +3.00% grade intersects a -2.40% at station 46+70.00 and elevation 853.48 ft. A 400.00 ft curve will be used to connect the two grades. Compute Station and elevation for the curve's endpoints.arrow_forward
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