PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Question
Chapter 3, Problem 46P
To determine
The station of the PTof the curve.
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A sag curve connects a -1.5 percent grade with a +2.5 percent grade on a rural arterial highway. The criterion selected for design is the minimum stopping sight distance, and the design speed of the highway is 70 mph. Assume the perception-reaction time of 2.5 seconds and a deceleration rate of 11.2 ft./sec^2.
a. Determine the length of the curve.
b. Compute the elevation of the curve at PVC and PVT if the grades intersect at station (475 + 00) at an elevation of 300 ft.
A horizontal curve is being designed for a new two-lane highway (3.6-m lanes).
The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of
0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the
highway by computing the radius and stationing of the PC and PT.
(TRAFFIC AND HIGHWAY ENGINEERING)
A highway segment has an equal-tangent sag curve and a horizontal curve with the same design speed. It is known that the sag curve has an initial grade of –1.8% and a positive final grade that is not known. The station of the PVC is 232 + 70, and the station of the low point of the sag vertical curve is 235 + 14.8. The horizontal curve has a superelevation of 8%, central angle of 30 degrees, and a PT at Station 302 + 20. The road has two 11-ft lanes (one in each direction). What is the station of the PI?
Chapter 3 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- Q: A horizontal curve is being designed through mountainous terrain for a four- ane with lanes that are 3 m wide. The central angle is known to be 40 degrees, the tangent distance is 155m, and the stationing of the tangent intersection (PI) 'is 8 + 23. Under specified conditions and vehicle speed, the roadway surface is determined to have a coefficient of side friction of 0.08, and the curve's superelevation is 0.09. what is the stationing of the PC and PT and what is the safe vehicle speed?arrow_forwardProblem 2. A horizontal curve is being designed for a two-lane highway (12-ft lanes). The PC is at station 1200 + 50, the design speed is 70 mph, and a design superelevation of 0.08 ft/ft is to be used. Central angle of the curve is 40 degrees. (1) What is the min radius (measured to the centerline of the inside-most lane)? (2) Use the min value in your design, determine the station of PT. A = 40' e = 0.08 V = 70 mph PC = 1200150 1 +3 3131(6(vtoner) =951.88 -Simple Circular curves - reverse curtes- compound curves - spr e bus of Sogements Options curves fs=0.08 9=32.174H/S²arrow_forwardThe design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The localjurisdiction governs 8% superelevation. The central angel of the curve is 40 degrees. The PI station is at 452+50.What is the curve radius to the travel path (R)? What is the curve radius (R)? What is the curve length (L)? What isthe station of PC? What is the station of PT? What is the SSD? How many feet must be cleared from the lane'sshoulder edge to provide adequate stopping sight distance?arrow_forward
- A section of a two-lane highway (12-ft lanes) is designed for 75 mph. At one point, a vertical curve connects a -2.5% and +1.5% grade. The VPT of this curve is at station 25+00. It is known that a horizontal curve starts (has PC) 292 ft before the vertical curve VPC. If the superelevation of the horizontal curve is 0.08 and the central angle is 38 degrees, what is the station of the PT?arrow_forwardA horizontal curve is being designed for a new four-lane roadway with 11-ft lanes. The PT is located at station 1050+20, the design speed is 45 mph and maximum superelevation of 4%. If the central angle of the curve is 30 degrees, what is the radius of the curve and location of the PC and PI?arrow_forwardA section of a two-lane, two-way highway (2 @ 3.5 m) is to be designed with a circular curve. Sta. Pl at 200 + 100.000 Design speed = 60 kph Intersection angle = 40 degrees Rate of change of acceleration: 0.5 m/sec2arrow_forward
- An equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20arrow_forwardA horizontal curve is to connect PC on freeway B and PT on freeway A to serve traffic turning from freeway B be two freeway A if the design speed is 45 mph (66 ft per second) super elevation is 2.5 and the coefficient of friction between tire and pavement is .10 what should be the minimum radius of the horizontal curve in feet?arrow_forwardQ1) Answer the following A) A section of a two-lane highway (12-ft lanes) is designed for 75 mi/h. At one point a vertical curve connects a -2.5% and +1.5% grade. The vertical curve ends at station 36 + 50. It is known that a horizontal curve starts 294 ft before the starting of the vertical curve. If the superelevation of the horizontal curve is 8% and the central angle is 38 degrees, what is the station of the beginning of the horizontal curve?arrow_forward
- A horizontal Curve is designed for a two lane mountainous terrain. The following data are known. intersection angle: 40 degrees tangent length: 436.76 ft Station on PI: 2700+10.65 fs=0.12 e=0.08 Find the following Design speed Station of the PC Station of the PT Deflection Angle and chord length to the first even 100 ft stationarrow_forwardAn equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.arrow_forwardA vertical curve is going to be designed to join a 0% grade with a +5% grade at a section of a highway. The station and elevation of the PVC point are 5+00 and 12 ft, respectively. Assuming AASHTO design standard values for perception-reaction time, deceleration rate for braking, and driver’s eye and object heights, determine the following: 1. The min length of the curve if the design speed is 65 mi/h. 2. The station and elevation of the PVT. 3. The station and elevation of the high or low point. 4. The elevation of the point at station 6+50.arrow_forward
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