PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 3, Problem 30P
To determine
The station and elevation of the low point.
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An equal-tangent sag vertical curve is designed for 100 kph. The lowest point is at elevation 308.0 m. The initial grade is -2% and the final grade is +1%. What is the elevation of the PVC?
A 500-ft-long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1322 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.
Solve this problem using parabolic equation and offset method.
Compute:
A 520 ft long equal-tangent crest vertical curve connects tangents that intersect at
station 340+00 and elevation 1325 ft. The initial grade is +4.0% and the final grade
is -2.5%.
Determine the stationing and elevation of the PVC, PVT, and high point.
Chapter 3 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- A +4.0% grade intersects a -3.0% percent grade at PVI Sta. 222+00 and two-lane highway with a design speed of 45 mph. Assume AASHTO Standards. 1. Determine the minimum length for the curve that is designed to meet passing sight distance using K-value method 2. Determine the Station and Elevation of the PVC Duoblem 1arrow_forwardHighway engineering: A 520-ft–long equal-tangent crest vertical curve connects tangents that intersect at station 340 + 00 and elevation 1325 ft. The initial grade is +4.0% and the final grade is -2.5%. Determine the elevation and stationing of the high point, PVC, and PVT.arrow_forwardAn underpass, designed to be a vertical sag curve, is to be constructed parallel to an existing horizontal road with an elevation of 120 m such that the lowest point of the curve is directly below the center-line of the road with a clearance of 5.5 m. If the vertical curve has grades of -4% and +3% and PI is at an elevation of 105 m, determine the required length of the curve.arrow_forward
- A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The initial grade is 3.5% and the final grade is -3%. Determine the station of the highest point of the curvearrow_forwardA plus 5.0 percent grade intersects a minus 3.0 percent grade at station 4 + 10 and at an elevation of 460.60 ft. Given that a PVC station 3+00 is utilized. Determine the length of curve, PVT station, EPVC and EPVT?arrow_forwardA sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of the proposed curve is at elevation 312 ft and the bottom of the overpass is at elevation 329 ft. The curve is being designed to match a -2.3% grade to a 2.5% grade at a design speed of 40 mph. If the curve is positioned to give maximum clearance to the overpass, will it provide at least 15 ft of clearance? Please do all calculations in feet so I can check my answer. Include a sketch of the curvearrow_forward
- 1. A crest vertical curve connects a +1.5 % grade with a -2.5 % grade on a two-lane highway. The criterion selected for design is the minimum stopping sight distance for a design speed of 90 km/h based on AASHTO (2004) design criteria. If the grades intersect at station (14+465) at an elevation of 100 m, compute the station and elevation of BVC, EVC, and highest point. Also, compute the elevation of the curve at 50-m intervals. Display all results in a tabular form.arrow_forwardA sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of the proposed curve is at elevation 312 ft and the bottom of the overpass is at elevation 329 ft. The curve is being designed to match a -2.3% grade to a 2.5% grade at a design speed of 40 mph. If the curve is positioned to give maximum clearance to the overpass, will it provide at least 15 ft of clearance? Include a sketch of the curvearrow_forward2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00 with its elevation of 1,005 ft. Please determine following. a. PVC station b. PVC elevation C. PVT station d. PVT elevation e. The station where the highest elevation is located f. The highest elevation on the road g. The stations where the road elevation is 995 feet. Crest Vertical Curve PVI = 110+00 sta Design Speed: 70 mph Yev= 1,005' PVI Highest elevation PVI 2.5% -2.0% PVC PVT Elevation = 995 ft L=1,115 ftarrow_forward
- A crest vertical curve connects a +4.44 % grade and a -6.87 % grade. The PVI is located at station 43 + 50.00 at an elevation of 1,240.00 feet. The design speed is 30 mph. Determine the following: The length of the vertical curve using the AASHTO method (“K” factors) (1/8 pts.) The station of the PVC/BVC (1/8 pts.) The station of the PVT/EVC (1/8 pts.) The station of the high point (1/8 pts.) The elevation of the PVC/BVC (1/8 pts.) The elevation of the PVT/EVC (1/8 pts.) The elevation of the high point (1/8 pts.) The elevation of station 44+ 23.23 (1/8 pts.)arrow_forward3.12 An equal-tangent crest vertical curve connects a +3.2% and a -1.1% grade. The PVI is at station 98 + 20. Due to drainage considerations, the highest point of the curve is at station 100+79.35. Determine the station of the PVC and PVT, and the design speed of the curve.arrow_forwardQuestion # 5 An existing crest vertical curve which connects +3% and -1% grades is designed for 55 MPH. The curve is to be re-constructed for a 65 MPH design speed. The PVI of the new curve will remain the same as the existing curve but the PVC and PVT will change to accommodate the new curve length. The existing curve's PVT is situated at station 40+00 and the elevation of the existing curve directly below the PVI is 179.22 ft. Stations increase from PVC to PVT. Determine: a. The stations of the new curve at PVC and PVT b. The elevations of the new curve at PVC and PVT c. Determine depth of excavation (d) at PVI station from existing to the new curve. PVC₂ PVC₁ 91 +3% New Curve PVI 92= -1% Elevation 179.22 Station 40+00 PVT₁ PVT2arrow_forward
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