Thermodynamics, Statistical Thermodynamics, & Kinetics
Thermodynamics, Statistical Thermodynamics, & Kinetics
3rd Edition
ISBN: 9780321766182
Author: Thomas Engel, Philip Reid
Publisher: Prentice Hall
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 3, Problem 3.3NP
Interpretation Introduction

Interpretation:

The value of q, w, ΔU and H needs to be determined for the given conditions considering ideal gas behavior for the matter.

Concept Introduction:

The ideal gas equation is used to find out the volume of any gas produced under given conditions as follows:

  PV=nRTWhere, P= Pressure, V=volume, n= number of moles, R= universal gas constant and T= temperature

From first law of thermodynamics, the enthalpy of system is obtained as:

  H=U+PV

The energy (q) of a system is obtained as:

  ΔU=q+Wq=ΔU+WW=ΔUqSince, workdone in terms of pressure is obtained as dW=PdVdU=dq-PdV

Putting the equations together; (at constant pressure)

  ΔH=ΔU+Δ(PV)ΔH=ΔqPΔV+PΔVΔH=ΔqH=q

Hence, in the given case value of Δ H and q will be same.

The enthalpy change is also obtained as:

  ΔH=n T i T fC p,mdT,  where n= mole, Cp.m = molar specific heat, dT= change in temperature, Ti=Initial temperature, and Tf=Final temperature

Blurred answer
Students have asked these similar questions
(ii) The standard enthalpy of formation of HCI(g) at 298 K is equal to -93.2 kJmol¹. Calculate the value of this quantity at 1000 K. Molar heat capacities in this temperature range are given by the empirical equations: Cp(H₂)/JK¹mol¹ = 27.28 +3.25 x 10³T +0.5 x 10³T ² Cp(Cl₂)/JK ¹mol¹ = 36.90 +0.25 x 10³T -2.84 x 10³T-² Cp(HCI)/JK ¹mol¹ = 26.53 +4.60 x 10³T + 1.09 x 105T-² Where T is the thermodynamic temperature.
One mol of an ideal gas is heated at a constant external pressure of 200 kPa. Calculate the enthalpy involved and change in internal energy during this process upon the temperature change from 100 oC to 25.0 oC. Molar specific heat capacity CV = 3/2 R and the universal gas constant is 8.3145 J‧mol-1·K-1.
A 1.65 mole sample of an ideal gas for which Cv, m = 3/2 R undergoes the following two-step process: (a) From an initial state of the gas described by T = 14.5 oC and P = 2x104 Pa, the gas undergoes isothermal expansion against a constant external pressure of 1.0x104 Pa until the volume has doubled. (b) Then the gas is cooled to constant volume. The temperature drops to -35.6 oC. Calculate q, w, ΔH, ΔU for each step and for the overall process.

Chapter 3 Solutions

Thermodynamics, Statistical Thermodynamics, & Kinetics

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Physical Chemistry
    Chemistry
    ISBN:9781133958437
    Author:Ball, David W. (david Warren), BAER, Tomas
    Publisher:Wadsworth Cengage Learning,
Text book image
Physical Chemistry
Chemistry
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Wadsworth Cengage Learning,
Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY