An equal-tangent crest vertical curve is designed for 45 mi/h. The high point is at elevation 380.10 ft. The initial grade is +1.90% and the final grade is -3.10%. What is the elevation of the PVT? You answer must be in ft and rounded to the second digit (e.g., 0.00), if you need to use values from tables, use "design" values (usually last column), not "calculated"

An equal-tangent crest vertical curve is designed for 45 mi/h. The high point is at elevation 380.10 ft. The initial grade is +1.90% and the final grade is -3.10%. What is the elevation of the PVT? You answer must be in ft and rounded to the second digit (e.g., 0.00), if you need to use values from tables, use "design" values (usually last column), not "calculated"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Please help me answer problem number 2, thank you!
A 618m equal tangent crest vertical curve has PVC at Sta 19+218 and at elevation 177m. The initial grade is 4.05% and the final grade is -6.26%. Determine the elevation (m) of PVI. Round your answer to 3 decimal places.
answer question 22 only
An equal-tangent equal tangent vertical curve connects a +2.10% initial grade and -2.70% final grade. The PVT is at station 127+18 and elevation 206.52 ft. If the design speed is 75 mi/h, what is the elevation of the curve at station 121+58? You answer must be in ft and rounded to the second digit, if you need to use values from tables, use "design" values (usually last column), not "calculated".
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