Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 21, Problem 3P
A population with an allele frequency (p) of 0.5 and a genotype frequency (p2) of 0.25 is at equilibrium. How can you explain the fact that a population with an allele frequency (p) of 0.1 and a genotype frequency (p2) of 0.01 is also at equilibrium?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A sample of 100 individuals from a population that is dimorphic at the A locus has genotype counts as follows.
AA: 30
Aa: 60
aa: 10
a) What are the allele frequencies in the population?
b) What are the expected genotype frequencies, if the population were at HardyWeinberg equilibrium?
c) Is the proportion of heterozygotes lower or higher than expected at Hardy-Weinberg equilibrium? What deviations from the assumptions of the model would best explain the observed difference?
A population with an allele frequency (p) of 0.5 anda genotype frequency (p2) of 0.25 is at equilibrium.How can you explain the fact that a population withan allele frequency (p) of 0.1 and a genotype frequency (p2) of 0.01 is also at equilibrium?
If a population is in Hardy-Weinberg equilibrium for the multiple alleles A+, A and a, whose frequencies are p= 0.60 for A+, q= 0.20 for A, and r = 0.20 for a, what percentage of the population is expected to be heterozygous?
Chapter 21 Solutions
Genetics: From Genes to Genomes
Ch. 21 - Choose the best matching phrase in the right...Ch. 21 - When an allele is dominant, why does it not always...Ch. 21 - A population with an allele frequency p of 0.5 and...Ch. 21 - In a certain population of frogs, 120 are green,...Ch. 21 - Which of the following populations are at...Ch. 21 - A dominant mutation in Drosophila called Delta...Ch. 21 - A large, random mating population is started with...Ch. 21 - Prob. 8PCh. 21 - Alkaptonuria is a recessive autosomal genetic...Ch. 21 - Two hypothetical lizard populations found on...
Ch. 21 - It is the year 1998, and the men and women sailors...Ch. 21 - a. Alleles of genes on the X chromosome can also...Ch. 21 - In 1927, the ophthalmologist George Waaler tested...Ch. 21 - The equation p2 2pq q2> = 1 representing the...Ch. 21 - A gene has two alleles A frequency = p and a...Ch. 21 - Some people can taste the bitter compound...Ch. 21 - Androgenetic alopecia pattern baldness is a...Ch. 21 - The following figure shows the FBI-style analysis...Ch. 21 - Why is the elimination of a fully recessive...Ch. 21 - Tristan da Cunha is a group of small islands in...Ch. 21 - Small population size causes genetic drift because...Ch. 21 - Three basic predictions underlie genetic drift in...Ch. 21 - A mouse mutation with incomplete dominance t =...Ch. 21 - In Drosophila, the vestigial wings recessive...Ch. 21 - In a population of infinite size, three loci A, B,...Ch. 21 - You have identified an autosomal gene that...Ch. 21 - In Europe, the frequency of the CF allele causing...Ch. 21 - An allele of the G6PD gene acts in a recessive...Ch. 21 - Explain why evolutionary biologists monitor...Ch. 21 - Tiny foxes live on the Channel Islands off the...Ch. 21 - What is the most straightforward evidence at the...Ch. 21 - In March 2013, the American Journal of Human...Ch. 21 - If you go back 40 generations into your biological...Ch. 21 - In Fig. 21.17, to what part of the world does...Ch. 21 - Predict the DNA sequences at the four nodes...Ch. 21 - A cladogram not drawn to scale for the taxonomic...Ch. 21 - As noted in Fig. 21.22, humans now living in...Ch. 21 - As of this writing in 2016, no Neanderthal-derived...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The frequency of the A1 allele is p = 0.4, and that of the A2 allele is q = 0.6. The observed genotype frequencies are as follows: f(A1A1) = 0.25 f(A1A2) = 0.36 f(A2A2) = 0.39 Is there a Hardy-Weinberg equilibrium in the population?arrow_forwardThe frequency of the dominant allele “A” in an imaginary population is 0.20 (p) and the frequency of the recessive allele “a” in the population is 0.80 (q). What are the PREDICTED/EXPECTED genotype frequencies of all three genotypes (homozygous dominant, heterozygous, and homozygous recessive) if the population is in Hardy-Weinberg equilibrium?arrow_forwardConsider a population in which the frequency of allele A is p = 0.7 and the frequency of allele a is q = 0.3, and where the alleles are codominant. What will be the allele frequencies after one generation if the following occurs? (a) wAA = 1, wAa = 0.9, waa = 0.8 (b) wAA = 1, wAa = 0.95, waa = 0.9 (c) wAA = 1, wAa = 0.99, waa = 0.98 (d) wAA = 0.8, wAa = 1, waa = 0.8arrow_forward
- A hypothetical population of 10,000 humans has 6848 individuals with the blood type AA, 2846 individuals with blood type AB, and 306 individuals with the blood type BB. What is the frequency of each genotype in this population? What is the frequency of the A allele? What is the frequency of the B allele? If the next generation contained 25,000 individuals, how many individuals would have blood type BB, assuming the population is in Hardy-Weinberg equilibrium?arrow_forwardIn a population of 10,000 individuals, where 3600 are MM, 1600 are Mm, and 4800 are mm, what are the frequencies of the M alleles and the m alleles? M= 0.7; m = 0.3 M= 0.6; m = 0.4 М-0.8; т %3D 0.2 M= 0.9; m = 0.1 M= 0.5; m = 0.5arrow_forwardIn a population of 200 people, an allele F has a frequency of 84%. What is the frequency of allele f? Using the Hardy-Weinberg equation, estimate the numbers of homozygous dominant, heterozygous, and homozygous recessive genotypes. (Remember that the formula is: p2 + 2pq + q2 = 1, where p represents the dominant allele and q represents the recessive allele.) *Be sure to account for all 200 people in the population.arrow_forward
- In a population with two alleles at the R locus (R and r), the frequency of the genotype rr is 0.31. Assuming that the R locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Rr)? Round and report your answer to the second decimal place (0.00).arrow_forwardIn smurfs, blue tails and red tails are codominant to white tails (this is similar to blood type in humans). In a population of 200 smurfs, 6 have white tails, 93 have blue tails, 51 have red tails, and 50 have purple tails. Papa smurf has learned that the frequency of the blue tail allele is 0.53. Is this population in Hardy-Weinberg Equilibrium? Be sure to do a Chi-square test and show your work.arrow_forwardIn a population with two alleles at the C locus (C and c), the frequency of the genotype cc is 0.17. Assuming that the C locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Cc)? Round and report your answer to the second decimal place (0.00).arrow_forward
- Use the equation p2+2pq+q2+1.0 to solve the following problem. In a population of 100 squirrels there are 64 black ones, and the remaining are white. Black (B) is the dominant allele, and the white (b) is the recessive allele. If the population is in Hardy-Weinberg equilibrium, what is the frequency of the black squirrels that are heterozygous (BB) for their coat color. A. 0.48 B. 0.16 C.0.40 D. 0.32 E.0.64arrow_forwardWhat would be the expected number of each genotype (round to the nearest whole number assuming genotype represents an individual) assuming the population was in Hardy Weinberg equilibrium? f(M1M1) = 0.127 f(M1M2) = 0.390 f(M2M2) = 0.300 f(M1M3) = 0.068 f(M2M3) = 0.105 f(M3M3) = 0.009 Referencing a p-value of 0.05 and a CV of 11.070, state if the population is in HWE. Genotype Observed Expected O–E (O–E)2 (O–E)2/E M1M1 M1M2 M2M2 M1M3 M2M3 M3M3 Chi-squared = Statement:arrow_forwardIn a population with two alleles at the C locus (C and c), the frequency of the genotype cc is 0.14. Assuming that the C locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Cc)? Round and report your answer to the second decimal place (0.00). Vour Answor:arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Genetic Variation and Mutation | 9-1 GCSE Science Biology | OCR, AQA, Edexcel; Author: SnapRevise;https://www.youtube.com/watch?v=bLP8udGGfHU;License: Standard YouTube License, CC-BY