Concept explainers
Interpretation:
The complete Lewis structure of
Concept introduction:
Lewis structures illustrates connectivity of a molecule. They account for all the valence electrons, differentiating between bonding pairs and lone pairs of electrons. They indicate which atoms are bonded together and by what types of bonds. Lewis structures are constructed so that the maximum number of atoms have filled valence shells.
An H-bond donor is an H atom which is covalently bonded to a strongly electronegative atom such as N, O, or F, and the H-bond acceptor is the neighboring electronegative ion or molecule which must possess a lone pair of electrons.
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Organic Chemistry: Principles and Mechanisms (Second Edition)
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- Explain why acetic acid, CH3CO2H, Contains two distinct types of Carbon oxygen Bonds, Whereas the acetate ion, formed by loss of hydrogen ion from acetic acid, Only contains one type of carbon oxygen bondarrow_forwardDraw the Lewis structure of acetic acid, CH3CO2H, clearly indicating all non-bonding pairs of electrons. Even though nitrogen and phosphorus have the same number of valence electrons, nitrogen can only bond to chlorine four times forming NCl4+ but phosphorus can bond with chlorine five times forming PCl5. Explain. Draw all the isomers of C4H9Br, using bond-line formulas. Draw the Lewis structure of the nitrite ion, NO2–, clearly indicating resonance contributors as well as non-bonding pairs of electrons and formal charges, as relevant. Nitromethane is a polar molecule but contains 2 equal polar covalent bonds. Briefly explain why and draw a relevant 3-dimensional structure to show the overall dipole moment of the molecule. Draw all isomers of C6H12O that are aldehydes.arrow_forwardDraw the Lewis Structures for C(CH3)3.arrow_forward
- 85. Propane, C3H8, is a hydrocarbon that is commonly used as a fuel. (a) Write a balanced equation for the complete combustion of propane gas. (b) Calculate the volume of air at 25 °C and 1.00 atmosphere that is needed to completely combust 25.0 grams of propane. Assume that air is 21.0 percent O2 by volume. (Hint: We will see how to do this calculation in a later chapter on gases—for now use the information that 1.00 L of air at 25 °C and 1.00 atm contains 0.275 g of O2 per liter.) (c) The heat of combustion of propane is −2,219.2 kJ/mol. Calculate the heat of formation, ΔH∘fΔHf° of propane given that ΔH∘fΔHf° of H2O(l) = −285.8 kJ/mol and ΔH∘fΔHf° of CO2(g) = −393.5 kJ/mol. (d) Assuming that all of the heat released in burning 25.0 grams of propane is transferred to 4.00 kilograms of water, calculate the increase in temperature of the water.arrow_forwardIn an advanced analytical chemistry lab, a team analyzing a compound 'Q' known to be a structural isomer of octane (C8H18). To determine the specific structure of 'Q', a series of spectroscopic analyses are performed. The sequence of the analysis involves: Infrared (IR) spectroscopy, which indicates the absence of functional groups like alcohols, ketones, and carboxylic acids. Nuclear Magnetic Resonance (NMR) spectroscopy, showing signals indicative of only methyl and methylene groups, with no evidence of methine (CH) or quaternary carbon environments. Mass spectrometry (MS), revealing a fragmentation pattern consistent with branched alkane structures. Based on this sequence of analyses, what is the most likely structure of compound 'Q'? Options: A. 2,2,4- Trimethylpentane B. n-Octane C. 2-Methylheptane D. 3-Ethylhexane Don't use chatgpt please provide valuable answerarrow_forwardA student adds bromine solution to a test tube containing an isomer of C3H6. After shaking the sample and exposing it to UV light, the student observes that the colour of the bromine solution changes from orange to clear. Provide a hypothesis for what happened in the test tube. What do you believe to be the structure of the original isomer, and what was the final product, if a reaction occurred?arrow_forward
- The organic product of the reaction 0 O 0. 0- OH × HO OH is:arrow_forwardDraw Lewis structures and condensed structural formulas for the four alcohols with the molecular formula C4H10O. Classify each alcohol as primary, secondary, or tertiary. (Hint: First consider the connectivity of the four carbon atoms; they can be bonded either four in a chain or three in a chain with the fourth carbon as a branch on the middle carbon. Then consider the points at which the iOH group can be bonded to each carbon chain.)arrow_forwardDraw the Lewis structure for the ethylene C2H4 moleculearrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning