Chapter 19, Problem 35P

(a)

To determine

The equivalent capacitance for parallel connections of the capacitors.

Answer to Problem 35P

The equivalent capacitance in parallel connection is $28.2\text{μF}$ .

Explanation of Solution

Given info:

The number of capacitors is, n = 6.

The capacitance of each capacitor is, $C=4.7\text{μF}$ .

Formula Used:

The expression to calculate the equivalent capacitance in parallel connection is,

  $C_p=nC$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}{C}_p=6\left(4.7\text{μF}\right)\\ =28.2\text{μF}\end{array}$

Conclusion:

Therefore, the equivalent capacitance in parallel connection is $28.2\text{μF}$ .

(b)

To determine

The equivalent capacitance for series connections of the capacitors.

Answer to Problem 35P

The equivalent capacitance in series connection is $0.78\text{μF}$ .

Explanation of Solution

Formula Used:

The expression to calculate the equivalent capacitance in series connection is,

  $C_s=\frac{C}{n}$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}{C}_s=\frac{4.7\text{μF}}{6}\\ =0.78\text{μF}\end{array}$

Conclusion:

Therefore, the equivalent capacitance in series connection is $0.78\text{μF}$ .