Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 19, Problem 64GP
To determine

The method to connect the resistance to obtain desired voltage.

Expert Solution & Answer
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Answer to Problem 64GP

The one resistor of resistance 72000Ω should be connected in series connection with human resistance to obtain desired voltage.

Explanation of Solution

Given info:

The potential difference between the two points on human body is, v=0.25V .

The resistance of the human body is, r=2000Ω .

The voltage of the battery is, V=9V .

Formula Used:

The expression to calculate the current in the human body is,

  I=vr

The expression to calculate the resistance that produces the desired voltage is,

  R=VI

Calculation:

Substitute all the values in the above expression.

  I=0.25V2000Ω=1.25×104A

Substitute all the values in the above expression.

  R=9V1.25×104A=72000Ω

The voltage drop in the parallel connection remains constant across each resistance and voltage drop occurs in the series connection of the resistance. The resistance of the value 72000Ω must be connect in the series connection with resistance of the human body to obtain the desired voltage.

Conclusion:

Thus, the one resistor of resistance 72000Ω should be connected in series connection with human resistance to obtain desired voltage.

Chapter 19 Solutions

Physics: Principles with Applications

Ch. 19 - Prob. 11QCh. 19 - Prob. 12QCh. 19 - Prob. 13QCh. 19 - Prob. 14QCh. 19 - Prob. 15QCh. 19 - Prob. 16QCh. 19 - Given the circuit shown in Fig. 19-38, use the...Ch. 19 - Prob. 18QCh. 19 - Prob. 19QCh. 19 - 19. What is the main difference between an analog...Ch. 19 - What would happen if you mistakenly used an...Ch. 19 - Prob. 22QCh. 19 - Prob. 23QCh. 19 - Prob. 24QCh. 19 - Prob. 1PCh. 19 - Prob. 2PCh. 19 - Prob. 3PCh. 19 - Prob. 4PCh. 19 - Prob. 5PCh. 19 - Prob. 6PCh. 19 - Prob. 7PCh. 19 - Prob. 8PCh. 19 - Prob. 9PCh. 19 - Prob. 10PCh. 19 - Prob. 11PCh. 19 - Prob. 12PCh. 19 - Prob. 13PCh. 19 - Prob. 14PCh. 19 - Prob. 15PCh. 19 - Prob. 16PCh. 19 - Prob. 17PCh. 19 - Prob. 18PCh. 19 - Prob. 19PCh. 19 - Prob. 20PCh. 19 - Prob. 21PCh. 19 - Prob. 22PCh. 19 - Prob. 23PCh. 19 - Prob. 24PCh. 19 - Prob. 25PCh. 19 - Prob. 26PCh. 19 - Prob. 27PCh. 19 - Prob. 28PCh. 19 - Prob. 29PCh. 19 - Prob. 30PCh. 19 - Prob. 31PCh. 19 - Prob. 32PCh. 19 - Prob. 33PCh. 19 - Prob. 34PCh. 19 - Prob. 35PCh. 19 - Prob. 36PCh. 19 - Prob. 37PCh. 19 - Prob. 38PCh. 19 - Prob. 39PCh. 19 - Prob. 40PCh. 19 - Prob. 41PCh. 19 - Prob. 42PCh. 19 - Prob. 43PCh. 19 - Prob. 44PCh. 19 - Prob. 45PCh. 19 - Prob. 46PCh. 19 - Prob. 47PCh. 19 - Prob. 48PCh. 19 - Prob. 49PCh. 19 - Prob. 50PCh. 19 - Prob. 51PCh. 19 - Prob. 52PCh. 19 - Prob. 53PCh. 19 - Prob. 54PCh. 19 - Prob. 55PCh. 19 - Prob. 56PCh. 19 - Prob. 57PCh. 19 - Prob. 58PCh. 19 - Prob. 59PCh. 19 - Prob. 60PCh. 19 - Prob. 61PCh. 19 - Prob. 62PCh. 19 - Prob. 63PCh. 19 - Prob. 64GPCh. 19 - Prob. 65GPCh. 19 - Prob. 66GPCh. 19 - Prob. 67GPCh. 19 - Prob. 68GPCh. 19 - Prob. 69GPCh. 19 - Prob. 70GPCh. 19 - Prob. 71GPCh. 19 - Prob. 72GPCh. 19 - Prob. 73GPCh. 19 - Prob. 74GPCh. 19 - Prob. 75GPCh. 19 - Prob. 76GPCh. 19 - Prob. 77GPCh. 19 - Prob. 78GPCh. 19 - Prob. 79GPCh. 19 - Prob. 80GPCh. 19 - Prob. 81GPCh. 19 - Prob. 82GPCh. 19 - Prob. 83GPCh. 19 - Prob. 84GPCh. 19 - Prob. 85GPCh. 19 - Prob. 86GPCh. 19 - Prob. 87GP
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