Concept explainers
(a)
Interpretation:
The atoms of 2-phenylethylamine in the molecule of mescaline needs to be determined.
Concept Introduction:
Organic compounds are the compounds which are mainly composed C and H atoms. The branch of chemistry that deals with preparation, reactions, and properties of organic compounds. The molecular formula of organic compound represents the number of bonded atoms with their atomic symbols.
(b)
Interpretation:
The atoms of 2-phenylethylamine in the molecule of LSD molecule needs to be determined.
Concept Introduction:
Organic compounds are the compounds which are mainly composed C and H atoms. The branch of chemistry that deals with preparation, reactions, and properties of organic compounds. The molecular formula of organic compound represents the number of bonded atoms with their atomic symbols.
Functional groups are the groups of atoms or atoms which are bonded with parent carbon chain in the organic molecule and are responsible for the physical and chemical properties of the compound. In organic chemistry, there are different functional groups such as carboxylic acid, alcohol, ester, or amide.
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General, Organic, and Biological Chemistry - 4th edition
- Here is the chemical structure of methyl propanamide: H H. H H. H-C- C-C -N-C-H H. Decide whether each molecule in the table below is another mnolecule of methyl propanamide, a molecule of an isomer of methyl propanamide, or a molecule of an entirely different compound. molecule relationship to methyl propanamide NH-CH, (Choose one) another molecaule of methyl propanamide a molecule of an isomer of methyl propanamide a molecule of a different compound CH,-CH,-C=0 H H :o: H (Choose one) H-C H- H :0: H H H C-C (Choose one) H. H 回 山回arrow_forwardF. F C. 2. F F draw structurearrow_forwardAnswer choices for first blank: a. ketone b.aldehyde c.amide d. aromatic ring Answer choices for second blank: a. 3700 b. 2200 c. 1725arrow_forward
- Sand (1 cm) 1. A Glass wool or cotton 2. B and D Stopcock to control flow 3. С 4. E Solvent 5. F Alumina: 25 g for every 1 g of mixture to be separated >arrow_forwardProvide an acceptable name for the compound below. ci Clarrow_forward27. The dehydration of ethyl alcohol primarily yields A. Ethylene B. Ethanal C. Ethanoic acid D. Ethane 28. In general, the boiling point of primary alcohol is the boiling point of a linear ether of the same carbon chain length. A. Greater than B. Lower than C. Equal to D. Stronger than 29. Ethyl alcohol and dimethyl ether are isomers. However, they differ in their dipole moment. Which statement is TRUE? A. Dimethyl ether has a lower dipole moment than ethyl alcohol. B. Ethyl alcohol has a lower dipole moment than dimethyl ether. C. Dimethyl ether has a greater bond dipole than ethyl alcohol. D. Ethyl alcohol has a greater bond dipole than dimethyl ether. 30. Based on molecular structure, alcohol molecules and ether molecules are analogues of water. This implies that both molecules can form hydrogen bonds with water molecules. Which statement is FALSE? A. Alcohol molecules are hydrogen bond donors. B. Ether molecules are hydrogen bond acceptors. C. Alcohol molecules are hydrogen bond…arrow_forward
- 1 Give an example (molecular structures) of each functional group. Use arbitrary alkyl groups (e.g., methyl, ethyl, etc.) ex. carbonate a b. C. d. e. f. 9. h. i. halohydrocarbons (for each halogen) alcohols (for primary, secondary, and tertiary) ethers aldehydes ketones carboxylic acids محمد esters amines (for primary, secondary, and tertiary) Draw the molecular structure of 4-chloro-2,5-dimethyl-3-heptanone. Draw the molecular structure of isopropyl acetate.arrow_forwardA. Complete the table below. For each of the given compounds, identify the polarity and the type of IMFA present in each molecule. An example is given as your guide. Polarity (Polar or Nonpolar) Compound Type of IMFA H H. polar H-bonding water :FF: Xe F: xenon tetrafluUoride нон H-C-C-C-H H. acetone Ozone :F: FIF: :F: sulfur hexafluoride H-C N: hydrogen cyanidearrow_forwardIndicate which compound in each of the following pairs has the higher value of the specified property, or if the two compounds in a pair have nearly the same value for the property. Supply the compound name or same. A: I. methyl propanoate or II. pentanal: boiling pointB: I. methyl butanoate or II. hexanal: solubility in waterC: I. methyl propanoate or II. 1-pentanol: boiling pointD: I. methyl pentanoate or II. hexanoic acid: solubility in waterE: I. butanoic acid or II. methyl propanoate: boiling pointarrow_forward
- Give the IUPAC name for each compound. Part 1 of 2 Name: X Part 2 of 2 Name: Give detailed Solution with explanation needed...don't give Handwritten answer...explain also IUPAC Rulesarrow_forwarda. Classify each of the following amines as (1) primary, secondary or tertiary and as (2) aliphatic or aromatic. b. Classify each of the following amines as primary, secondary or tertiary.arrow_forward2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases.arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning