Chapter 16.2, Problem 10SP

Interpretation Introduction

Interpretation: To determine the molarity of the solution.

Concept introduction: Molarity is a term used to express concentration. Molarity is defined as the number of moles of solutes present in one liter of the solution. Molarity is expressed in a unit that is $\frac{mol}{L}$ .

Answer to Problem 10SP

The molarity of the solution is $0.1\text{ M}$ .

Explanation of Solution

Molarity is used to express the concentration of the solution and the formula to find out the concentration is as follows:

  $Molarity=\frac{n}{V}$

Where:

n is the number of moles of solute.

V is the volume of solution (in liters).

The data given to find the molarity of the solution is as follows:

• Volume of solution ( V )is $2.0\text{ L}$ .
• Given the mass of glucose ( W ) is $36.0\text{ g}$ .
• Molar mass of glucose ( M ) is $180\frac{g}{mol}$ .

The formula to find the number of moles is as follows:

  $Moles=\frac{W}{M}$

Substitute the value of the given mass and molar mass of glucose to find out the number of moles as:

  $Moles=\frac{36.0g}{180\frac{g}{mol}}$

  $Moles=0.2$

Substitute the value of moles and volume in the formula of molarity.

  $Molarity=\frac{0.2moles}{2.0L}$

  $Molarity=0.1\text{ M}$

The unit $\frac{mol}{L}$ is denoted by M in molarity.

Conclusion

The molarity of the solution is $0.1\text{ M}$ .