Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 16, Problem 2STP
Interpretation Introduction

Interpretation: The mole fraction of methanol is to be calculated when 2 moles of methanol is dissolved in 45g of water.

Concept introduction: Mole fraction is a term that can be used to express solutions' concentration.

The formula that can be used for the calculation is,

  Xa=nana+nb

Here, na are the moles of solvent, nb are the moles of solute and Xa is mole fraction of solute.

Expert Solution & Answer
Check Mark

Answer to Problem 2STP

The correct option is (A).

Explanation of Solution

The number of moles of solute can be determined by taking the ratio of the given mass and molecular mass.

Hence, the number of moles of methanol is na=2mol .

The number of moles of water is calculated as:

  nb=4518=2.5mol

Substitute 2 for na and 2.5 for nb in the formula of mole fraction to calculate the mole fraction of methanol, Xa .

  Xa=22+2.5mol=0.44

Thus, the correct option is (A).

Chapter 16 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 16.2 - Prob. 11SPCh. 16.2 - Prob. 12SPCh. 16.2 - Prob. 13SPCh. 16.2 - Prob. 14SPCh. 16.2 - Prob. 15SPCh. 16.2 - Prob. 16SPCh. 16.2 - Prob. 17SPCh. 16.2 - Prob. 18SPCh. 16.2 - Prob. 19LCCh. 16.2 - Prob. 20LCCh. 16.2 - Prob. 21LCCh. 16.2 - Prob. 22LCCh. 16.2 - Prob. 23LCCh. 16.2 - Prob. 24LCCh. 16.2 - Prob. 25LCCh. 16.2 - Prob. 26LCCh. 16.2 - Prob. 27LCCh. 16.3 - Prob. 28LCCh. 16.3 - Prob. 29LCCh. 16.3 - Prob. 30LCCh. 16.3 - Prob. 31LCCh. 16.3 - Prob. 32LCCh. 16.3 - Prob. 33LCCh. 16.4 - Prob. 34SPCh. 16.4 - Prob. 35SPCh. 16.4 - Prob. 36SPCh. 16.4 - Prob. 37SPCh. 16.4 - Prob. 38SPCh. 16.4 - Prob. 39SPCh. 16.4 - Prob. 40SPCh. 16.4 - Prob. 41SPCh. 16.4 - Prob. 42LCCh. 16.4 - Prob. 43LCCh. 16.4 - Prob. 44LCCh. 16.4 - Prob. 45LCCh. 16.4 - Prob. 46LCCh. 16.4 - Prob. 47LCCh. 16 - Prob. 48ACh. 16 - Prob. 49ACh. 16 - Prob. 50ACh. 16 - Prob. 51ACh. 16 - Prob. 52ACh. 16 - Prob. 53ACh. 16 - Prob. 54ACh. 16 - Prob. 55ACh. 16 - Prob. 56ACh. 16 - Prob. 57ACh. 16 - Prob. 58ACh. 16 - Prob. 59ACh. 16 - Prob. 60ACh. 16 - Prob. 61ACh. 16 - Prob. 62ACh. 16 - Prob. 63ACh. 16 - Prob. 64ACh. 16 - Prob. 65ACh. 16 - Prob. 66ACh. 16 - Prob. 67ACh. 16 - Prob. 68ACh. 16 - Prob. 69ACh. 16 - Prob. 70ACh. 16 - Prob. 71ACh. 16 - Prob. 72ACh. 16 - Prob. 73ACh. 16 - Prob. 74ACh. 16 - Prob. 75ACh. 16 - Prob. 76ACh. 16 - Prob. 77ACh. 16 - Prob. 78ACh. 16 - Prob. 79ACh. 16 - Prob. 80ACh. 16 - Prob. 81ACh. 16 - Prob. 82ACh. 16 - Prob. 83ACh. 16 - Prob. 84ACh. 16 - Prob. 85ACh. 16 - Prob. 86ACh. 16 - Prob. 87ACh. 16 - Prob. 88ACh. 16 - Prob. 89ACh. 16 - Prob. 90ACh. 16 - Prob. 91ACh. 16 - Prob. 92ACh. 16 - Prob. 93ACh. 16 - Prob. 94ACh. 16 - Prob. 95ACh. 16 - Prob. 96ACh. 16 - Prob. 97ACh. 16 - Prob. 98ACh. 16 - Prob. 99ACh. 16 - Prob. 100ACh. 16 - Prob. 101ACh. 16 - Prob. 103ACh. 16 - Prob. 104ACh. 16 - Prob. 105ACh. 16 - Prob. 106ACh. 16 - Prob. 107ACh. 16 - Prob. 108ACh. 16 - Prob. 109ACh. 16 - Prob. 110ACh. 16 - Prob. 111ACh. 16 - Prob. 112ACh. 16 - Prob. 113ACh. 16 - Prob. 114ACh. 16 - Prob. 115ACh. 16 - Prob. 116ACh. 16 - Prob. 117ACh. 16 - Prob. 118ACh. 16 - Prob. 119ACh. 16 - Prob. 120ACh. 16 - Prob. 121ACh. 16 - Prob. 122ACh. 16 - Prob. 123ACh. 16 - Prob. 124ACh. 16 - Prob. 1STPCh. 16 - Prob. 2STPCh. 16 - Prob. 3STPCh. 16 - Prob. 4STPCh. 16 - Prob. 5STPCh. 16 - Prob. 6STPCh. 16 - Prob. 7STPCh. 16 - Prob. 8STPCh. 16 - Prob. 9STPCh. 16 - Prob. 10STPCh. 16 - Prob. 11STPCh. 16 - Prob. 12STPCh. 16 - Prob. 13STPCh. 16 - Prob. 14STP
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