Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 15, Problem 10TYK
Summary Introduction
Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.
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Fragile X syndrome is an X-linked recessive Achondroplasia is an autosomal dominant trait characterized by a shortened stature. An XX individual is a carrier for Fragile X disorder and is unaffected by achondroplasia. An XY individual is not affected by Fragile X disorder and has achondroplasia.
a. What is the XX individual’s genotype
b. What is the XY individual’s genotype?
c. If the two individuals where to have children, what are the possible genotypes and phenotypes of their children? Use a Punnett square.
d. What is the probability of them having a child with Fragile X and achondroplasia?
In humans, hemophilia is an X-linked recessive
condition characterized by the inability of blood to
clot normally. A woman who is a carrier for
hemophilia marries a man who has hemophilia.
What are the genotypes of the woman and man,
respectively?
a. xH+xH+, xH+y
b. xH+xH xH+y
c. xH+xH xHy
Od. XHXH, XH+y
O e. xHxH xHy
Calico is a coat color found in cats, which is caused by a X-linked, co-dominant alleleFemale cats: XBXB= black; XOXO = orange; and XBXO = calico
Male cats: XBY = black; orange XOY = orange
What is the outcome of a black male crossed with an orange female?
A. All offspring are black
B. All female cats are calico, male cats are orange
C. All female cats are calico, male cats are orange
D. 1/4 female calico, 1/4 female black, 1/4 male black, 1/4 male orange
Chapter 15 Solutions
Study Guide for Campbell Biology
Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQCh. 15 - Prob. 8IQCh. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...
Ch. 15 - Prob. 3SYKCh. 15 - Prob. 4SYKCh. 15 - Thomas Hunt Morgan firmly established the location...Ch. 15 - Prob. 2TYKCh. 15 - Sex-linked traits a. are coded for by genes...Ch. 15 - Prob. 4TYKCh. 15 - Prob. 5TYKCh. 15 - Prob. 6TYKCh. 15 - Prob. 7TYKCh. 15 - Prob. 8TYKCh. 15 - Prob. 9TYKCh. 15 - Prob. 10TYKCh. 15 - Consider three genes on the X chromosome: A, B,...Ch. 15 - Prob. 12TYKCh. 15 - Genomic imprinting a. explains cases in which the...Ch. 15 - Prob. 14TYKCh. 15 - Prob. 15TYKCh. 15 - Suppose that alleles for an X-linked character for...Ch. 15 - Some girls who fail to undergo puberty are found...Ch. 15 - Prob. 18TYKCh. 15 - The genetic event that results in Turner syndrome...Ch. 15 - Prob. 20TYKCh. 15 - Prob. 1GPCh. 15 - Prob. 2GPCh. 15 - Prob. 3GPCh. 15 - Prob. 4GPCh. 15 - Prob. 5GPCh. 15 - Red-green color blindness is caused by a...
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- Choose the statement that is incorrect.a. A son can inherit a recessive allele on anX chromosome from either parent.b. An individual may inherit three or more of eachtype of chromosome characteristic of the species, acondition called polyploidy.c. A female child inherits one X chromosome from hermother and one from her father.d. Pedigree analysis can be used to determine a futurechild’s chance of being born with achondroplasiaarrow_forwardIn humans, the genes for coloblindedness and hemophilia re both located on the X chromosome with no corresponding gene in the Y. These are both recessive alleles. a. If a man and a woman, both with normal vision, marry and have a colorblind son, draw the Punnet square that illustrates this. b. If the man dies and the woman remarries to a colorblind man, draw a Punnet Square showing the type of children could be expected from hre second marriage. How many/what percentages of each could ne expectedarrow_forwardA type of baldness is sex –limited such that the allele that causes it is dominant in men and recessive in women. Thus baldness is much more common in men than women even though the locus is on an autosome. How is the pattern of inheritance in this example different from X-linked inheritance of a recessive allele? Group of answer choices A. the trait can be passed from fathers to sons B. the trait can be passed from fathers to daughters C. the trait can be passed from mothers to sons D. the trait can be passed from mothers to daughtersarrow_forward
- Which of the following is an explanation for independent assortment of alleles on different chromosomes (Mendel's second law)? A. Chromosomes can have different functions in various types of cells of the same organism. B. In metaphase I, alignment of 1 pair of replicated chromosomes does not affect the alignment of another pair. C. Each chromosome is capable of a different function. D. In prophase I, which chromosomes pairs with which other one is completely random. E. Chromosomes are divided into daughter cells in a random fashion.arrow_forwardWhen one examines the pattern of inheritance of a trait and finds that it is transmitted from fathers to sons to grandsons (never appearing in the females genotype) what is the conclusion about the inheritance pattern? a. Sex linked b. Sex limited С. Sex related d. X linked e. Sex influenced Red-Green color blindness a. Has its genetic determination on the x chromosome b. Affects more males than females С. Is influenced by somatic sex differentiation d. A and b e. All of thesearrow_forwardRabbits may be classified as agouti, chinchilla, Himalayan, or albino according to coat color. A cross between CC h x C ch c produced 5 agouti, 3 chinchilla and 2 Himalayans. a. What are the phenotypes of the parent rabbits? Copy the genotypes then write the corresponding phenotype beside each. b. What are the genotypes of the F1s? c. What mode of inheritance is exhibited? d. If the two F1 agouti genotypes will be crossed, what percentage of theiroffspring will have the same phenotype? e. What will be the genotypes of the rabbits in (d)?arrow_forward
- ch of the following best describes why males cannot be carriers of sex-linked traits? A. Males cannot be carriers because their Y chromosome makes them immune to sex-linked traits B. This is incorrect, males can be carriers of sex-linked traits O C. Males cannot be carriers because they only inherit one X chromosome, either having the trait or not O D. Males cannot be carriers because their mothers pass on an X chromosome without the sex-linked traitarrow_forwardFragile X is a disorder which causes mental impairment in affected individuals. The trait which is due to a mutation in the FMR1 gene on the X chromosome is inherited in a recessive manner. An unaffected son was born to an affected man and an unaffected woman. The woman’s mother was affected while the father was normal. a. Indicate the gene notation. b. Give the genotype of the son. c. Is it possible for the couple to have an affected daughter? affected son? Derive the genotypic and phenotypic ratios for the offspring. Show and label your solutions properly. d. If the couple has four children, what is the probability that they will have three normal daughters and one normal son?arrow_forwardColor blindness in men is controlled by a recessive gene located on the X chromosome. Can a brother and sister with color blindness have another normal brother? A. Yes, if the mother is a carrier. B.Yes, if the mother is homozygous. C.Yes, if the father is heterogametic. D.Yes, if the father is a carrier.arrow_forward
- Under what conditions does one expect a 9:3:3:1 ratio? What may cause this ratio to vary? A. dihybrid cross with independent assortment; epistasis B trihybrid cross with linked chromosomes; Down syndrome C dihybrid cross with linked chromosomes; the 9:3:3:1 ratio will remain unchanged regardless of other conditions D. dihybrid cross with independent assortment; Turner syndrome E. monohybrid cross with independent assortment; epistasisarrow_forwardIn labrador retrievers an allele B codes for black pigment and b codes for brown. A second gene E is responsible for deposition of pigment into the hair follicle. The e allele results in the blockage of pigment deposition. a. What fraction of yellow puppies would you predict to be born in a cross between a yellow labrador Bbee and a Black labrador BbEe? b. What color is a labrador with the genotype bbEe?arrow_forwardTay–Sachs disease is caused by recessive alleles on anautosome. In which case(s) could two parents with anormal phenotype have a child with Tay–Sachs?a. Both parents are homozygous for a Tay–Sachs allele.b. Both parents are heterozygous for a Tay–Sachsallele.c. One parent is homozygous for a Tay–Sachs allele,and the other is heterozygous.arrow_forward
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