Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 15, Problem 20TYK
Summary Introduction
Introduction: According to
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In the snail Limnaea peregra, coiling of the shell is determined by the genes D for right-handed coiled shells, and d for left-handed coiled shells. The gene for the right-handed shell is dominant. However, the direction of coiling in any single individual is determined by the genotype of the maternal parent producing the egg, regardless of the progeny's genotype. Which describes this type of inheritance?
A. infectious heredity
B. maternal effect
C. dominant X-linked
D. organelle heredity
For the following traits, what information must you have in order to predict the phenotype of an offspring? A. Snail coiling direction B. Dwarfism due to a mutant Igf2 allele C. Leber hereditary optic neuropathy
A mother has a high heteroplasmic load in her germ cells (cells that will produce her eggs). Which of the following statements is correct?
A. ALL of her offspring are guaranteed to inherit the disease associated with this heteroplasmic load.
B. She can only pass the mitochondrial mutation to her daughters.
C. ALL of her eggs that can potentially be fertilized will have a high heteroplasmic load.
D. Cell division could lead to uneven distribution of mitochondria.
Chapter 15 Solutions
Study Guide for Campbell Biology
Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQCh. 15 - Prob. 8IQCh. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...
Ch. 15 - Prob. 3SYKCh. 15 - Prob. 4SYKCh. 15 - Thomas Hunt Morgan firmly established the location...Ch. 15 - Prob. 2TYKCh. 15 - Sex-linked traits a. are coded for by genes...Ch. 15 - Prob. 4TYKCh. 15 - Prob. 5TYKCh. 15 - Prob. 6TYKCh. 15 - Prob. 7TYKCh. 15 - Prob. 8TYKCh. 15 - Prob. 9TYKCh. 15 - Prob. 10TYKCh. 15 - Consider three genes on the X chromosome: A, B,...Ch. 15 - Prob. 12TYKCh. 15 - Genomic imprinting a. explains cases in which the...Ch. 15 - Prob. 14TYKCh. 15 - Prob. 15TYKCh. 15 - Suppose that alleles for an X-linked character for...Ch. 15 - Some girls who fail to undergo puberty are found...Ch. 15 - Prob. 18TYKCh. 15 - The genetic event that results in Turner syndrome...Ch. 15 - Prob. 20TYKCh. 15 - Prob. 1GPCh. 15 - Prob. 2GPCh. 15 - Prob. 3GPCh. 15 - Prob. 4GPCh. 15 - Prob. 5GPCh. 15 - Red-green color blindness is caused by a...
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- Which of the below explains why trisomy is better tolerated in humans than monosomy? (Select all correct options). a. Loss of heterozygosity in monosomy b. Increased gene expression in trisomic cells is beneficial c. Reduced gene expression in monosomy d.The extra chromosome in trisomic cells is degraded Which two are both necessary to hold a tetrad together until Anaphase I? a) nondisjunction b) cross over c) centromere cohesion d) synaptonemal complex e) separese activityarrow_forwardWhich of the following inheritance patterns was observed, for the T2 bacteriophages of Escherichia coli, in the experiments performed by Alfred Hershey and Martha Chase? A. neither 35S-labeled proteins nor 32P-labeled DNA molecules were passed on to viral progeny B. 35S-labeled DNA molecules were passed on to viral progeny, but not 32P-labeled proteins C. both 32P-labeled DNA molecules and 35S-labeled proteins were passed on to viral progeny D. 32P-labeled DNA molecules were passed on to viral progeny, but not 35S-labeled proteins E. both 35S-labeled DNA molecules and 32P-labeled proteins were passed on to viral progenyarrow_forwardFruit flies are very useful model organisms that have been used to study genetics. One mutant recessive trait in fruit flies is called "eyeless" because it causes flies to have no eyes. Cross an eyeless fly with a homozygous normal fly. a. Draw the Punnett square. b. What is the genotyoe ratio of the offspring? c. What is the phenotype ratio of the offspring? d. What genetic problem is this? (monohybrid, dihybrid or multiple allele)arrow_forward
- Holstein cattle suffer from the condition citrullinemia, in which homozygous recessive calves die within a week of birth because they cannot break down ammonia that is produced when amino acids are metabolized. If a cow that is heterozygous for the citrullinemia gene is inseminated by a bull that is homozygous dominant, what is the probability that a calf inherits citrullinemia?arrow_forwardTay–Sachs disease is caused by recessive alleles on anautosome. In which case(s) could two parents with anormal phenotype have a child with Tay–Sachs?a. Both parents are homozygous for a Tay–Sachs allele.b. Both parents are heterozygous for a Tay–Sachsallele.c. One parent is homozygous for a Tay–Sachs allele,and the other is heterozygous.arrow_forwardAlbinism is caused by an autosomal recessive allele that interferes with skin pigmentation in mammals. Two normally pigmented human parents already have an albino boy. They plan to continue to have children until they get a girl. Some or all of this information is important for each of the questions below. a) What is the probability that their next child (currently unborn) will be a girl with albinism? Explain your reasoning. b) What is the probability their first female child will be albino? Explain your reasoning. c) The answer to part (b) is different (and, yes, the answer is different) from the answer to part (a). Explain why. (Hint: it has something to do with the underlined words.)arrow_forward
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