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Three inverting amplifiers, each with
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Microelectronics: Circuit Analysis and Design
- In the circuit in the figure Vcc= 25 V, Vi= 40 mV, RB = 470 kg. RC = 3.3 kg, RE1 = 470 G, RE2 = 1.2 kg RL = 32.5 k(2 and B = 110 because you find the value of the output voltage (Vo) according to. Note-1: capacitors are worth neglecting at mid-band frequency. Note-2: the output impedance (ro) of the transistor will be ignored. RB Q1 NPN RCarrow_forwardDetermine the Miller input and output capacitances for the amplifier in figure below VGSQ = -1.9 V IDQ = 2.8 mA Cw₁ = 4 pF Cwo = 8 pF Cgd = 9 pF Cgs = 14 pF Cds = 4 pF 1.5 k$2 0.05 μF Ht C 3.3 ΜΩ +10 V D + S 680 Ω 2.4 ΚΩ HH 0.05 µF pss = 10 mA Vp = -4 V + 100 µF 4.8 ΚΩarrow_forward1. Build a circuit that allows variable aplification from 1 to 10 time, you can use inverting configurations but the net phase change must be zero. include procedure and values for resistors and input voltage. please use AD620 for amplifiersarrow_forwardI designed a summing amplifier that could amplify a 1mV sinusoid (Vina) into a sinusoid with 1V amplitude and 3.5V offset. The value for R1a is 1k ohms, for R1b is 1mega ohms, R2 is 1 mega ohms, and Vin b is -3.5V. What is the input offset voltage?arrow_forward3) With reference to the switching conditions given below develop an appropriate circuitry that can develop output waveforms as given below, Mark in the circuitry the different components as well Periodic Time (T) A +VL 90° 180° 360 450° 540° time 270° -VL VAB VAC VBc VBA VCA VCB VAB VẠC VBc VBA VDC Vpc 30° 90° 150° 210° 270° 330° 390° 450° 510° 570° time 60° Output Voltage Waveformarrow_forward92 ۱ ۹:۱ ص Qs= 1107 and Qp= 1041 Qs= 1207 and Qp= 1241 Qs= 1007 and Qp= 1041 Qs= 1107 and Qp= 1141 In the figure shown below we can find output current is equal to.. . if the input voltage is equal to 12 mv 12 kO 12 ka 6 ka No option is correct 10 = 32 uA 10 = 34 uA 10 = 38 uA 10 = 36 uA In the fig. shown below we can find the higher critical frequency due to the inputarrow_forwardDetermine the transfer function (VOUT / VIN) for the circuit in figure # 1,composed of a voltage source ranging from -80v to + 80v, this function ofTransfer must define the output voltage for all input voltage values. R1 = 7R2 = 1R3 = 3arrow_forwardThe signal source in Figure B3 is v5-5sinot mV. The transistor's current gain B-120 and the Early voltage VA=∞. Neglect the impacts of capacitors. Assume VBE(on) = 0.7 V, V₁ = 0.026 V. V+ = +5 V Rς = 2.5 ΚΩ www www Rc V=-5 V 2. Find small signal parameters 9m and T RE Figure B3 3. Draw the small-signal equivalent circuit. Cc HH 4. Determine the small-signal voltage gain A- AHI لسل 1. Design the circuit's RE and Re such that Icq = 0.25 mA and VCEQ = 3 V Ov R₁ = 5 KQ2arrow_forwardThe input signal Vin shown in the figure is a 1 KHz square wave voltage that alternates between +7V and -7V with a 50% duty cycle. Both transistors have the same current gain, which is large. The circuit delivers power to the load resistor RL. What is the efficiently of this circuit for the given input? Choose the closest answer. -10V Vino O -10V MM | R₁ = 1052arrow_forwarda) Calculate the overall voltage gain vo/vi . b) Find the voltage gain that would be needed in a fourth stage which would make the overall gain to be 65 dB when added. -20 -12.5 +0.8arrow_forwardDetermine VCE for Prob#6. QUESTION 9 Plot the quiescent point for Prob#6.arrow_forwardDesign a difference amplifier shown in the following figure to meet the following criteria: vo = 2vb - 5va. The resistance seen by the signal source vb is 750 kΩ, and the resistance seen by the signal source va is 16 kΩ when the output voltage vo is zero. (Figure 1) Specify the value of Ra Specify the value of Rb Specift the value of Rc Specify the value of Rdarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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