EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
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Chapter 13, Problem 77CP
Interpretation Introduction
Interpretation: The mechanism for the given reaction needs to be proposed.
Concept Introduction: When in any chemical situation there are two possible reactions, the product formation depends on the mechanism leading to a stable product. The formation of an intermediate also plays an important role in any reaction. In the given case, electrophilic bromine attacks the given reactant to form a bromonium ion. The formation of an
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In an aqueous solution containing sodium bicarbonate, aniline reacts quickly withbromine to give 2,4,6-tribromoaniline. Nitration of aniline requires very strong conditions,however, and the yields (mostly m-nitroaniline) are poor.(a) What conditions are used for nitration, and what form of aniline is present under theseconditions?
gas, Cl¬CH2CH2¬S¬CH2CH2¬Cl, was used as a poisonous chemical agentin World War I. Mustard gas is much more toxic than a typical primary alkyl chloride. Itstoxicity stems from its ability to alkylate amino groups on important metabolic enzymes,rendering the enzymes inactive.(a) Propose a mechanism to explain why mustard gas is an exceptionally potent alkylatingagent.(b) Bleach (sodium hypochlorite, NaOCl, a strong oxidizing agent) neutralizes and inactivates mustard gas. Bleach is also effective on organic stains because it oxidizes coloredcompounds to colorless compounds. Propose products that might be formed by thereaction of mustard gas with bleach.
Propose mechanisms consistent with the
following reactions. (a) (b) (c) (d) (f) (breif
Written explantion for each PLEASE)
Propose mechanisms consistent with the following reactions.
(a)
HBr
ROOR
Br
H₂SO4
(b)
H₂O
OH
Br
HBr
Br
(d)
(c)
CHBr
Br
NaOH
Br
Br
(e)
HCI
CH3CH₂OH
Br
OCH2CH3
Br
ED-8
CH2CH3
H-
OH
H+, H₂O
(f)
H
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CH3CH2
CH2CH3
CH2CH3
(continued)
Chapter 13 Solutions
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
Ch. 13.2 - Prob. 1LTSCh. 13.2 - Prob. 1PTSCh. 13.2 - Prob. 2PTSCh. 13.2 - Prob. 3ATSCh. 13.4 - Prob. 4CCCh. 13.5 - Prob. 2LTSCh. 13.5 - Prob. 5PTSCh. 13.5 - Prob. 6ATSCh. 13.5 - Prob. 7CCCh. 13.5 - Prob. 8CC
Ch. 13.5 - Prob. 9CCCh. 13.6 - Prob. 10CCCh. 13.7 - Prob. 11CCCh. 13.7 - Prob. 12CCCh. 13.8 - Prob. 3LTSCh. 13.8 - Prob. 13PTSCh. 13.8 - Prob. 14ATSCh. 13.9 - Prob. 15CCCh. 13.10 - Prob. 4LTSCh. 13.10 - Prob. 17ATSCh. 13.10 - Prob. 5LTSCh. 13.10 - Prob. 19ATSCh. 13.11 - Prob. 20CCCh. 13.12 - Prob. 6LTSCh. 13.12 - Prob. 7LTSCh. 13 - Prob. 26PPCh. 13 - Prob. 27PPCh. 13 - Prob. 28PPCh. 13 - Prob. 29PPCh. 13 - Prob. 30PPCh. 13 - Prob. 31PPCh. 13 - Prob. 32PPCh. 13 - Prob. 33PPCh. 13 - Prob. 34PPCh. 13 - Prob. 35PPCh. 13 - Prob. 36PPCh. 13 - Prob. 37PPCh. 13 - Prob. 38PPCh. 13 - Prob. 39PPCh. 13 - Prob. 40PPCh. 13 - Prob. 41PPCh. 13 - Prob. 42PPCh. 13 - Prob. 43PPCh. 13 - Prob. 44PPCh. 13 - Prob. 45PPCh. 13 - Prob. 46ASPCh. 13 - Prob. 47ASPCh. 13 - Prob. 48ASPCh. 13 - Prob. 49ASPCh. 13 - Prob. 50ASPCh. 13 - Prob. 51ASPCh. 13 - Prob. 52ASPCh. 13 - Prob. 53ASPCh. 13 - Prob. 54IPCh. 13 - Prob. 59IPCh. 13 - Prob. 60IPCh. 13 - Prob. 61IPCh. 13 - Prob. 62IPCh. 13 - Prob. 63IPCh. 13 - Prob. 64IPCh. 13 - Prob. 65IPCh. 13 - Prob. 66IPCh. 13 - Prob. 69IPCh. 13 - Prob. 70IPCh. 13 - Prob. 71IPCh. 13 - Prob. 72IPCh. 13 - Prob. 73IPCh. 13 - Prob. 74IPCh. 13 - Prob. 77CPCh. 13 - Prob. 79CPCh. 13 - Prob. 80CP
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