World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Question
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Chapter 13, Problem 65A

(a)

Interpretation Introduction

Interpretation:

For the given diagram of helium and neon gases, which gas has greater initial pressure and how much pressure it has, is to be identified.

Concept Introduction :

  • The ideal gases are those gases which obey the ideal gas equation and the ideal gas equation is written as
  •   PV= nRT

Where, P = pressure of the gas

V = Volume of the gas

R = Gas constant

T = temperature of the gas

  • Boyle’s Law gives the inverse relation of volume with pressure at constant temperature and number of moles, such that
  •   PfinalVfinal=PinitialVinitial

(a)

Expert Solution
Check Mark

Answer to Problem 65A

The initial pressure of helium gas is 1.5 times greater than the initial pressure of neon gas.

Explanation of Solution

Given information:

The number of molecules of helium gas = 6

The number of molecules of neon gas = 4

Calculation:

The relation between pressure and number of moles of gases at the same temperature and volume is

  PHenHe=PNenNePHePNe=nHenNePHePNe=64PHePNe=32PHe=1.5PPNe

So, the initial pressure of helium gas is greater than the initial pressure of neon gas.

(b)

Interpretation Introduction

For the diagram of helium and neon gases, the diagram will looks after opened the stopcock

By neglecting the volume of the connecting tube is to be drawn.

Interpretation:

Concept Introduction :

The ideal gases are those gases which obey the ideal gas equation and the ideal gas equation is written as

  PV= nRT

Where, P = pressure of the gas

V = Volume of the gas

R = Gas constant

T = temperature of the gas

  • The inverse relation of volume with pressure at constant temperature and number of moles, such that
  •   PfinalVfinal=PinitialVinitial

(b)

Expert Solution
Check Mark

Answer to Problem 65A

The diagram after opened the stopcock is

  World of Chemistry, 3rd edition, Chapter 13, Problem 65A

Explanation of Solution

When the valve is opened, due to the pressure differences some moles of neon gas are moving from the right side bulb to the left side bulb.

(c)

Interpretation Introduction

Interpretation:

For the given diagram of helium and neon gases, the final pressure in terms of the original pressure of helium and neon gases is to be determined.

Concept Introduction :

  • The ideal gases are those gases which obey the ideal gas equation and the ideal gas equation is written as
  •   PV= nRT

Where, P = pressure of the gas

V = Volume of the gas

R = Gas constant

T = temperature of the gas

  • Boyle’s Law gives the inverse relation of volume with pressure at constant temperature and number of moles, such that
  •   PfinalVfinal=PinitialVinitial

(c)

Expert Solution
Check Mark

Answer to Problem 65A

The final pressure in terms of the original pressures of helium and neon at constant temperature is Ptotal=(PHe+PNe)2 .

Explanation of Solution

Given information:

The number of molecules of helium gas = 6

The number of molecules of neon gas = 4

The volume of each bulb = x

Calculation:

Total volume = x+x=2x

  PtotalVtotal=P1V1+P2V2=PHeX+PNeXPtotal(X+X)=X(PHe+PNe)Ptotal(2X)=X(PHe+PNe)Ptotal=(PHe+PNe)2

The final pressure in terms of original pressure of neon gas

  Ptotal=(PHe+PNe)2but,PHe=1.5PNePtotal=(1.5PNe+PNe)2=2.5PNe2Ptotal=1.25PNe

The final pressure in terms of original pressure of helium gas is

  Ptotal=(PHe+PNe)2but,PHe=1.5PNeÞPNe=PHe1.5=0.66PHePtotal=(PHe+PNe)2Ptotal=(PHe+0.66PHe)2=1.66PHe2Ptotal=0.86PHe

(d)

Interpretation Introduction

Interpretation:

For the given diagram of helium and neon gases, the final partial pressure of each gas in terms of the final pressure of the system is to be determined.

Concept Introduction :

  • The ideal gases are those gases which obey the ideal gas equation and the ideal gas equation is written as
  •   PV= nRT

Where, P = pressure of the gas

V = Volume of the gas

R = Gas constant

T = temperature of the gas

  • Boyle’s Law gives the inverse relation of volume with pressure at constant temperature and number of moles, such that
  •   PfinalVfinal=PinitialVinitial

(d)

Expert Solution
Check Mark

Answer to Problem 65A

The initial pressure of helium gas is 1.5 times greater than the initial pressure of neon gas.

Explanation of Solution

Given information:

The Initial number of molecules of helium gas = 6

The Initial number of molecules of neon gas = 4

Calculation:

The final partial pressure of helium gas in terms of final pressure

  Ptotal=(PHe+PNe)2but,PHe=1.5PNeÞPNe=PHe1.5=0.66PHePtotal=(PHe+PNe)2Ptotal=(PHe+0.66PHe)2=1.66PHe2Ptotal=0.86PHeByrearrangingtheaboveequation,PHe=56Ptotal

The final partial pressure of neon gas in terms of final pressure of the system

  Ptotal=(PHe+PNe)2but,PHe=1.5PNe   Ptotal=(1.5PNe+PNe)2=2.5PNe2Ptotal=1.25PNeByreaarangingthisarrangmentPNe=45Ptotal

Chapter 13 Solutions

World of Chemistry, 3rd edition

Ch. 13.2 - Prob. 4RQCh. 13.2 - Prob. 5RQCh. 13.2 - Prob. 6RQCh. 13.2 - Prob. 7RQCh. 13.2 - Prob. 8RQCh. 13.3 - Prob. 1RQCh. 13.3 - Prob. 2RQCh. 13.3 - Prob. 3RQCh. 13.3 - Prob. 4RQCh. 13.3 - Prob. 5RQCh. 13 - Prob. 1ACh. 13 - Prob. 2ACh. 13 - Prob. 3ACh. 13 - Prob. 4ACh. 13 - Prob. 5ACh. 13 - Prob. 6ACh. 13 - Prob. 7ACh. 13 - Prob. 8ACh. 13 - Prob. 9ACh. 13 - Prob. 10ACh. 13 - Prob. 11ACh. 13 - Prob. 12ACh. 13 - Prob. 13ACh. 13 - Prob. 14ACh. 13 - Prob. 15ACh. 13 - Prob. 16ACh. 13 - Prob. 17ACh. 13 - Prob. 18ACh. 13 - Prob. 19ACh. 13 - Prob. 20ACh. 13 - Prob. 21ACh. 13 - Prob. 22ACh. 13 - Prob. 23ACh. 13 - Prob. 24ACh. 13 - Prob. 25ACh. 13 - Prob. 26ACh. 13 - Prob. 27ACh. 13 - Prob. 28ACh. 13 - Prob. 29ACh. 13 - Prob. 30ACh. 13 - Prob. 31ACh. 13 - Prob. 32ACh. 13 - Prob. 33ACh. 13 - Prob. 34ACh. 13 - Prob. 35ACh. 13 - Prob. 36ACh. 13 - Prob. 37ACh. 13 - Prob. 38ACh. 13 - Prob. 39ACh. 13 - Prob. 40ACh. 13 - Prob. 41ACh. 13 - Prob. 42ACh. 13 - Prob. 43ACh. 13 - Prob. 44ACh. 13 - Prob. 45ACh. 13 - Prob. 46ACh. 13 - Prob. 47ACh. 13 - Prob. 48ACh. 13 - Prob. 49ACh. 13 - Prob. 50ACh. 13 - Prob. 51ACh. 13 - Prob. 52ACh. 13 - Prob. 53ACh. 13 - Prob. 54ACh. 13 - Prob. 55ACh. 13 - Prob. 56ACh. 13 - Prob. 57ACh. 13 - Prob. 58ACh. 13 - Prob. 59ACh. 13 - Prob. 60ACh. 13 - Prob. 61ACh. 13 - Prob. 62ACh. 13 - Prob. 63ACh. 13 - Prob. 64ACh. 13 - Prob. 65ACh. 13 - Prob. 66ACh. 13 - Prob. 67ACh. 13 - Prob. 68ACh. 13 - Prob. 69ACh. 13 - Prob. 70ACh. 13 - Prob. 71ACh. 13 - Prob. 72ACh. 13 - Prob. 73ACh. 13 - Prob. 74ACh. 13 - Prob. 75ACh. 13 - Prob. 76ACh. 13 - Prob. 1STPCh. 13 - Prob. 2STPCh. 13 - Prob. 3STPCh. 13 - Prob. 4STPCh. 13 - Prob. 5STPCh. 13 - Prob. 6STPCh. 13 - Prob. 7STPCh. 13 - Prob. 8STPCh. 13 - Prob. 9STPCh. 13 - Prob. 10STP
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