World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 13, Problem 40A
Interpretation Introduction

Interpretation: -Volume of Oxygen gas is calculated using given variables.

Concept Introduction: - For calculating volume of Oxygen, the formula for ideal gas equation is applied.

It is represented as follows:

  PV=nRT

Or,

  n=PVRT

Where

  V is volume of the gas

  n is the number of moles of the gas

  P is pressure of the gas

  T is temperature of the gas

  R is gas constant

Expert Solution & Answer
Check Mark

Answer to Problem 40A

Volume of oxygen at 25°C is 14.7L .

Explanation of Solution

There is a relation between volume of a gas and number of molecules of gas present in it, this relation is expressed by Avogadro’s law

According to Avogadro’s law 1 mole of every substance occupies 22.4L at STP weigh’s equal to the molecular mass and contains Avogadro’s number 6.023×1023 of particles.

  no. of moles = given massmolar mass=5.53 g44.1g/mol=0.125moles

The combustion reaction is represented as follows:

  C3H8+5O23CO2+4H2O

According to stoichiometry, 1 mole of propane requires 5 moles of Oxygen.

So, 0.125 moles will require number of oxygen atoms as follows:

  nO2= 0.125×5 = 0.625 moles

According to the Ideal gas equation

  PV=nRT

P = pressure of the gas = 1.04atm

V = volume of the gas =?

T = Temperature of the gas

The Temperature in Kelvin will be:

  T=250C+273=298 K

R = gas constant = 0.0821 atm Lk mol

n = moles of gas = 0.625 mol

Thus, volume for 0.125 moles of propane will be:

  T=24+273 K=297K

R is 0.0821 L atm/K mol

Putting the values,

  V=nRTP=0.625×0.0821×2981.04V=15.29111.04=14.7L

Volume of oxygen at 25°C is 14.7L .

Conclusion

Volume of oxygen at 25°C is 14.7L .

Chapter 13 Solutions

World of Chemistry, 3rd edition

Ch. 13.2 - Prob. 4RQCh. 13.2 - Prob. 5RQCh. 13.2 - Prob. 6RQCh. 13.2 - Prob. 7RQCh. 13.2 - Prob. 8RQCh. 13.3 - Prob. 1RQCh. 13.3 - Prob. 2RQCh. 13.3 - Prob. 3RQCh. 13.3 - Prob. 4RQCh. 13.3 - Prob. 5RQCh. 13 - Prob. 1ACh. 13 - Prob. 2ACh. 13 - Prob. 3ACh. 13 - Prob. 4ACh. 13 - Prob. 5ACh. 13 - Prob. 6ACh. 13 - Prob. 7ACh. 13 - Prob. 8ACh. 13 - Prob. 9ACh. 13 - Prob. 10ACh. 13 - Prob. 11ACh. 13 - Prob. 12ACh. 13 - Prob. 13ACh. 13 - Prob. 14ACh. 13 - Prob. 15ACh. 13 - Prob. 16ACh. 13 - Prob. 17ACh. 13 - Prob. 18ACh. 13 - Prob. 19ACh. 13 - Prob. 20ACh. 13 - Prob. 21ACh. 13 - Prob. 22ACh. 13 - Prob. 23ACh. 13 - Prob. 24ACh. 13 - Prob. 25ACh. 13 - Prob. 26ACh. 13 - Prob. 27ACh. 13 - Prob. 28ACh. 13 - Prob. 29ACh. 13 - Prob. 30ACh. 13 - Prob. 31ACh. 13 - Prob. 32ACh. 13 - Prob. 33ACh. 13 - Prob. 34ACh. 13 - Prob. 35ACh. 13 - Prob. 36ACh. 13 - Prob. 37ACh. 13 - Prob. 38ACh. 13 - Prob. 39ACh. 13 - Prob. 40ACh. 13 - Prob. 41ACh. 13 - Prob. 42ACh. 13 - Prob. 43ACh. 13 - Prob. 44ACh. 13 - Prob. 45ACh. 13 - Prob. 46ACh. 13 - Prob. 47ACh. 13 - Prob. 48ACh. 13 - Prob. 49ACh. 13 - Prob. 50ACh. 13 - Prob. 51ACh. 13 - Prob. 52ACh. 13 - Prob. 53ACh. 13 - Prob. 54ACh. 13 - Prob. 55ACh. 13 - Prob. 56ACh. 13 - Prob. 57ACh. 13 - Prob. 58ACh. 13 - Prob. 59ACh. 13 - Prob. 60ACh. 13 - Prob. 61ACh. 13 - Prob. 62ACh. 13 - Prob. 63ACh. 13 - Prob. 64ACh. 13 - Prob. 65ACh. 13 - Prob. 66ACh. 13 - Prob. 67ACh. 13 - Prob. 68ACh. 13 - Prob. 69ACh. 13 - Prob. 70ACh. 13 - Prob. 71ACh. 13 - Prob. 72ACh. 13 - Prob. 73ACh. 13 - Prob. 74ACh. 13 - Prob. 75ACh. 13 - Prob. 76ACh. 13 - Prob. 1STPCh. 13 - Prob. 2STPCh. 13 - Prob. 3STPCh. 13 - Prob. 4STPCh. 13 - Prob. 5STPCh. 13 - Prob. 6STPCh. 13 - Prob. 7STPCh. 13 - Prob. 8STPCh. 13 - Prob. 9STPCh. 13 - Prob. 10STP
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