Organic Chemistry (8th Edition)
Organic Chemistry (8th Edition)
8th Edition
ISBN: 9780134042282
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Chapter 12, Problem 47P

(a)

Interpretation Introduction

Interpretation:

The ΔH value for the given reaction should be calculated.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

The ΔH can be calculated by using following formula,

ΔHo=bondbroken-bondsformed

(b)

Interpretation Introduction

Interpretation:

The sum of the ΔH value for the given reaction should be calculated.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Propagation: In this stage, two steps are involving hydrogen abstraction and halogen abstraction (no change in the number of free radicals)

(c)

Interpretation Introduction

Interpretation:

The reason why both the above reactions from subpart (a) and (b) have same ΔH value.has to be explained.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Propagation: In this stage, two steps are involving hydrogen abstraction and halogen abstraction (no change in the number of free radicals)

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Calculate ∆H for the reaction 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g), from the following data. 1. N2 (g) + O2 (g) → 2NO (g) ∆H = -180.5 kJ 2. N2 (g) + 3H2 (g) → 2 NH3 (g) ∆H = -91.8 kJ 3. 2H2 (g) + O2 (g) → 2H2O (g) ∆H = -483.6 kJ

Chapter 12 Solutions

Organic Chemistry (8th Edition)

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