Genetic Analysis: An Integrated Approach (3rd Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 12, Problem 29P

The bacterial insertion sequence IS 10 uses antisense RNA to regulate translation of the mRNA that produces the enzyme transposase, which is required for insertion sequence transposition. Transcription of the antisense RNA gene iscontrolled by POUT, which is over 10 times more efficient at transcription than the PIN promoter that controls transposase gene transcription.

a. If a mutation reduced the transcriptional efficiency of POUT so as to be equal to that of PIN, what is the likely effect on the transposition of IS 10 ?

b. If a mutation of PIN eliminates its ability to function in transcription, what is the likely effect on the transposition of IS 10 ?

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A bacterial species has a hypothetical sigma  promoter that has the following sequence: TTGGCA ­- 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT 1.The mutation would move the promoter away from consensus and reduce the level of transcription 2.No change the consensus TATAAT sequence in the same. 3.The mutation would bind the promoter to the consensus and produce normal levels of transcription 4.The mutation would inhibit the promoter thereby inhibiting transcription
A bacterial species has a hypothetical sigma promoter that has the following sequence: TTGGCA - 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT O The mutation would bind the promoter to the consensus and produce normal levels of transcription O The mutation would inhibit the promoter thereby inhibiting transcription The mutation would move the promoter away from consensus and reduce the level of transcription O No change the consensus TATAAT sequence in the same. D00 F3 F4 F5 F6 F7 F8 F9 % & 5 6 7 8 9 %24
Consider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices 1.Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds. 2.Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. 3.Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. 4.Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination.

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Genetic Analysis: An Integrated Approach (3rd Edition)

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