Consider the transconductance feedback amplifier shown in Figure P 12.56 with R D = 1.6 k Ω and R L = 248 Ω . The transistor parameters are V T N = 0.5 V , V T P = − 0.5 V , K n = 2 mA / V 2 , K p = 10 mA / V 2 , and λ n = λ p = 0. The LED turn-on voltage is V γ = 1.6 V . Assume the LED small signal resistance is r f = 0. The current source is ideal. (a) Determine the quiescent values of V D 1 , I D Q 3 and V G 2. (b) Derive the small-signal transconductance function A g f = I o / V i . (c) Calculate the value of A g f = I o / V i .
Consider the transconductance feedback amplifier shown in Figure P 12.56 with R D = 1.6 k Ω and R L = 248 Ω . The transistor parameters are V T N = 0.5 V , V T P = − 0.5 V , K n = 2 mA / V 2 , K p = 10 mA / V 2 , and λ n = λ p = 0. The LED turn-on voltage is V γ = 1.6 V . Assume the LED small signal resistance is r f = 0. The current source is ideal. (a) Determine the quiescent values of V D 1 , I D Q 3 and V G 2. (b) Derive the small-signal transconductance function A g f = I o / V i . (c) Calculate the value of A g f = I o / V i .
Solution Summary: The author explains the quiescent values of V_D1,I DQ3 and
Consider the transconductance feedback amplifier shown in Figure
P
12.56
with
R
D
=
1.6
k
Ω
and
R
L
=
248
Ω
.
The transistor parameters are
V
T
N
=
0.5
V
,
V
T
P
=
−
0.5
V
,
K
n
=
2
mA
/
V
2
,
K
p
=
10
mA
/
V
2
,
and
λ
n
=
λ
p
=
0.
The LED turn-on voltage is
V
γ
=
1.6
V
.
Assume the LED small signal resistance is
r
f
=
0.
The current source is ideal. (a) Determine the quiescent values of
V
D
1
,
I
D
Q
3
and
V
G
2.
(b) Derive the small-signal transconductance function
A
g
f
=
I
o
/
V
i
.
(c) Calculate the value of
A
g
f
=
I
o
/
V
i
.
Question -
qv²= +3 V
Rp
= 10 k2
= 100 k2
R2
= 200 k2
Rs
= 3 k2
(Vt=1V ve Kn=1.0mA/V)
(IRF540 N-Channel Mosfet)
- Calculate AC parameters. Compute the gain by completing the small signal analysis. Draw the input
and output signals to scale.
A = 100,000. Resistor
values are RI – 1000 Ω and Rf = 10,000 Ω. What is the
feedback return, and what is the amplification of the
feedback amplifier?
The circuit uses current- (or shunt-) feedback bias. The Si transistor has ICEO = 0, VCEsat =0, and
B= 100. If RC = 2k and VCC =12V, size RF for ideal maximum symmetrical swing (that is, location
of the quiescent point such that VCEQ =VCC/2).
+Vcc
Rc
Cc
lic
VL
Cc
R.
-20
"ca. V
-10
-12
14
-16
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