Chapter 10, Problem 52A

Interpretation Introduction

Interpretation: The specific heat capacity of the gold in $\text{cal/g°C}$ needs to be determined if the specific heat capacity in $\text{J/g°C}$ is $0.13\text{J/g°C}$ .

Concept introduction: Specific heat of capacity can be defined as the amount of heat added to a substance to raise the temperature by one degree.

The equation for the calculation of mass is as follows:

  $Q=s\times m\times \Delta T$

Where, Q is the amount of heat, m is the mass of substance, s is the specific heat capacity and $\Delta T$ is the temperature change.

Answer to Problem 52A

The value of $0.13\text{J/g°C}$ in $\text{cal/g°C}$ is $0.031\text{cal/g°C}$ .

Explanation of Solution

Conversion of specific heat capacity value $0.13\text{J/g°C}$ to $\text{cal/g°C}$ is as:

  $0.13\frac{\text{J}}{\text{g°C}}\times \frac{\text{1}\text{cal}}{\text{4}\text{.184}\text{J}}=0.031\text{cal/g°C}$

Hence, value of $0.13\text{J/g°C}$ in $\text{cal/g°C}$ is $0.031\text{cal/g°C}$ .

Conclusion

The specific heat capacity in $\text{J/g°C}$ can be converted into $\text{cal/g°C}$ using the conversion factor as:

  $\frac{\text{1}\text{cal}}{\text{4}\text{.184}\text{J}}$