Chapter 10, Problem 28A

Interpretation Introduction

Interpretation:35.2 g sample of metal X requires 1251 J of energy to heat the sample by $25.0°\text{C}$ . Specific heat capacity of this metal needs to be explained.

Concept Introduction:The expression for heat is as follows:

  $Q=s\times m\times \Delta T$

Here, Q represent energy required, s denotes specific heat capacity, m represent mass of the sample in grams and $\Delta T$ represent change in temperature.

Answer to Problem 28A

The s value in $\text{J/g}\text{°C}$ is $1.42\text{J/g}°\text{C}$ .

Explanation of Solution

Given values are as follows:

  $\begin{array}{l}Q=1251\text{J}\\ m=35.2\text{g}\\ \Delta T=25.0°\text{C}\\ s=?\end{array}$

Substitute all values in below question and find s.

  $\begin{array}{c}Q=s\times m\times \Delta T\\ 1251\text{J}=s\times 35.2\text{g}\times 25.0°\text{C}\\ s=\frac{1251\text{J}}{\text{35}\text{.2}\text{g}\times 25.0°\text{C}}\\ =1.42\text{J/g}°\text{C}\end{array}$

Therefore, s value is $1.42\text{J/g}°\text{C}$ .

Conclusion

The s value in $\text{J/g}\text{°C}$ is $1.42\text{J/g}°\text{C}$ .