Chapter 10, Problem 10A

Interpretation Introduction

Interpretation: If $100.0\text{g}$ of water at $90°\text{C}$ is added to $50.0\text{g}$ of water at $10°\text{C}$ , then final temperature of the water needs to be explained.

Concept Introduction: Temperature is a measurement of the spontaneous movements of a substance’s components. So, ${\text{H}}_{\text{2}}\text{O}$ molecules are progressing quickly in warm water than the ${\text{H}}_{\text{2}}\text{O}$ molecules in cold water.

Answer to Problem 10A

Final temperature of the water is $50°\text{C}$ .

Explanation of Solution

The final temperature is the average of the original temperature. Hence,

  $\begin{array}{c}{\text{T}}_{\text{final}}=\frac{{\text{T}}_{\text{1}}{\text{+T}}_{\text{2}}}{2}\\ =\frac{90°\text{C}+10°\text{C}}{2}\\ =\frac{100°\text{C}}{2}\\ =50°\text{C}\end{array}$

Hence, temperature of water is $50°\text{C}$ .

Conclusion

Final temperature of water is $50°\text{C}$ .