EBK ORGANIC CHEMISTRY-PRINT COMPANION (
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
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Chapter 1, Problem 57PP
Interpretation Introduction

Interpretation: The reason for higher boiling point of one of the isomers amongst two having molecular formula C2H6O needs to be explained.

Concept Introduction: The temperature at which transition of a substance takes place from liquid to gaseous state is said to be its boiling point. At boiling point, the vapor pressure and applied pressure on the liquid become equal. There is a direct relationship between the interaction present in molecule and the boiling point of the molecule. The molecule that has stronger interaction between its atoms/molecules possess higher boiling point and vice-versa.

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In what way(s) is(are) the structure of H2O similar to that of CHCl3? In what way is the structure of water different from that of CHCl3?
Draw Lewis structures and condensed structural formulas for the four alcohols with the molecular formula C4H10O. Classify each alcohol as primary, secondary, or tertiary. (Hint: First consider the connectivity of the four carbon atoms; they can be bonded either four in a chain or three in a chain with the fourth carbon as a branch on the middle carbon. Then consider the points at which the iOH group can be bonded to each carbon chain.)
Ethanol and dimethyl ether have the same molecular formula C2H6O. Ethanol is liquid at room teperature while dimethyl ether is gas. How is this possible? Explain.
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