Chapter U3.63, Problem 6E

(a)

Interpretation Introduction

Interpretation :

The given samples must be listed in order of increasing gas pressure.

Concept Introduction :

A gas sample with lesser volume and larger number of molecules will have high pressure as per ideal gas equation. The equation is as follows:

  $\text{PV=nRT}$

Here P, V,n, R and T are pressure, volume, mole number, universal gas constant and absolute temperature respectively.

Answer to Problem 6E

Sample in the order of increasing gas pressure will be

sample B <sample A<sample C.

Explanation of Solution

Sample C has maximum number of gas molecules and smallest volume. Thus, pressure will be maximum.

Sample B and C have same number of gas molecules but sample B has larger volume as compared to sample A. Thus, sample B will have minimum pressure.

b)

Interpretation Introduction

Interpretation :

A volume of air must be sketched that has a pressure in between the pressures in boxes A and B.

Concept Introduction :

To have in between pressure of a sample with respect to box A and B, the $\frac{\text{n}}{\text{V}}$ (mol/L) ratio of the new sample must be in between of Box A and B.

Answer to Problem 6E

A sketch of air is shown below.

  

Explanation of Solution

From the sketch it is clear that the new sample also contains same number of gas molecules (10) as present in box A and B. But the volume of new sample is more than sample A but less then sample B. Thus $\frac{\text{n}}{\text{V}}$ ratio for new sample will be in between of sample A and B. So new sample will have in between pressure with respect to box A and B.