Living by Chemistry
Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
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Chapter U3.54, Problem 4E
Interpretation Introduction

Interpretation: The volume of the gas at 130 oC needs to be determined if it is initially 980 mL at 27 oC temperature.

Concept Introduction:

The Charles’s law states that at constant pressure, the volume of the gas is directly proportional to its temperature. It is mathematically represented as follows:

  T1V1=T2V2

Here, T1 is initial temperature, V1 is initial volume, T2 is final temperature and V2 is final volume.

Expert Solution & Answer
Check Mark

Answer to Problem 4E

1316.3 mL

Explanation of Solution

The initial volume and temperature of the gas is 980 mL and 27 oC respectively. First convert the temperature from oC to K as follows:

  T=(27+273.15) K=300.15 K

Thus,

  T1=300.15 K and V1=980 mL

Now, the final temperature is given 130 oC which can be converted into K as follows:

  T2=(130+273.15) K=403.15 K

Thus, final volume can be calculated from Charles’s law as follows:

  T1V1=T2V2

Putting the values,

  300.15 K980 mL=403.15 KV2

On rearranging,

  V2=403.15 K300.15 K×980 mL=1316.3 mL

Conclusion

Thus, the volume of the gas becomes 1316.3 mL at 130 oC.

Chapter U3 Solutions

Living by Chemistry

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