Living by Chemistry
Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
bartleby

Concept explainers

Kinetic-Theory of Gases
Kinetic theory of gases is the model or method which was developed in the 19th century by Maxwell and Boltzmann. This is possible as the interatomic force which is of short-range forces that are important for solids and liquids can be neglected for gases…
Question
Book Icon
Chapter U3.63, Problem 1E
Interpretation Introduction

Interpretation :

The decrease in air pressure with increasing altitude must be explained.

Concept Introduction :

Air pressure or the atmospheric pressure is due to the weight of the column of air which is present from ground to higher altitude.

Expert Solution & Answer
Check Mark

Answer to Problem 1E

Air pressure decreases with increase in altitude because the length of the column of air decreases.

Explanation of Solution

Due to gravity, the air is denser near the ground sea level. With the increase of altitude the air becomes lighter. The upper limit where the presence of air can be detected is around 10000 km. So, the length of column of air decreases as higher altitude is reached. Thus, air pressure decreases.

Conclusion

The decrease in air pressure with the increase in altitude is explained.

Previous
Chapter U3.63, Problem 1TAI
Next
Chapter U3.63, Problem 2E

Chapter U3 Solutions

Living by Chemistry

Ch. U3.49 - Prob. 1TAICh. U3.49 - Prob. 1ECh. U3.49 - Prob. 2ECh. U3.49 - Prob. 3ECh. U3.49 - Prob. 4ECh. U3.49 - Prob. 6ECh. U3.50 - Prob. 1TAICh. U3.50 - Prob. 1ECh. U3.50 - Prob. 2ECh. U3.50 - Prob. 3E
Ch. U3.50 - Prob. 4ECh. U3.50 - Prob. 5ECh. U3.50 - Prob. 6ECh. U3.50 - Prob. 7ECh. U3.51 - Prob. 1TAICh. U3.51 - Prob. 1ECh. U3.51 - Prob. 2ECh. U3.51 - Prob. 3ECh. U3.51 - Prob. 4ECh. U3.51 - Prob. 5ECh. U3.51 - Prob. 6ECh. U3.51 - Prob. 7ECh. U3.51 - Prob. 8ECh. U3.51 - Prob. 9ECh. U3.52 - Prob. 1TAICh. U3.52 - Prob. 1ECh. U3.52 - Prob. 2ECh. U3.52 - Prob. 3ECh. U3.52 - Prob. 4ECh. U3.52 - Prob. 5ECh. U3.52 - Prob. 6ECh. U3.52 - Prob. 7ECh. U3.52 - Prob. 8ECh. U3.52 - Prob. 9ECh. U3.53 - Prob. 1TAICh. U3.53 - Prob. 1ECh. U3.53 - Prob. 2ECh. U3.53 - Prob. 3ECh. U3.53 - Prob. 4ECh. U3.53 - Prob. 5ECh. U3.53 - Prob. 6ECh. U3.53 - Prob. 7ECh. U3.53 - Prob. 8ECh. U3.53 - Prob. 9ECh. U3.53 - Prob. 10ECh. U3.53 - Prob. 11ECh. U3.53 - Prob. 12ECh. U3.54 - Prob. 1TAICh. U3.54 - Prob. 1ECh. U3.54 - Prob. 2ECh. U3.54 - Prob. 3ECh. U3.54 - Prob. 4ECh. U3.54 - Prob. 5ECh. U3.54 - Prob. 6ECh. U3.54 - Prob. 7ECh. U3.54 - Prob. 8ECh. U3.55 - Prob. 1TAICh. U3.55 - Prob. 1ECh. U3.55 - Prob. 2ECh. U3.55 - Prob. 3ECh. U3.55 - Prob. 4ECh. U3.55 - Prob. 5ECh. U3.55 - Prob. 6ECh. U3.56 - Prob. 1TAICh. U3.56 - Prob. 1ECh. U3.56 - Prob. 2ECh. U3.56 - Prob. 3ECh. U3.56 - Prob. 4ECh. U3.56 - Prob. 5ECh. U3.56 - Prob. 6ECh. U3.56 - Prob. 7ECh. U3.56 - Prob. 8ECh. U3.56 - Prob. 9ECh. U3.56 - Prob. 10ECh. U3.57 - Prob. 1TAICh. U3.57 - Prob. 1ECh. U3.57 - Prob. 2ECh. U3.57 - Prob. 3ECh. U3.57 - Prob. 4ECh. U3.57 - Prob. 5ECh. U3.57 - Prob. 6ECh. U3.57 - Prob. 7ECh. U3.57 - Prob. 8ECh. U3.57 - Prob. 10ECh. U3.58 - Prob. 1TAICh. U3.58 - Prob. 1ECh. U3.58 - Prob. 2ECh. U3.58 - Prob. 4ECh. U3.58 - Prob. 5ECh. U3.58 - Prob. 6ECh. U3.58 - Prob. 7ECh. U3.59 - Prob. 1TAICh. U3.59 - Prob. 1ECh. U3.59 - Prob. 2ECh. U3.59 - Prob. 3ECh. U3.59 - Prob. 4ECh. U3.59 - Prob. 5ECh. U3.60 - Prob. 1TAICh. U3.60 - Prob. 1ECh. U3.60 - Prob. 2ECh. U3.60 - Prob. 3ECh. U3.60 - Prob. 4ECh. U3.60 - Prob. 5ECh. U3.60 - Prob. 6ECh. U3.60 - Prob. 7ECh. U3.60 - Prob. 8ECh. U3.61 - Prob. 1TAICh. U3.61 - Prob. 1ECh. U3.61 - Prob. 2ECh. U3.61 - Prob. 3ECh. U3.61 - Prob. 4ECh. U3.61 - Prob. 5ECh. U3.61 - Prob. 6ECh. U3.61 - Prob. 7ECh. U3.62 - Prob. 1TAICh. U3.62 - Prob. 1ECh. U3.62 - Prob. 2ECh. U3.63 - Prob. 1TAICh. U3.63 - Prob. 1ECh. U3.63 - Prob. 2ECh. U3.63 - Prob. 3ECh. U3.63 - Prob. 4ECh. U3.63 - Prob. 5ECh. U3.63 - Prob. 6ECh. U3.63 - Prob. 7ECh. U3.63 - Prob. 8ECh. U3.64 - Prob. 1TAICh. U3.64 - Prob. 1ECh. U3.64 - Prob. 2ECh. U3.64 - Prob. 3ECh. U3.64 - Prob. 4ECh. U3.64 - Prob. 5ECh. U3.64 - Prob. 6ECh. U3.64 - Prob. 7ECh. U3.65 - Prob. 1TAICh. U3.65 - Prob. 1ECh. U3.65 - Prob. 2ECh. U3.65 - Prob. 3ECh. U3.65 - Prob. 4ECh. U3.65 - Prob. 5ECh. U3.65 - Prob. 6ECh. U3.65 - Prob. 7ECh. U3.65 - Prob. 8ECh. U3.66 - Prob. 1TAICh. U3.66 - Prob. 1ECh. U3.66 - Prob. 2ECh. U3.66 - Prob. 3ECh. U3.66 - Prob. 4ECh. U3.66 - Prob. 5ECh. U3.66 - Prob. 6ECh. U3.66 - Prob. 7ECh. U3.66 - Prob. 8ECh. U3.66 - Prob. 9ECh. U3.66 - Prob. 10ECh. U3.66 - Prob. 11ECh. U3.66 - Prob. 12ECh. U3.67 - Prob. 1TAICh. U3.67 - Prob. 1ECh. U3.67 - Prob. 2ECh. U3.67 - Prob. 4ECh. U3 - Prob. C10.1RECh. U3 - Prob. C10.2RECh. U3 - Prob. C10.3RECh. U3 - Prob. C10.4RECh. U3 - Prob. C10.5RECh. U3 - Prob. C11.1RECh. U3 - Prob. C11.2RECh. U3 - Prob. C11.3RECh. U3 - Prob. C11.4RECh. U3 - Prob. C11.5RECh. U3 - Prob. C12.1RECh. U3 - Prob. C12.2RECh. U3 - Prob. C12.3RECh. U3 - Prob. C12.4RECh. U3 - Prob. C12.5RECh. U3 - Prob. 1RECh. U3 - Prob. 2RECh. U3 - Prob. 3RECh. U3 - Prob. 4RECh. U3 - Prob. 5RECh. U3 - Prob. 6RECh. U3 - Prob. 7RECh. U3 - Prob. 8RECh. U3 - Prob. 9RECh. U3 - Prob. 10RECh. U3 - Prob. 11RECh. U3 - Prob. 12RECh. U3 - Prob. 13RECh. U3 - Prob. 1STPCh. U3 - Prob. 2STPCh. U3 - Prob. 3STPCh. U3 - Prob. 4STPCh. U3 - Prob. 5STPCh. U3 - Prob. 6STPCh. U3 - Prob. 7STPCh. U3 - Prob. 8STPCh. U3 - Prob. 9STPCh. U3 - Prob. 10STPCh. U3 - Prob. 11STPCh. U3 - Prob. 12STPCh. U3 - Prob. 13STPCh. U3 - Prob. 14STPCh. U3 - Prob. 15STPCh. U3 - Prob. 16STPCh. U3 - Prob. 17STPCh. U3 - Prob. 18STPCh. U3 - Prob. 19STPCh. U3 - Prob. 20STP

Additional Science Textbook Solutions

Find more solutions based on key concepts
The salt which would require more energy to break the ionic bonds needs to be identified. Concept introduction:...

Chemistry: Matter and Change

33. Consider the reaction: The tabulated data were collected for the concentration of C4H8 as a function...

Chemistry: Structure and Properties (2nd Edition)

Calculate the quantity of heat, in kilojoules, (a) required to raise the temperature of 9.25 L of water from 22...

General Chemistry: Principles and Modern Applications (11th Edition)

a. How can aspirin be synthesized from benzene? b. Ibuprofen is the active ingredient in pain relievers such as...

Organic Chemistry

Calculate the lattice energy of CaCl2 using a Born-Haber cycle and data from Appendices F and L and Table 7.5. ...

Chemistry & Chemical Reactivity

Determine [OH], [H+], and the pH of each of the following solutions. a. 1.0 M KCl b. 1.0 M KC2H3O2

Chemistry

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
SEE MORE TEXTBOOKS