a.
The molecule’s impulse on the wall.
a.
Answer to Problem 55A
Explanation of Solution
Given:
The mass of the nitrogen molecule,
Initial velocity of the molecule,
Final velocity of the molecule,
Formula used:
Momentum of an object of mass m and moving with velocity v is given by,
Impulse on an object is equal to the change in momentum of an object,
Where
Calculation:
Assume the initial direction of motion of the molecule be positive, then the opposite direction will be negative. Then, the velocities will be,
Using the given values, the impulse on the molecule will be,
Then, the molecule’s impulse on the wall will be in opposite direction of above Impulse,
Conclusion:
Thus, the molecule’s momentum on the wall is
b.
The average force on the wall if there are
b.
Answer to Problem 55A
Explanation of Solution
Given:
The mass of the nitrogen molecule,
Initial velocity of the molecule,
Final velocity of the molecule,
From part (a), the molecule’s impulse on the wall,
Formula used:
Momentum of an object of mass m and moving with velocity v is given by,
Impulse on an object is equal to the change in momentum of an object,
Where
Calculation:
Then the force on the molecule due to the collisions will be,
Using all the given values in above,
Then, the force on the wall will be,
Conclusion:
Thus, the average force on the wall is
Chapter 9 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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