Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Chapter 9, Problem 3P
The calculations of the average restriction fragment size in Fig. 9.2 assume that DNA is composed equally of the four possible
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The restriction endonuclease NciI recognizes and cuts the five-base-pair sequence 5’- CC(G/C)GG-3’ [where (G/C) means either G or C will work at that position]. (1) How often, on average, would this sequence occur in random DNA? Assume the DNA contains 25% each of A, G, T & C. (2) After digestion, Nci1 leaves a one-base 5’ overhang. Write/draw the cut site/digested products.
A linear DNA molecule is subjected to complete restriction digestion by (1) EcoRI alone, (2)
HindIII alone, and (3) both enzymes together. The DNA fragments are then separated using
gel electrophoresis. Results are shown below:
(i)
(ii)
(iii)
EcoRI Hindill Both
| |
—
| |
10 kb
9 kb
8 kb
5 kb
2 kb
1 kb
How long is the original DNA molecule?
How many EcoRI recognition sites does it have?
Does the longest EcoRI fragment contain a HindIII restriction site? Explain your
answer.
Human genomic libraries used for DNA sequencing are often made from fragments obtained by cleaving human DNA with Haeiii in such a way that the DNA is only partially digested; that is, not all the possible HaeIII sites have been cleaved. What is a possible reason for doing this?
Chapter 9 Solutions
Genetics: From Genes to Genomes
Ch. 9 - Match each of the terms in the left column to the...Ch. 9 - For each of the restriction enzymes listed below:...Ch. 9 - The calculations of the average restriction...Ch. 9 - The DNA molecule whose entire sequence follows is...Ch. 9 - Why do longer DNA molecules move more slowly than...Ch. 9 - Agarose gels with different average pore sizes are...Ch. 9 - The following picture shows the ethidium...Ch. 9 - The linear bacteriophage genomic DNA has at each...Ch. 9 - Consider a partial restriction digestion, in which...Ch. 9 - The text stated that molecular biologists have...
Ch. 9 - a. What is the purpose of molecular cloning? b....Ch. 9 - a. DNA polymerase b. RNA polymerase c. A...Ch. 9 - Is it possible that two different restriction...Ch. 9 - A plasmid vector pBS281 is cleaved by the enzyme...Ch. 9 - A recombinant DNA molecule is constructed using a...Ch. 9 - Suppose you are using a plasmid cloning vector...Ch. 9 - Prob. 17PCh. 9 - The lacZ gene from E. coli encodes the enzyme...Ch. 9 - Your undergraduate research advisor has assigned...Ch. 9 - Which of the enzymes from the following list would...Ch. 9 - You use the primer 5 GCCTCGAATCGGGTACC 3 to...Ch. 9 - a. To make a genomic library useful for sequencing...Ch. 9 - Problem 15 showed part of the sequence of the...Ch. 9 - Eukaryotic genomes are replete with repetitive...
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- DNA isolated from an organism can be sheared into fragments of uniform size (∼1000 bp), heated to separate the strands, then cooled to allow complementary strands to reanneal. The renaturation process can be followed over time. Explain why the renaturation of E. coli DNA is a monophasic process, whereas the renaturation of human DNA is biphasic (an initial rapid phase followed by a slower phase).arrow_forwardA facility says they need 15 μL of a 40 ng/μL solution of plasmid DNA for sequencing. The typical yield for a DNA miniprep 5 μg eluted in 50 μL of solution. What do you need to do (for example dilution) to send the appropriate amount to the facility? Show all math work with an explanation.arrow_forwardA linear piece of DNA that is 14 kb long is cut first by EcoRI alone, then by SmaI alone, and finally, by both EcoRI and SmaI together. The following results are obtained: Draw a map of the EcoRI and SmaI restriction sites on this 14-kb piece of DNA, indicating the relative positions of the restriction sites and the distances between them.arrow_forward
- Base analysis of DNA from maize (corn) shows it to have 23 mole percent cytosine (moles per 100 moles total nucleotide). What are the percentages of the other three bases?arrow_forwardA purified recombinant protein is analyzed for molecular weight by SDS-PAGE at pH 8.5. From the protein sequence deduced from the gene that was expressed in bacteria, the protein is expected to have a molecular weight of 44,000. However, the molecular weight of the protein is found by SDS-PAGE to be 52,000. Explain the reason or reasons for this difference in molecular weight. What calculation could you make to help explain this discrepancy?arrow_forwardUsing the formulae for dsDNA to calculate g/mol: You have a 4110 bp cloning vector Want to ligate a 245 bp insert for molecular cloning. efficient cloning requires that a 1:5 molar ratio of vector to insert is optimal for the ligation reaction. What are the relative weights of vector and the insert DNA necessary in g?arrow_forward
- DNA renaturation curves occasionally show three distinct phases of renaturation. In this graph, DNA renaturation is plotted against C0t (initialconcentration times time of renaturation—essentially a measure of relativerenaturation time). See Figure 21.3.(a) Identify each part of this plot that corresponds to reannealing of (1)unique sequences, (2) moderately repetitive sequences, and (3) highlyrepetitive sequences.(b) Suppose that you cloned a single-copy gene, such as the gene for dihydrofolate reductase (DHFR), into a plasmid vector and subjected it torenaturation analysis. Sketch the curve you might expect.(c) Suppose that you used reverse transcriptase to copy the ovalbumin mRNA and cloned this complementary DNA (cDNA) into a plasmid vector. Would you expect this cDNA to reanneal (1) more slowly, (2) more rapidly, or (3) at the same rate as genomic DNA? Briefly explain your answer.arrow_forwardA lilP mutant called lilPXS is isolated that produces a truncated polypeptide of only 6 AA in length. Describe a single basepair DNA change that would lead to this truncated version of the protein. Multiple options are possible (100 words max.)arrow_forwardKpn I and Acc 65I are restriction enzymes that identify and cleave the same 6-bp sequence. The sticky end created by Kpn I cleavage, on the other hand, cannot be directly ligated to the sticky end formed by Acc 65I cleavage. Please explain why.arrow_forward
- Your PhD thesis advisor has given you the task of preparing a human genomic DNA library. 3a. How will you prepare DNA fragments from the human genomic DNA for use in construction of this library assuming that you want the insert sizes to be about 20000bp in size?arrow_forwardAgarose gels with different average pore sizes areneeded to separate DNA molecules of different sizeclasses. For example, optimal separation of 1100 bpand 1200 bp fragments would require a gel with alarger average pore size than optimal separation of8500 bp and 8600 bp fragments. How do you thinkthat scientists prepare gels of different average poresizes? (Hint: Agarose gels are made in a mannersimilar to gelatin desserts such as JELL-O.)arrow_forwardIn Polymerase Chain Reaction (PCR), the temperature is one of the most important parameters that could influence the efficiency of this technique. Each cycle of this reaction has its own specific temperature. For instance, the denaturation step possesses a temperature of 94 - 98 ℃ to ensure that the double stranded DNA is fully separated. (i) (ii) (iii) Why is the annealing temperature vital in this technique? Explain how will this temperature affects the efficiency of this reaction. Why is Hot Start PCR technique preferred by some researchers? If the primers you purchased possessed the following information. 5'-GGA AAC AGC TAT GAC CAT G-3' Calculate the melting temperature of this primer and estimate the annealing temperature of this primer.arrow_forward
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