Chapter 8.8, Problem 37IP

To determine

Find the number of granola bar and magazines he can buy.

Answer to Problem 37IP

Tim can buy at most 6 Granola bars and 6 magazines.

Explanation of Solution

Given:

Tim is taking the train to Seattle to visit his grandparents. He has at most $15.00 to spend on snacks and reading material. Granola bars cost $1.15 each, and magazines cost $1.25. If Tim buys the same number of granola bars and magazines, how many he can buy?

Concept Used:

Translate the conditions given in the question into an inequality.

He has at most $15.00 to spend: $\le \$15$

Granola bars cost $1.15 each, and magazines cost $1.25.

Tim buys the same number of granola bars and magazines.

Let the number of both item is x

The required inequality: $1.15x+1.25x\le \$15$

Calculation:

The required inequality: $1.15x+1.25x\le \$15$

Now solve for x :

  $\begin{array}{l}1.15x+1.25x\le \$15\\ 2.40x\le 15\\ \frac{2.40x}{2.40}\le \frac{15}{2.40}[\text{Divide}\text{both}\text{sides}\text{by}2.40]\\ x\le 6.25\end{array}$

Tim can buy at most 6 Granola bars and 6 magazines.

Thus, Tim can buy at most 6 Granola bars and 6 magazines.