Answer The equation is 10 + 6 m = 6 + 8 m The months are m = 2 . Explanation Given: An online video game site charges a $10 membership fee and a %6.00 monthly cost. Another game site charges $6 membership fee and a $8.00 monthly cost Concept Used: To get rid of a number in addition from one side, subtract the same number from both sides of equal sign. To get rid of a number in subtraction from one side, add the same number both sides of equal sign. To get rid of a number in multiplication from one side, divide the same number from both sides of equal sign. To get rid of a number in division from one side, multiply the same number both sides of equal sign. Rules of Addition/ Subtraction: Two numbers with similar sign always get added and the resulting number will carry the similar sign. Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number. Rules of Multiplication/ Division: The product/quotient of two similar sign numbers is always positive. The product/quotient of two numbers with opposite signs is always negative. Calculation: In order to find the month Let m be the month A video game site charge $10 is the membership fee and $6 is the cost per month So, the equation is 10 + 6 m Another game site charge $6 is the membership fee and $8 is the cost per month So, the equation is 6 + 8 m Equate the both expression 10 + 6 m = 6 + 8 m Thus, the equation is 10 + 6 m = 6 + 8 m Here to isolate m on left side, first subtract both sides by 6 m and then subtract both sides by 6 and then divide both sides by 2 and then simplify further as shown below, 10 + 6 m = 6 + 8 m 10 + 6 m − 6 m = 6 + 8 m − 6 m 10 = 6 + 2 m 10 − 6 = 6 + 2 m − 6 4 = 2 m 4 2 = 2 m 2 2 = m ⇒ m = 2 Thus, the months are m = 2 .

Glencoe Math Accelerated, Student Edition

1st Edition

ISBN: 9780076637980

Author: McGraw-Hill Glencoe

Publisher: MCG

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Question

Chapter 8, Problem 34CR

To determine

An equation and how many months it would take for the total cost of the two sites to be the same

Expert Solution & Answer

Answer to Problem 34CR

The equation is $10+6m=6+8m$

The months are $m=2$ .

Explanation of Solution

Given:

An online video game site charges a $10 membership fee and a %6.00 monthly cost. Another game site charges $6 membership fee and a $8.00 monthly cost

Concept Used:

To get rid of a number in addition from one side, subtract the same number from both sides of equal sign.
To get rid of a number in subtraction from one side, add the same number both sides of equal sign.
To get rid of a number in multiplication from one side, divide the same number from both sides of equal sign.
To get rid of a number in division from one side, multiply the same number both sides of equal sign.

Rules of Addition/ Subtraction:

Two numbers with similar sign always get added and the resulting number will carry the similar sign.
Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number.

Rules of Multiplication/ Division:

The product/quotient of two similar sign numbers is always positive.
The product/quotient of two numbers with opposite signs is always negative.

Calculation:

In order to find the month

Let m be the month

A video game site charge $10 is the membership fee and $6 is the cost per month

So, the equation is $10+6m$

Another game site charge $6 is the membership fee and $8 is the cost per month

So, the equation is $6+8m$

Equate the both expression $10+6m=6+8m$

Thus, the equation is $10+6m=6+8m$

Here to isolate m on left side, first subtract both sides by $6m$ and then subtract both sides by $6$ and then divide both sides by $2$ and then simplify further as shown below,

$10+6m=6+8m10+6m−6m=6+8m−6m10=6+2m10−6=6+2m−64=2m42=2m22=m⇒m=2$

Thus, the months are $m=2$ .

Chapter 8, Problem 33CR

Chapter 8, Problem 35CR

Chapter 8 Solutions

Glencoe Math Accelerated, Student Edition

Ch. 8.1 - Prob. 1GP Ch. 8.1 - Prob. 2GP Ch. 8.1 - Prob. 3GP Ch. 8.1 - Prob. 4GP Ch. 8.1 - Prob. 5GP Ch. 8.1 - Prob. 6GP Ch. 8.1 - Prob. 7GP Ch. 8.1 - Prob. 8GP Ch. 8.1 - Prob. 9GP Ch. 8.1 - Prob. 10GP

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