(a) Answer The distance travelled by the traveller is 500 units. Given: The given diagram is shown in Figure 1 Figure 1 The function for the distance travelled by the traveller is y = D ( x ) . Calculation: Consider the function D ( 2 ) . From the graph the function D ( 2 ) shows that the distance and the time have a liner relation at D ( 2 ) and at D ( 2 ) the distance travelled by the traveller is 500 units. (b) To Find: The solution to determine the solution of the equation D ( x ) = 3500 and explain its relevance. The solution is D ( 15 ) = 3500 . Consider the given function D ( x ) = 3500 . Consider the given function is y = D ( x ) . Then at y = 35000 the time is x = 15 and the required solution is, D ( 15 ) = 3500 (c) To Find: The time for which the traveller has to wait for the shuttle bus. The wait time of the traveller is 15 min . The graph shows that the time taken by the traveller to reach the shuttle is of x = 15 minute. (d) To Find: The distance travelled by the traveller on the shuttle bus. The distance travelled by the traveller on the shuttle bus is not determined from the graph. From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet. (e) To Find: The total distance that the traveller walks before and after riding the shuttle bus. The total distance travelled is 5508 . Consider the distance from the origin to the first point ( 4 , 1000 ) is, d 1 = ( 4 − 0 ) 2 + ( 1000 − 0 ) 2 = 1000 Consider the distance from ( 4 , 1000 ) to the first point ( 12 , 1000 ) is, d 2 = ( 12 − 4 ) 2 + ( 1000 − 1000 ) 2 = 8 Consider the distance from ( 12 , 1000 ) to the first point ( 13 , 3000 ) is, d 3 = ( 3000 − 1000 ) 2 + ( 13 − 12 ) 2 = 2000 Consider the distance from ( 13 , 3000 ) to the first point ( 13 , 3500 ) is, d 3 = ( 15 − 12 ) 2 + ( 3500 − 1000 ) 2 = 2500 Thus, the total distance travelled by the traveller is, d = 1000 + 8 + 2000 + 2500 = 5508 Explanation Given: The given diagram is shown in Figure 1 Figure 1 The function for the distance travelled by the traveller is y = D ( x ) . Calculation: Consider the function D ( 2 ) . From the graph the function D ( 2 ) shows that the distance and the time have a liner relation at D ( 2 ) and at D ( 2 ) the distance travelled by the traveller is 500 units. (b) To determine To Find: The solution to determine the solution of the equation D ( x ) = 3500 and explain its relevance. Answer The solution is D ( 15 ) = 3500 . Consider the given function D ( x ) = 3500 . Consider the given function is y = D ( x ) . Then at y = 35000 the time is x = 15 and the required solution is, D ( 15 ) = 3500 (c) To Find: The time for which the traveller has to wait for the shuttle bus. The wait time of the traveller is 15 min . The graph shows that the time taken by the traveller to reach the shuttle is of x = 15 minute. (d) To Find: The distance travelled by the traveller on the shuttle bus. The distance travelled by the traveller on the shuttle bus is not determined from the graph. From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet. (e) To Find: The total distance that the traveller walks before and after riding the shuttle bus. The total distance travelled is 5508 . Consider the distance from the origin to the first point ( 4 , 1000 ) is, d 1 = ( 4 − 0 ) 2 + ( 1000 − 0 ) 2 = 1000 Consider the distance from ( 4 , 1000 ) to the first point ( 12 , 1000 ) is, d 2 = ( 12 − 4 ) 2 + ( 1000 − 1000 ) 2 = 8 Consider the distance from ( 12 , 1000 ) to the first point ( 13 , 3000 ) is, d 3 = ( 3000 − 1000 ) 2 + ( 13 − 12 ) 2 = 2000 Consider the distance from ( 13 , 3000 ) to the first point ( 13 , 3500 ) is, d 3 = ( 15 − 12 ) 2 + ( 3500 − 1000 ) 2 = 2500 Thus, the total distance travelled by the traveller is, d = 1000 + 8 + 2000 + 2500 = 5508 Explanation Consider the given function D ( x ) = 3500 . Consider the given function is y = D ( x ) . Then at y = 35000 the time is x = 15 and the required solution is, D ( 15 ) = 3500 (c) To determine To Find: The time for which the traveller has to wait for the shuttle bus. Answer The wait time of the traveller is 15 min . The graph shows that the time taken by the traveller to reach the shuttle is of x = 15 minute. (d) To Find: The distance travelled by the traveller on the shuttle bus. The distance travelled by the traveller on the shuttle bus is not determined from the graph. From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet. (e) To Find: The total distance that the traveller walks before and after riding the shuttle bus. The total distance travelled is 5508 . Consider the distance from the origin to the first point ( 4 , 1000 ) is, d 1 = ( 4 − 0 ) 2 + ( 1000 − 0 ) 2 = 1000 Consider the distance from ( 4 , 1000 ) to the first point ( 12 , 1000 ) is, d 2 = ( 12 − 4 ) 2 + ( 1000 − 1000 ) 2 = 8 Consider the distance from ( 12 , 1000 ) to the first point ( 13 , 3000 ) is, d 3 = ( 3000 − 1000 ) 2 + ( 13 − 12 ) 2 = 2000 Consider the distance from ( 13 , 3000 ) to the first point ( 13 , 3500 ) is, d 3 = ( 15 − 12 ) 2 + ( 3500 − 1000 ) 2 = 2500 Thus, the total distance travelled by the traveller is, d = 1000 + 8 + 2000 + 2500 = 5508 Explanation The graph shows that the time taken by the traveller to reach the shuttle is of x = 15 minute. (d) To determine To Find: The distance travelled by the traveller on the shuttle bus. Answer The distance travelled by the traveller on the shuttle bus is not determined from the graph. From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet. (e) To Find: The total distance that the traveller walks before and after riding the shuttle bus. The total distance travelled is 5508 . Consider the distance from the origin to the first point ( 4 , 1000 ) is, d 1 = ( 4 − 0 ) 2 + ( 1000 − 0 ) 2 = 1000 Consider the distance from ( 4 , 1000 ) to the first point ( 12 , 1000 ) is, d 2 = ( 12 − 4 ) 2 + ( 1000 − 1000 ) 2 = 8 Consider the distance from ( 12 , 1000 ) to the first point ( 13 , 3000 ) is, d 3 = ( 3000 − 1000 ) 2 + ( 13 − 12 ) 2 = 2000 Consider the distance from ( 13 , 3000 ) to the first point ( 13 , 3500 ) is, d 3 = ( 15 − 12 ) 2 + ( 3500 − 1000 ) 2 = 2500 Thus, the total distance travelled by the traveller is, d = 1000 + 8 + 2000 + 2500 = 5508 Explanation From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet. (e) To determine To Find: The total distance that the traveller walks before and after riding the shuttle bus. Answer The total distance travelled is 5508 . Consider the distance from the origin to the first point ( 4 , 1000 ) is, d 1 = ( 4 − 0 ) 2 + ( 1000 − 0 ) 2 = 1000 Consider the distance from ( 4 , 1000 ) to the first point ( 12 , 1000 ) is, d 2 = ( 12 − 4 ) 2 + ( 1000 − 1000 ) 2 = 8 Consider the distance from ( 12 , 1000 ) to the first point ( 13 , 3000 ) is, d 3 = ( 3000 − 1000 ) 2 + ( 13 − 12 ) 2 = 2000 Consider the distance from ( 13 , 3000 ) to the first point ( 13 , 3500 ) is, d 3 = ( 15 − 12 ) 2 + ( 3500 − 1000 ) 2 = 2500 Thus, the total distance travelled by the traveller is, d = 1000 + 8 + 2000 + 2500 = 5508 Explanation Consider the distance from the origin to the first point ( 4 , 1000 ) is, d 1 = ( 4 − 0 ) 2 + ( 1000 − 0 ) 2 = 1000 Consider the distance from ( 4 , 1000 ) to the first point ( 12 , 1000 ) is, d 2 = ( 12 − 4 ) 2 + ( 1000 − 1000 ) 2 = 8 Consider the distance from ( 12 , 1000 ) to the first point ( 13 , 3000 ) is, d 3 = ( 3000 − 1000 ) 2 + ( 13 − 12 ) 2 = 2000 Consider the distance from ( 13 , 3000 ) to the first point ( 13 , 3500 ) is, d 3 = ( 15 − 12 ) 2 + ( 3500 − 1000 ) 2 = 2500 Thus, the total distance travelled by the traveller is, d = 1000 + 8 + 2000 + 2500 = 5508

BIG IDEAS MATH Integrated Math 1: Student Edition 2016

16th Edition

ISBN: 9781680331127

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Houghton Mifflin Harcourt

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Question

Chapter 7, Problem 9CA

(a)

To determine

To Find: The estimation and the interpretation of $D(2)$ .

(a)

Expert Solution

Answer to Problem 9CA

The distance travelled by the traveller is 500 units.

Given:

The given diagram is shown in Figure 1

BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 9CA , additional homework tip 1

Figure 1

The function for the distance travelled by the traveller is $y=D(x)$ .

Calculation:

Consider the function $D(2)$ .

From the graph the function $D(2)$ shows that the distance and the time have a liner relation at $D(2)$ and at $D(2)$ the distance travelled by the traveller is 500 units.

(b)

To Find: The solution to determine the solution of the equation $D(x)=3500$ and explain its relevance.

The solution is $D(15)=3500$ .

Consider the given function $D(x)=3500$ .

Consider the given function is $y=D(x)$ .

Then at $y=35000$ the time is $x=15$ and the required solution is,

$D(15)=3500$

(c)

To Find: The time for which the traveller has to wait for the shuttle bus.

The wait time of the traveller is $15 min$ .

The graph shows that the time taken by the traveller to reach the shuttle is of $x=15$ minute.

(d)

To Find: The distance travelled by the traveller on the shuttle bus.

The distance travelled by the traveller on the shuttle bus is not determined from the graph.

From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet.

(e)

To Find: The total distance that the traveller walks before and after riding the shuttle bus.

The total distance travelled is $5508$ .

Consider the distance from the origin to the first point $(4,1000)$ is,

$d1=(4−0)2+(1000−0)2=1000$

Consider the distance from $(4,1000)$ to the first point $(12,1000)$ is,

$d2=(12−4)2+(1000−1000)2=8$

Consider the distance from $(12,1000)$ to the first point $(13,3000)$ is,

$d3=(3000−1000)2+(13−12)2=2000$

Consider the distance from $(13,3000)$ to the first point $(13,3500)$ is,

$d3=(15−12)2+(3500−1000)2=2500$

Thus, the total distance travelled by the traveller is,

$d=1000+8+2000+2500=5508$

Explanation of Solution

Given:

The given diagram is shown in Figure 1

BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 9CA , additional homework tip 2

Figure 1

The function for the distance travelled by the traveller is $y=D(x)$ .

Calculation:

Consider the function $D(2)$ .

From the graph the function $D(2)$ shows that the distance and the time have a liner relation at $D(2)$ and at $D(2)$ the distance travelled by the traveller is 500 units.

(b)

To determine

To Find: The solution to determine the solution of the equation $D(x)=3500$ and explain its relevance.

(b)

Expert Solution

Answer to Problem 9CA

The solution is $D(15)=3500$ .

Consider the given function $D(x)=3500$ .

Consider the given function is $y=D(x)$ .

Then at $y=35000$ the time is $x=15$ and the required solution is,

$D(15)=3500$

(c)

To Find: The time for which the traveller has to wait for the shuttle bus.

The wait time of the traveller is $15 min$ .

The graph shows that the time taken by the traveller to reach the shuttle is of $x=15$ minute.

(d)

To Find: The distance travelled by the traveller on the shuttle bus.

The distance travelled by the traveller on the shuttle bus is not determined from the graph.

From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet.

(e)

To Find: The total distance that the traveller walks before and after riding the shuttle bus.

The total distance travelled is $5508$ .

Consider the distance from the origin to the first point $(4,1000)$ is,

$d1=(4−0)2+(1000−0)2=1000$

Consider the distance from $(4,1000)$ to the first point $(12,1000)$ is,

$d2=(12−4)2+(1000−1000)2=8$

Consider the distance from $(12,1000)$ to the first point $(13,3000)$ is,

$d3=(3000−1000)2+(13−12)2=2000$

Consider the distance from $(13,3000)$ to the first point $(13,3500)$ is,

$d3=(15−12)2+(3500−1000)2=2500$

Thus, the total distance travelled by the traveller is,

$d=1000+8+2000+2500=5508$

Explanation of Solution

Consider the given function $D(x)=3500$ .

Consider the given function is $y=D(x)$ .

Then at $y=35000$ the time is $x=15$ and the required solution is,

$D(15)=3500$

(c)

To determine

To Find: The time for which the traveller has to wait for the shuttle bus.

(c)

Expert Solution

Answer to Problem 9CA

The wait time of the traveller is $15 min$ .

The graph shows that the time taken by the traveller to reach the shuttle is of $x=15$ minute.

(d)

To Find: The distance travelled by the traveller on the shuttle bus.

The distance travelled by the traveller on the shuttle bus is not determined from the graph.

From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet.

(e)

To Find: The total distance that the traveller walks before and after riding the shuttle bus.

The total distance travelled is $5508$ .

Consider the distance from the origin to the first point $(4,1000)$ is,

$d1=(4−0)2+(1000−0)2=1000$

Consider the distance from $(4,1000)$ to the first point $(12,1000)$ is,

$d2=(12−4)2+(1000−1000)2=8$

Consider the distance from $(12,1000)$ to the first point $(13,3000)$ is,

$d3=(3000−1000)2+(13−12)2=2000$

Consider the distance from $(13,3000)$ to the first point $(13,3500)$ is,

$d3=(15−12)2+(3500−1000)2=2500$

Thus, the total distance travelled by the traveller is,

$d=1000+8+2000+2500=5508$

Explanation of Solution

The graph shows that the time taken by the traveller to reach the shuttle is of $x=15$ minute.

(d)

To determine

To Find: The distance travelled by the traveller on the shuttle bus.

(d)

Expert Solution

Answer to Problem 9CA

The distance travelled by the traveller on the shuttle bus is not determined from the graph.

From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet.

(e)

To Find: The total distance that the traveller walks before and after riding the shuttle bus.

The total distance travelled is $5508$ .

Consider the distance from the origin to the first point $(4,1000)$ is,

$d1=(4−0)2+(1000−0)2=1000$

Consider the distance from $(4,1000)$ to the first point $(12,1000)$ is,

$d2=(12−4)2+(1000−1000)2=8$

Consider the distance from $(12,1000)$ to the first point $(13,3000)$ is,

$d3=(3000−1000)2+(13−12)2=2000$

Consider the distance from $(13,3000)$ to the first point $(13,3500)$ is,

$d3=(15−12)2+(3500−1000)2=2500$

Thus, the total distance travelled by the traveller is,

$d=1000+8+2000+2500=5508$

Explanation of Solution

From the graph the distance travelled by the rider on the shuttle bus is not determined as the graph shows the distance travelled by the traveller to reach the bus in feet.

(e)

To determine

To Find: The total distance that the traveller walks before and after riding the shuttle bus.

(e)

Expert Solution

Answer to Problem 9CA

The total distance travelled is $5508$ .

Consider the distance from the origin to the first point $(4,1000)$ is,

$d1=(4−0)2+(1000−0)2=1000$

Consider the distance from $(4,1000)$ to the first point $(12,1000)$ is,

$d2=(12−4)2+(1000−1000)2=8$

Consider the distance from $(12,1000)$ to the first point $(13,3000)$ is,

$d3=(3000−1000)2+(13−12)2=2000$

Consider the distance from $(13,3000)$ to the first point $(13,3500)$ is,

$d3=(15−12)2+(3500−1000)2=2500$

Thus, the total distance travelled by the traveller is,

$d=1000+8+2000+2500=5508$

Explanation of Solution

Consider the distance from the origin to the first point $(4,1000)$ is,

$d1=(4−0)2+(1000−0)2=1000$

Consider the distance from $(4,1000)$ to the first point $(12,1000)$ is,

$d2=(12−4)2+(1000−1000)2=8$

Consider the distance from $(12,1000)$ to the first point $(13,3000)$ is,

$d3=(3000−1000)2+(13−12)2=2000$

Consider the distance from $(13,3000)$ to the first point $(13,3500)$ is,

$d3=(15−12)2+(3500−1000)2=2500$

Thus, the total distance travelled by the traveller is,

$d=1000+8+2000+2500=5508$

Chapter 7, Problem 8CA

Chapter 8.1, Problem 1E

Chapter 7 Solutions

BIG IDEAS MATH Integrated Math 1: Student Edition 2016

Ch. 7.1 - Prob. 1E Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E Ch. 7.1 - Prob. 9E Ch. 7.1 - Prob. 10E

Ch. 7.1 - Prob. 11E Ch. 7.1 - Prob. 12E Ch. 7.1 - Prob. 13E Ch. 7.1 - Prob. 14E Ch. 7.1 - Prob. 15E Ch. 7.1 - Prob. 16E Ch. 7.1 - Prob. 17E Ch. 7.1 - Prob. 18E Ch. 7.1 - Prob. 19E Ch. 7.1 - Prob. 20E Ch. 7.1 - Prob. 21E Ch. 7.1 - Prob. 22E Ch. 7.1 - Prob. 23E Ch. 7.1 - Prob. 24E Ch. 7.1 - Prob. 25E Ch. 7.1 - Prob. 26E Ch. 7.1 - Prob. 27E Ch. 7.1 - Prob. 28E Ch. 7.1 - Prob. 29E Ch. 7.1 - Prob. 30E Ch. 7.1 - Prob. 31E Ch. 7.1 - Prob. 32E Ch. 7.1 - Prob. 33E Ch. 7.1 - Prob. 34E Ch. 7.1 - Prob. 35E Ch. 7.1 - Prob. 36E Ch. 7.1 - Prob. 37E Ch. 7.1 - Prob. 38E Ch. 7.1 - Prob. 39E Ch. 7.1 - Prob. 40E Ch. 7.1 - Prob. 41E Ch. 7.1 - Prob. 42E Ch. 7.1 - Prob. 43E Ch. 7.1 - Prob. 44E Ch. 7.1 - Prob. 45E Ch. 7.1 - Prob. 46E Ch. 7.1 - Prob. 47E Ch. 7.2 - Prob. 1E Ch. 7.2 - Prob. 2E Ch. 7.2 - Prob. 3E Ch. 7.2 - Prob. 4E Ch. 7.2 - Prob. 5E Ch. 7.2 - Prob. 6E Ch. 7.2 - Prob. 7E Ch. 7.2 - Prob. 8E Ch. 7.2 - Prob. 9E Ch. 7.2 - Prob. 10E Ch. 7.2 - Prob. 11E Ch. 7.2 - Prob. 12E Ch. 7.2 - Prob. 13E Ch. 7.2 - Prob. 14E Ch. 7.2 - Prob. 15E Ch. 7.2 - Prob. 16E Ch. 7.2 - Prob. 17E Ch. 7.2 - Prob. 18E Ch. 7.2 - Prob. 19E Ch. 7.2 - Prob. 20E Ch. 7.2 - Prob. 21E Ch. 7.2 - Prob. 22E Ch. 7.2 - Prob. 23E Ch. 7.2 - Prob. 24E Ch. 7.2 - Prob. 25E Ch. 7.2 - Prob. 26E Ch. 7.2 - Prob. 27E Ch. 7.3 - Prob. 1E Ch. 7.3 - Prob. 2E Ch. 7.3 - Prob. 3E Ch. 7.3 - Prob. 4E Ch. 7.3 - Prob. 5E Ch. 7.3 - Prob. 6E Ch. 7.3 - Prob. 7E Ch. 7.3 - Prob. 8E Ch. 7.3 - Prob. 9E Ch. 7.3 - Prob. 10E Ch. 7.3 - Prob. 11E Ch. 7.3 - Prob. 12E Ch. 7.3 - Prob. 13E Ch. 7.3 - Prob. 14E Ch. 7.3 - Prob. 15E Ch. 7.3 - Prob. 16E Ch. 7.3 - Prob. 17E Ch. 7.3 - Prob. 18E Ch. 7.3 - Prob. 19E Ch. 7.3 - Prob. 20E Ch. 7.3 - Prob. 21E Ch. 7.3 - Prob. 22E Ch. 7.3 - Prob. 23E Ch. 7.3 - Prob. 24E Ch. 7.3 - Prob. 25E Ch. 7.3 - Prob. 26E Ch. 7.3 - Prob. 27E Ch. 7.3 - Prob. 28E Ch. 7.3 - Prob. 1Q Ch. 7.3 - Prob. 2Q Ch. 7.3 - Prob. 3Q Ch. 7.3 - Prob. 4Q Ch. 7.3 - Prob. 5Q Ch. 7.3 - Prob. 6Q Ch. 7.3 - Prob. 7Q Ch. 7.3 - Prob. 8Q Ch. 7.3 - Prob. 9Q Ch. 7.4 - Prob. 1E Ch. 7.4 - Prob. 2E Ch. 7.4 - Prob. 3E Ch. 7.4 - Prob. 4E Ch. 7.4 - Prob. 5E Ch. 7.4 - Prob. 6E Ch. 7.4 - Prob. 7E Ch. 7.4 - Prob. 8E Ch. 7.4 - Prob. 9E Ch. 7.4 - Prob. 10E Ch. 7.4 - Prob. 11E Ch. 7.4 - Prob. 12E Ch. 7.4 - Prob. 13E Ch. 7.4 - Prob. 14E Ch. 7.4 - Prob. 15E Ch. 7.4 - Prob. 16E Ch. 7.4 - Prob. 17E Ch. 7.4 - Prob. 18E Ch. 7.4 - Prob. 19E Ch. 7.4 - Prob. 20E Ch. 7.4 - Prob. 21E Ch. 7.4 - Prob. 22E Ch. 7.4 - Prob. 23E Ch. 7.4 - Prob. 24E Ch. 7.4 - Prob. 25E Ch. 7.4 - Prob. 26E Ch. 7.4 - Prob. 27E Ch. 7.4 - Prob. 28E Ch. 7.4 - Prob. 29E Ch. 7.4 - Prob. 30E Ch. 7.4 - Prob. 31E Ch. 7.4 - Prob. 32E Ch. 7.4 - Prob. 33E Ch. 7.4 - Prob. 34E Ch. 7.5 - Prob. 1E Ch. 7.5 - Prob. 2E Ch. 7.5 - Prob. 3E Ch. 7.5 - Prob. 4E Ch. 7.5 - Prob. 5E Ch. 7.5 - Prob. 6E Ch. 7.5 - Prob. 7E Ch. 7.5 - Prob. 8E Ch. 7.5 - Prob. 9E Ch. 7.5 - Prob. 10E Ch. 7.5 - Prob. 11E Ch. 7.5 - Prob. 12E Ch. 7.5 - Prob. 13E Ch. 7.5 - Prob. 14E Ch. 7.5 - Prob. 15E Ch. 7.5 - Prob. 16E Ch. 7.5 - Prob. 17E Ch. 7.5 - Prob. 18E Ch. 7.5 - Prob. 19E Ch. 7.5 - Prob. 20E Ch. 7.5 - Prob. 21E Ch. 7.5 - Prob. 22E Ch. 7.5 - Prob. 23E Ch. 7.5 - Prob. 24E Ch. 7.5 - Prob. 25E Ch. 7.5 - Prob. 26E Ch. 7.5 - Prob. 27E Ch. 7.5 - Prob. 28E Ch. 7.5 - Prob. 29E Ch. 7.5 - Prob. 30E Ch. 7.5 - Prob. 31E Ch. 7.5 - Prob. 32E Ch. 7.5 - Prob. 33E Ch. 7 - Prob. 1CR Ch. 7 - Prob. 2CR Ch. 7 - Prob. 3CR Ch. 7 - Prob. 4CR Ch. 7 - Prob. 5CR Ch. 7 - Prob. 6CR Ch. 7 - Prob. 7CR Ch. 7 - Prob. 8CR Ch. 7 - Prob. 9CR Ch. 7 - Prob. 10CR Ch. 7 - Prob. 11CR Ch. 7 - Prob. 12CR Ch. 7 - Prob. 13CR Ch. 7 - Prob. 14CR Ch. 7 - Prob. 15CR Ch. 7 - Prob. 1CT Ch. 7 - Prob. 2CT Ch. 7 - Prob. 3CT Ch. 7 - Prob. 4CT Ch. 7 - Prob. 5CT Ch. 7 - Prob. 6CT Ch. 7 - Prob. 7CT Ch. 7 - Prob. 8CT Ch. 7 - Prob. 9CT Ch. 7 - Prob. 10CT Ch. 7 - Prob. 1CA Ch. 7 - Prob. 2CA Ch. 7 - Prob. 3CA Ch. 7 - Prob. 4CA Ch. 7 - Prob. 5CA Ch. 7 - Prob. 6CA Ch. 7 - Prob. 7CA Ch. 7 - Prob. 8CA Ch. 7 - Prob. 9CA

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