BIG IDEAS MATH Integrated Math 1: Student Edition 2016
BIG IDEAS MATH Integrated Math 1: Student Edition 2016
16th Edition
ISBN: 9781680331127
Author: HOUGHTON MIFFLIN HARCOURT
Publisher: Houghton Mifflin Harcourt
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Chapter 7, Problem 3CA

(a)

To determine

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

(a)

Expert Solution
Check Mark

Answer to Problem 3CA

The shape is skewed to the right, the majority of the distribution to the left.

Given:

The given diagram is shown in Figure 1

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  1

Figure 1

Calculation:

From figure 1 the majority of the data is on the left side of the plot. Since, the right whisker is on the longer on the left whisker this shows that the distribution is skewed on the right and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(b)

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

The shape is skewed to the left, the majority of the distribution to the right.

Given:

The given diagram is shown in Figure 2

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  2

Figure 2

Calculation:

From figure 1 the majority of the data is on the right side of the plot. Since, the left whisker is on the longer on the right whisker this shows that the distribution is skewed on the left and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(c)

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

The shape is skewed to the left, the majority of the distribution to the right.

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  3

Figure 3

Calculation:

From figure 1 the majority of the data is on the right side of the plot. Since, the left whisker is on the longer on the right whisker this shows that the distribution is skewed on the left and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(d)

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

The shape is skewed to the right, the majority of the distribution to the left.

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  4

Figure 3

Calculation:

From figure 1 the majority of the data is on the left side of the plot. Since, the right whisker is on the longer on the left whisker this shows that the distribution is skewed on the right and the median is used to describe the centre and use the and use the five number summary to determine the variation.

Explanation of Solution

Given:

The given diagram is shown in Figure 1

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  5

Figure 1

Calculation:

From figure 1 the majority of the data is on the left side of the plot. Since, the right whisker is on the longer on the left whisker this shows that the distribution is skewed on the right and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(b)

To determine

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

(b)

Expert Solution
Check Mark

Answer to Problem 3CA

The shape is skewed to the left, the majority of the distribution to the right.

Given:

The given diagram is shown in Figure 2

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  6

Figure 2

Calculation:

From figure 1 the majority of the data is on the right side of the plot. Since, the left whisker is on the longer on the right whisker this shows that the distribution is skewed on the left and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(c)

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

The shape is skewed to the left, the majority of the distribution to the right.

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  7

Figure 3

Calculation:

From figure 1 the majority of the data is on the right side of the plot. Since, the left whisker is on the longer on the right whisker this shows that the distribution is skewed on the left and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(d)

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

The shape is skewed to the right, the majority of the distribution to the left.

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  8

Figure 3

Calculation:

From figure 1 the majority of the data is on the left side of the plot. Since, the right whisker is on the longer on the left whisker this shows that the distribution is skewed on the right and the median is used to describe the centre and use the and use the five number summary to determine the variation.

Explanation of Solution

Given:

The given diagram is shown in Figure 2

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  9

Figure 2

Calculation:

From figure 1 the majority of the data is on the right side of the plot. Since, the left whisker is on the longer on the right whisker this shows that the distribution is skewed on the left and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(c)

To determine

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

(c)

Expert Solution
Check Mark

Answer to Problem 3CA

The shape is skewed to the left, the majority of the distribution to the right.

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  10

Figure 3

Calculation:

From figure 1 the majority of the data is on the right side of the plot. Since, the left whisker is on the longer on the right whisker this shows that the distribution is skewed on the left and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(d)

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

The shape is skewed to the right, the majority of the distribution to the left.

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  11

Figure 3

Calculation:

From figure 1 the majority of the data is on the left side of the plot. Since, the right whisker is on the longer on the left whisker this shows that the distribution is skewed on the right and the median is used to describe the centre and use the and use the five number summary to determine the variation.

Explanation of Solution

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  12

Figure 3

Calculation:

From figure 1 the majority of the data is on the right side of the plot. Since, the left whisker is on the longer on the right whisker this shows that the distribution is skewed on the left and the median is used to describe the centre and use the and use the five number summary to determine the variation.

(d)

To determine

To Find: The classification of the shape of the distribution, or symmetric, skewed left or skewed right.

(d)

Expert Solution
Check Mark

Answer to Problem 3CA

The shape is skewed to the right, the majority of the distribution to the left.

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  13

Figure 3

Calculation:

From figure 1 the majority of the data is on the left side of the plot. Since, the right whisker is on the longer on the left whisker this shows that the distribution is skewed on the right and the median is used to describe the centre and use the and use the five number summary to determine the variation.

Explanation of Solution

Given:

The given diagram is shown in Figure 3

  BIG IDEAS MATH Integrated Math 1: Student Edition 2016, Chapter 7, Problem 3CA , additional homework tip  14

Figure 3

Calculation:

From figure 1 the majority of the data is on the left side of the plot. Since, the right whisker is on the longer on the left whisker this shows that the distribution is skewed on the right and the median is used to describe the centre and use the and use the five number summary to determine the variation.

Chapter 7 Solutions

BIG IDEAS MATH Integrated Math 1: Student Edition 2016

Ch. 7.1 - Prob. 11ECh. 7.1 - Prob. 12ECh. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.1 - Prob. 33ECh. 7.1 - Prob. 34ECh. 7.1 - Prob. 35ECh. 7.1 - Prob. 36ECh. 7.1 - Prob. 37ECh. 7.1 - Prob. 38ECh. 7.1 - Prob. 39ECh. 7.1 - Prob. 40ECh. 7.1 - Prob. 41ECh. 7.1 - Prob. 42ECh. 7.1 - Prob. 43ECh. 7.1 - Prob. 44ECh. 7.1 - Prob. 45ECh. 7.1 - Prob. 46ECh. 7.1 - Prob. 47ECh. 7.2 - Prob. 1ECh. 7.2 - Prob. 2ECh. 7.2 - Prob. 3ECh. 7.2 - Prob. 4ECh. 7.2 - Prob. 5ECh. 7.2 - Prob. 6ECh. 7.2 - Prob. 7ECh. 7.2 - Prob. 8ECh. 7.2 - Prob. 9ECh. 7.2 - Prob. 10ECh. 7.2 - Prob. 11ECh. 7.2 - Prob. 12ECh. 7.2 - Prob. 13ECh. 7.2 - Prob. 14ECh. 7.2 - Prob. 15ECh. 7.2 - Prob. 16ECh. 7.2 - Prob. 17ECh. 7.2 - Prob. 18ECh. 7.2 - Prob. 19ECh. 7.2 - Prob. 20ECh. 7.2 - Prob. 21ECh. 7.2 - Prob. 22ECh. 7.2 - Prob. 23ECh. 7.2 - Prob. 24ECh. 7.2 - Prob. 25ECh. 7.2 - Prob. 26ECh. 7.2 - Prob. 27ECh. 7.3 - Prob. 1ECh. 7.3 - Prob. 2ECh. 7.3 - Prob. 3ECh. 7.3 - Prob. 4ECh. 7.3 - Prob. 5ECh. 7.3 - Prob. 6ECh. 7.3 - Prob. 7ECh. 7.3 - Prob. 8ECh. 7.3 - Prob. 9ECh. 7.3 - Prob. 10ECh. 7.3 - Prob. 11ECh. 7.3 - Prob. 12ECh. 7.3 - Prob. 13ECh. 7.3 - Prob. 14ECh. 7.3 - Prob. 15ECh. 7.3 - Prob. 16ECh. 7.3 - Prob. 17ECh. 7.3 - Prob. 18ECh. 7.3 - Prob. 19ECh. 7.3 - Prob. 20ECh. 7.3 - Prob. 21ECh. 7.3 - Prob. 22ECh. 7.3 - Prob. 23ECh. 7.3 - Prob. 24ECh. 7.3 - Prob. 25ECh. 7.3 - Prob. 26ECh. 7.3 - Prob. 27ECh. 7.3 - Prob. 28ECh. 7.3 - Prob. 1QCh. 7.3 - Prob. 2QCh. 7.3 - Prob. 3QCh. 7.3 - Prob. 4QCh. 7.3 - Prob. 5QCh. 7.3 - Prob. 6QCh. 7.3 - Prob. 7QCh. 7.3 - Prob. 8QCh. 7.3 - Prob. 9QCh. 7.4 - Prob. 1ECh. 7.4 - Prob. 2ECh. 7.4 - Prob. 3ECh. 7.4 - Prob. 4ECh. 7.4 - Prob. 5ECh. 7.4 - Prob. 6ECh. 7.4 - Prob. 7ECh. 7.4 - Prob. 8ECh. 7.4 - Prob. 9ECh. 7.4 - Prob. 10ECh. 7.4 - Prob. 11ECh. 7.4 - Prob. 12ECh. 7.4 - Prob. 13ECh. 7.4 - Prob. 14ECh. 7.4 - Prob. 15ECh. 7.4 - Prob. 16ECh. 7.4 - Prob. 17ECh. 7.4 - Prob. 18ECh. 7.4 - Prob. 19ECh. 7.4 - Prob. 20ECh. 7.4 - Prob. 21ECh. 7.4 - Prob. 22ECh. 7.4 - Prob. 23ECh. 7.4 - Prob. 24ECh. 7.4 - Prob. 25ECh. 7.4 - Prob. 26ECh. 7.4 - Prob. 27ECh. 7.4 - Prob. 28ECh. 7.4 - Prob. 29ECh. 7.4 - Prob. 30ECh. 7.4 - Prob. 31ECh. 7.4 - Prob. 32ECh. 7.4 - Prob. 33ECh. 7.4 - Prob. 34ECh. 7.5 - Prob. 1ECh. 7.5 - Prob. 2ECh. 7.5 - Prob. 3ECh. 7.5 - Prob. 4ECh. 7.5 - Prob. 5ECh. 7.5 - Prob. 6ECh. 7.5 - Prob. 7ECh. 7.5 - Prob. 8ECh. 7.5 - Prob. 9ECh. 7.5 - Prob. 10ECh. 7.5 - Prob. 11ECh. 7.5 - Prob. 12ECh. 7.5 - Prob. 13ECh. 7.5 - Prob. 14ECh. 7.5 - Prob. 15ECh. 7.5 - Prob. 16ECh. 7.5 - Prob. 17ECh. 7.5 - Prob. 18ECh. 7.5 - Prob. 19ECh. 7.5 - Prob. 20ECh. 7.5 - Prob. 21ECh. 7.5 - Prob. 22ECh. 7.5 - Prob. 23ECh. 7.5 - Prob. 24ECh. 7.5 - Prob. 25ECh. 7.5 - Prob. 26ECh. 7.5 - Prob. 27ECh. 7.5 - Prob. 28ECh. 7.5 - Prob. 29ECh. 7.5 - Prob. 30ECh. 7.5 - Prob. 31ECh. 7.5 - Prob. 32ECh. 7.5 - Prob. 33ECh. 7 - Prob. 1CRCh. 7 - Prob. 2CRCh. 7 - Prob. 3CRCh. 7 - Prob. 4CRCh. 7 - Prob. 5CRCh. 7 - Prob. 6CRCh. 7 - Prob. 7CRCh. 7 - Prob. 8CRCh. 7 - Prob. 9CRCh. 7 - Prob. 10CRCh. 7 - Prob. 11CRCh. 7 - Prob. 12CRCh. 7 - Prob. 13CRCh. 7 - Prob. 14CRCh. 7 - Prob. 15CRCh. 7 - Prob. 1CTCh. 7 - Prob. 2CTCh. 7 - Prob. 3CTCh. 7 - Prob. 4CTCh. 7 - Prob. 5CTCh. 7 - Prob. 6CTCh. 7 - Prob. 7CTCh. 7 - Prob. 8CTCh. 7 - Prob. 9CTCh. 7 - Prob. 10CTCh. 7 - Prob. 1CACh. 7 - Prob. 2CACh. 7 - Prob. 3CACh. 7 - Prob. 4CACh. 7 - Prob. 5CACh. 7 - Prob. 6CACh. 7 - Prob. 7CACh. 7 - Prob. 8CACh. 7 - Prob. 9CA
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