Explanation Given info: In a random sample of 300 parts, 12 were defective. That is, X = 12 and n = 300 . Calculation: The test hypotheses are given below: Null hypothesis: H 0 : p ≥ 0.08 ( or 8 % ) Alternative hypothesis: H 1 : p < 0.08 Verify the condition: Condition 1: n p 0 ≥ 10 n p 0 = 300 ( 0.08 ) = 24 ( > 10 ) Condition 2: n ( 1 − p 0 ) ≥ 10 n ( 1 − p 0 ) = 300 ( 1 − 0.08 ) = 276 ( > 10 ) Since both n p 0 and n ( 1 − p 0 ) are greater than 10, the z -test can be used

4th Edition

ISBN: 9780073401331

Author: William Navidi Prof.

Publisher: McGraw-Hill Education

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

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Chapter 6.3, Problem 8E

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Chapter 6.3, Problem 7E

Chapter 6.3, Problem 9E

Chapter 6 Solutions

Statistics for Engineers and Scientists

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Check whether there is evidence to conclude that the machine can be qualified or not.

Solution Summary: The author analyzes whether the machine can be qualified. In a random sample of 300 parts, 12 were defective.

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