Chapter 5, Problem 5G.20E

(a)

Interpretation Introduction

Interpretation:

The Gibbs free energy for the given reaction has to be calculated.

  ${\text{H}}_{\text{2}}\text{(g)}+{\text{I}}_2\text{(g)}\rightleftharpoons \text{2HI(g) K=54 at 700 K}$

Concept Introduction:

The Gibb’s free energy of a reaction can be calculated using the following expression,

  $\begin{array}{l}{\text{ΔG}}_{\text{r}}^{\text{°}}=-\text{RT}\text{lnK}\\ \\ \text{where,}\\ {\text{ΔG}}_{\text{r}}^{\text{°}}\text{=}\text{Standard}\text{Gibb's}\text{free}\text{energy}\\ \text{K}\text{=}\text{Equilibrium constant}\\ \text{T = Temperature}\\ \text{R = Gas constant}\end{array}$

(b)

Interpretation Introduction

Interpretation:

The Gibbs free energy for the given reaction has to be calculated.

  ${\text{Ag}}_{\text{2}}{\text{CrO}}_{\text{4}}\text{(s)}\rightleftharpoons {\text{2Ag}}^{+}{\text{(aq)+CeO}}_4{}^{2-}\text{(aq) K=1}\text{.1}\times {\text{10}}^{-12}\text{ at 298 K}$

Concept introduction:

Refer to part (a).