Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 4, Problem 4.9.4P
To determine
The radius of gyration
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Consider the truss shown in the figure. Determine the force in members ML, MC, and BC and state if these
members are in tension or compression. Show all your work. (lengths AB-BC=CD%3DE%3DEF%3FG=3m)
50 kN 50 kN 50 kN
N
ML K J IH
B CD E F
hod
18 m 6 @3 m
The maximum allowable tensile force in the members of
the truss is (Ft) max = 5.2 kN, and the maximum
allowable compressive force is (Fe) max = 3 kN. Take
d = 2 m. (Figure 1)
шах
Figure 1
of 1
d
E
d
d/2
C
d/2
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analysis the truss using method of joints to find the internal forces. by steps please.
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
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- my answer is wrong please help me solvearrow_forwardUsing Method of Joints. Solve the Truss Problem. Round off your answer into two decimal places.Eliminate all the zero-force members before analyzing. Find: BE, BC, EF ,DE, FG forces in kN.arrow_forwardThis is one question. Please answer all parts and doesn’t break honor code!arrow_forward
- The armor shown supports loads of 3 KN. The horizontal elements are 713cm long each. Determine the axial force on element FE; Use the section method to determine the axial force in the FE element and check your result with the nodal or joint method. INFO: Y= 100 cmarrow_forwardNeed answer fast.arrow_forwardShow complete free body diagram, and complete solution.arrow_forward
- A truss is loaded as shown in the figure. The cross- sectional area of each member is 500 mm^2. Hint: Use method of section in getting the axial forces. Use the guide cutting sections. L-6 m+6m- N 25 kN 8 m 50 kN - a 8 m 50 kN 8 m 50 kN 8 m B. 9. Find the axial stress in member HK O 35.34 MPa O 31.12 MPa O 33.34 MPa O 37.12 MPa Question 10 10. Find the axial stress in member HJ. O 125 MPa О 123 МPа O 127 MPa O 129 MPaarrow_forwardConsider the truss shown in (Figure 1). Set P₁ = 8 kN, P₂ = 10 kN, and P3 = 6 kN. Figure E ZA B C 3m P₁ P3 3m < 1 of 1 P₂ -3m- 3m D. ✓ Correct ▼ Part D Determine the force in member BF of the truss and state if this member is in tension or compression. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. FBF = 7.67 HA kN Submit Previous Answers Request Answer ? Review * Incorrect; Try Again; 5 attempts remainingarrow_forwardThe members of the truss are 25mmx50mm in cross section. Determine the maximum load P that can be applied so that the stresses will not exceed 100 MPa in tension or 70 MPa in compression. See figure 101. Figure 101 A 0 2m P B 2.5m 1.5m Carrow_forward
- By internal couple method, what is the maximum stress on the steel side of the transformed section? Consider the beam section shown below. Express your final answer in ksi and use two decimal places. 24" 14 As=3 IN. ² SECTION E (STEEL) = 29 x 10³ K.5.1. E (CONC) = 3.2 x 10³ K.5.1. M = 9 ALLOW. f(STEEL) = 20 K.5.1. ALLOW. f (CONC)= 1.35 K.S.I.arrow_forwardPlease Asaparrow_forward1.8-12 A plane truss is subjected to loads 2P and P at joints B and C, respectively, as shown in the figure part a. The truss bars are made of two L102 x 76 x 6.4 steel angles [see Table F-5(b): cross-sectional area of the two angles, A = 2180 mm², figure part b] having an ultimate stress in tension equal to 390 MPa. The angles are con- nected to an 12 mm-thick gusset plate at C (figure part c) with 16-mm diameter rivets; assume each rivet transfers an equal share of the member force to the gusset plate. The ultimate stresses in shear and bearing for the rivet steel are 190 MPa and 550 MPa, respectively. Determine the allowable load Pallow if a safety factor of 2.5 is desired with respect to the ultimate load that can be carried. (Consider tension in the bars, shear in the riv- ets, bearing between the rivets and the bars, and also bear- ing between the rivets and the gusset plate. Disregard friction between the plates and the weight of the truss itself.)arrow_forward
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