Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.6.2P
To determine
(a)
A W12 section of A992 steel using column load tables.
To determine
(b)
A W18 section of A592 steel using trial and error method.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar
was initially horizontal, and the rods were stress-free before the load P= 20 KN is applied.
Sleel
E-200 GPa
A-400mm
L1 m
2.0 m
0.6 m
1.5m
P-20 KN
Aluminum
E70 GPa
A-900mm
L-1.5 m
1. Axial load at steel rod in kN?
2. Axial stress at steel rod in MPa?
3. Axial deformation of aluminum rod in mm?
4. Axial deformation of steel rod in mm?
5. Axial Load at aluminum rod in kN?
The beam shown in Figure is a two-span beam with a pin (hinge) in the center of the left span,making the beam statically determinate. There is continuous lateral support. The concentratedloads are service live loads. Determine whether a W12 × 79 of A992 steel is adequate.a. Use LRFD.b. Use ASD.
How much service live load, in kN/m, can be supported?
The member weight is the only dead load. The axial
compressive load consists of a service dead load of 45 kN
and a service live load of 90 kN. Do not consider moment
amplification. Use NSCP 2015.
a.
b.
LRFD.
ASD.
wt A
kN/m mm²
W460x144 1.41 18400 472 13.6 283
SECTION
tw
bf
tf
Ix
Sx
mm mm mm mm³
22.2 726 3080
mm mm
mm
199
6.2m
W460x144
Sy Ty Zx
ly
mm mm³ mm
83.6 591
Zy J
Cw
mmº
mm³
mm³
67.4 3450 906 2440 4230
mmª
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
Knowledge Booster
Similar questions
- Compute the nominal shear strength of an M107.5 of A572 Grad 65 steel.arrow_forwardThe light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P 20 KN is applied. Sheel E200 GPa L-1 m 2.0 m 0.6m 1.5m P-20 KN Aluminum E-70 GPa A=900mm L-1.5 m What is the axial load at steel rod in KN?arrow_forwardA built-up section was made using PL414x12mm thk plates as shown in the figure below. It is pinned at both ends with additional support against weak axis at middle point. Assume A50 steel. PL414x12 DO Section W16x67 L x-axis a) Calculate moment of inertia at both axes in mm*. b) Determine the design compressive strength in kN if L-3m. c) Find the design compressive strength in kN if L=18m. Elevation y-axisarrow_forward
- The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P = 20 KN is applied. Steel E200 Gra A-600mm L-I m 2.0 m 0.6m 1.5 m D. V P-20 KN Aluminum E-70 GPa A-900mm L-1.5 m What is the axial load at aluminum rod in KN?arrow_forwardFrom the Truss member shown, design all the tension members for ASD and LRFD, if the connection for the angle bars are shown. Use A36 STEEL. 100 mm 150 mm 2.5 m B SERVICE DEAD LOAD =300 KN SERVICE LIVE LOAD = 200 KN 2 m 2 m 2 m 2 marrow_forwardA bolted connection shown is bolted with a A-325 bolts with an allowable shearing stress of 207 MPa. A-36 steel is used. The applied force "T" is equally divided among the bolts. Assume bolt hole diameter to be 3 mm bigger than bolt diameter. Diameter of bolt is 20 mm. T/2 T T/2 10 mr 10 mm T/2 300 mm T/2 Determine the capacity of the connection if shearing governs in kN. A 1548.58 B 1170.56 1290.62 D 1439.25 000arrow_forward
- 1. A steel column 10 m long is fabricated from a cover plate and C section arranged as shown. Determine the safe compressive load. Fy = 248 MPa, E= 200 GPa. Use AISC/NSCP Specs. 450 mm -cover plate 'I 12 mm y2 IP d2 10 m C 310 x 37 A = 4720 mm? d = 305 mm bf = 77 mm tf = 12.7 mm tw = 9.8 mm C 310 X 37 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. tw d=305- Ix = 59.9x10° mm ly = 1.85x10° mm x = 17.1 mm x=17.1arrow_forwardA beam is connected to a column with 3⁄4inchdiameter, Group A slipcritical bolts, as shown in Figure . A992 steel is used for the beam and column, and A36 steel is used for the angles. The force R is the beam reaction. Based on the strength of the 10 angletocolumn bolts, determine: a. The maximum available factored load reaction, Ru, for LRFD. b. The maximum available service load reaction, Ra, for ASD.arrow_forwardThe beam shown is simply supported and has lateral support only at its ends. The only service dead load is the weight of the beam. Determine whether it is satisfactory for the load shown. A992 steel (E= 345 MPa and F= 450 MPa) is used, and the 30 KN/m is a service live load. Use LRFD 30 KN/m WiL = 30 KN/m W16x 40 -Centroid W16 x 40 3marrow_forward
- A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltas shown below. Use A36 steel with Fy=36 ksi and Fu=58 ksi Determine the Yielding Capacity of the section based on LRFD (kips) Determine the Tensile Rupture capacity of the section based on LRFD Determine the Demand to Governing Capacity Ratio (based on yielding and rupture only) if the Demand load carried by the section are DL=200 kips LL=400 kips use LRFDarrow_forwardQuestion 1 Check that the medium-term load of 38 kN applied to the spaced column shown in below complies with the design requirements of BS 5268-2. The column consists of two 38 x 150 C22 timbers 76 mm apart. All joints are glued and intermediate packs are 250 mm long. suitable connection #### x ->89² 6:38. Y T -end blocking AP 100 intermediate blocking L₂ 1₁ x W L W EFH 400 m 38kN medium term load -ICHICHID -200 600 600 600 600 600 600 200 38kN medium term loadarrow_forwardDesign a column base plate for a W10x33 column supporting a service dead load of 20 kips and a service live load of 50 kips. The column is supported by a 12-inch × 12-inch concrete pier. Use A36 steel and f! 3 %3D ksi. a. Use LRFD. b. Use ASD.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning