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The frame shown in Figure P4.7-8 is unbraced, and bending is about the x-axis of the members. All beams are
a. Determine the effective length factor
b. Determine the effective length factor
c. If
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Chapter 4 Solutions
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- A truss is subjected to loads as shown. Assume AE is constant and use virtual work method for deflection of truss. 4m 120 KN B A TINT 3m EA = constant E = 200 G Pa 2 A = 1,500 mm Find the vertical deflection at B in mmarrow_forwardDetermine the force in members FG, BF, and CE of the truss shown in the figure below. Let P = 29 kN. NOTE: If your answer is a compressive force then just put a negative sign. If your answer is a tensile force then just type the answer directly. (ALSO, DON'T FORGET THE UNITS) 2P 2P 30° 600 60° 60 60° 30 B. 3P 4m 4m 4m Solve the force in member FG. Solve the force in member BF. Solve the force in member CE. Q =' 21 IIarrow_forwardThe rigid bar BDE is supported by two links AB and CD. Link AB is made of aluminum (E = 70 GPa) and has a cross-sectional area of 512 mm2; link CE is made of steel (E = 200 GPa) and has a cross-sectional area of 643 mm2. For the 32 kN force shown, determine the deflection of D (mm) *Note: Negative if compression and positive if tension. Also, the final answer should have two decimal places.arrow_forward
- The space truss shown below is made of steel (E = 30×10 psi). The cross- sectional area of each member is 2.0 in² find the maximum deflection, the maximum and minimum stresses and forces in the truss, and the reaction forces at supports. Verify your results. If the second moment of π᾽ΕΙ inertia I = 0.9 in, do you think that buckling will occur? (Per hind: apply constraints at Joint A, B, and C. Coordinate of joints are G (0,0,144) in, A(24,-36,0) in, B(24,36,0) in, C(-48,36,0) in. (units: use lb, in) 1² X {-500k) Ib (200) Ib E с 6 ft 6 ft 4 ft ·),arrow_forwardA pin-connected structure is supported and loaded as shown. Member ABCD is rigid and is horizontal before the load Pis applied. Bars (1) and (2) are both made from steel [E = 29000 ksi] and both have a cross-sectional area of 1.15 in.?. Assume L1=73 in., L2=118 in., a=54 in., b=100 in., and c=48 in. If the normal stress in each steel bar must be limited to 15.3 ksi, determine the maximum load P that may be applied to the rigid bar. (2) (1) L2 A В C D a b V Parrow_forwardThe cantilever beam consists of a rectangular structural steel tube shape [E = 29,000 ksi; /= 1780 in.4]. For the loading shown, determine: (a) the beam deflection at point A. (b) the beam deflection at point B. Assume MA = 170 kip-ft, P = 29 kips, LAB = 5.7 ft, LBC = 8.6 ft. MA LAB P B LBCarrow_forward
- For the truss shown, determine the safe value of P if the allowable stress in tension is 140 MPa in tension and 95 MPa in compression. The cross-sectional area of vertical and horizontal members is 1500 mm2 while that of diagonal members is 805 mm2. q = 5 t = 0arrow_forwardof A square plate (a x a) is a fixed supported on all four edges and carries a uniform load a (per nit area). The equation for deflection is: V"w=q/D where D is flexural rigidity. Take a h=Ax = Ay =-. Find the deflection at internal nodes. %3D 4arrow_forwardAs shown in the figure, aluminum, E= 70GPa links (1) and (2) support rigid beam ABC. Link (1) has a cross-sectional area of 320mm² and link (2) has a cross-sectional area of 480mm². For an applied load of P= 58kN, determine the rigid beam deflection at point B. (2) 4,000 mm (1) 2,500 mm B 1,400 mm 800 mmarrow_forward
- The cantilever beam consists of a rectangular structural steel tube shape [E = 29,000 ksi; / = 1930 in.41. For the loading shown, determine: (a) the beam deflection at point A (b) the beam deflection at point B. Assume MA = 250 kip-ft, P = 29 kips, LAB = 4.9 ft, LBc = 7.4 ft.arrow_forwardThe system shown below is comprised of the cantilever beam AB and the supporting truss BC connected to each other by a pin joint at B. Using the Stiffness Method compute the displacements and internal forces in the system under the applied load. Use a frame element to model member AB to account for axial stiffness. Take E = 250 GPa, IAB = 2x10 mm4, AAB = 2x104 mm², Aec = 1x10³ mm². A 80 KN 2 m * 4 m 6 m OBarrow_forwardFor the truss shown below determine the vertical displacement at joint A using the method of virtual work. In addition to the external loading, member ED is manufactured 0.5 inches too short. For all members: A = 2 in² and E = 29 x 10³ ksi. ED is 0.5 inches too short A 500 lb 8 ft E B 250 lb 8 ft pin pin с 8 ftarrow_forward
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