Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 3, Problem 9PDQ
When working out genetics problems in this and succeeding chapters, alwaysassumethatmembersof the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.
Which of Mendel's postulates can be demonstrated in the Now Solve This Problem 3-2 on p. 39 but not in Problem 3 above? Define this postulate.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
When working out genetics problems in this and succeeding chapters, always assume that members of the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.HOW DO WE KNOW? we focused on the Mendelian postulates, probability, and pedigree analysis. We also considered some of the methods and reasoning by which these ideas, concepts, and techniques were developed. On the basis of these discussions,
what answers would you propose to the followingquestion.
Question: Since experimental crosses are not performed in humans, how do we know how traits are inherited?
Required information
A single-factor cross is one in which the inheritance of only one character and its associated genotypes are followed.
Punnett squares are often used to predict the outcomes of simple genetic crosses. Based on Mendel's laws, the
genotypes of the parents can be used to predict the genes in their gametes and the resulting progeny. A Punnett square
enables you to predict the types of offspring the parents are expected to produce and in what proportions.
Sickle cell anemia is a recessive trait in humans. In a cross between two parents who are heterozygous for the gene, what are the gamete possibilities of the parer
Mother's gamete
possibilities
Father's gamete
possibilities
of 19
Show All
MacBook Air
田
Question: On the basis of Mendel's hypothesis and observations, predict the results from the following crosses in garden peas: (a) a tall (dominant and homozygous) variety crossed with a dwarf variety: (b) the progeny of (a) selfed; (c) the progeny from (a) crossed with the original tall parent; (d) the progeny from (a) crossed with the original dwarf-parent variety.
Chapter 3 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - CASE STUDY | To test or not to test Thomas first...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...
Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - Prob. 26PDQCh. 3 -
When working out genetics problems in this and...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- QUESTION 1 Exceptions to Mendel's Rules Matching. Match the exception to Mendel's rules with the example that illustrates it. human body shape is controlled by a number of genes children heterozygous for Tay-Sachs disease make about 50"% of v the normal healthy enzyme, homozygous recessive individuals make 0% and homozygous dominant individuals make 100% A. incomplete dominance diabetes, ultraviolet light, and alcoholism cause cataracts (cloudy v eyes) that are coded for by a dominant allele to develop earlier and B. codominance more severely C. epistasis a dominant allele codes for cataracts (cloudy eyes) but another allele affects how bad the cataract will be D. environmental effects on gene expression homozygous cattle are brown or white while heterozygotes have both brown and white hair E. pleiotropy F. polygenic men with the gene for goutare eight times more likely than women to develop a severe case G. sex linkage the human disease Marfan Syndrome results from a gene that affects…arrow_forwardNow cross two of the F₁ offspring. Parent 1 Gametes F2 Offspring Parent 2 Gametes 24. What is the phenotypic ratio in the F2 generation? 25. In the dihybrid cross you have considered two traits at a time. Although the number of traits has increased by one, what has happened to the number of possible phenotypes of offspring produced in the F2 generation? ni llit asa2013 bhidydenom sih at Simons 1:11 sabrax gatamearrow_forwardQUESTION 4 In Mendel's pea plants, round shape (R) is dominant to wrinkled shape (r), and yellow color (Y) is dominant to green color (y). The alleles for seed shape and seed color sort independently. In the parental generation, Mendel crossed a true-breeding round, yellow-seeded plant with a true-breeding wrinkled, green-seeded plant to create an F1 generation. He then crossed the F1 offspring to eachother to create the F2 generation. What is the probability Mendel would observe F2 plants with round and green seeds? O 3/16 O9/16 1/8 01/4 1/2 QUESTION 5 specific example of incomplete penetrance is the human bone disease osteogenesis imperfecta (OI). The majority of people with this disease have a dom utation in one of the hun nonce that produce hme 1 collagen COL1A1 or COL1A2 Raced on the DNA testing of a family with 15 membere amemhare he Save and Submit to save and submit. Click Save All Answers to save all answers. MacBook Airarrow_forward
- Question- 1. In onions, male sterility is due to the interaction of a chromosomal allele pair hh and “sterile” (S) cytoplasm. All other combinations (i.e. HH/Hh and “sterile” cytoplasm, HH/Hh or hh “fertile” (F) cytoplasm) result in male-fertile plants. The male-sterile trait is incorporated into inbred lines to produce hybrid F1 seed on a commercial scale.a) How would you perpetuate the male-sterile line? Show the cross.b) Briefly outline the method of producing hybrid seed (heterozygote) for the commercial crop. Show the cross.c) Does it matter whether the cytoplasm is fertile or sterile in the male-fertile inbred? Explain.arrow_forwardQUESTION 1 In pea plants, round (R) is dominant to wrinkled (r), yellow (Y) is dominant to green (y), and tall (T) is dominant to short (t). A homozygous round, heterozygous yellow, short pea plant is crossed with a wrinkled, heterozygous yellow, heterozygous tall plant. Show the branching diagram, along with the probabilities of all genotypes. What is the probability (show work) and phenotype of the following genotype: Rryytt. Attach Filearrow_forwardQuestion 6 Which of the Pedigree Diagrams below is most likely to show a family with Becker muscular dystrophy? B Afected female Normal fenale anecad sale Nermal maie KEY Homozygous Homazygous Heterozygous Heberozygous Wild Type Male Fumale Male Female Male Female Note: Completely red symbol denotes an individual exhibiting the phenotype of interest C OT 12 12 12 IV 1/4 14 Alfected 12. 1/2 Known camer A A B. A, 8.arrow_forward
- QUESTION 5. The pedigree below follows the appearance of a rare autosomal dominant condition resulting in malformation of limbs through a family. What is the penetrance of this trait? i.e., What is the ratio between the number of individuals in the pedigree who display the trait (numerator) and the number of individuals you know from the pedigree must have the trait-determining genotype (denominator)? Enter your answer in the form of a fraction without any spaces. e.g., If your answer is “one-fourth”, enter: 1/4arrow_forwardAnalysis of Autosomal Recessive and Dominant Traits In the following pedigree, assume that the father of the proband is homozygous for a rare trait. What pattern of inheritance is consistent with this pedigree? In particular, explain the phenotype of the proband.arrow_forwardMonohybrid Problems llustrating Codominamce 5. Another type of monohybrid inheritance involves the expression of both phenotypes in the heterozy- gous situation. This is called codominance. One well-known example of codominance occurs in the coat color of Shorthorn cattle. Those with reddish-gray roan coats are heterozygous (RR'), and result from a mating between a red (RR) Shorthorn and one that's white (R'R'). Roan cattle don't have roan-colored hairs, as would be expected with incom- plete dominance, but rather appear roan as a result of having both red and white hairs. Thus, the roan col- oration is not a consequence of pigments blending in each hair. Because the R and R' alleles are both fully expressed in the heterozygote, they are codominant. a. If a roan Shorthorn cow is mated with a white bull, what will be the genotypic and phenotypic ratios in the F, generation? genotypic ratio . phenotypic ratio b. List the parental genotypes of crosses that could produce at least some…arrow_forward
- QUESTION 6 In Drosophila, sepia eyes (se) and stubble bristles (sb) are recessive to the wildtype eyes and bristles (se* and sb+). A female heterozygous for both genes was test crossed to a male homozygous recessive for both genes. The progeny of this cross are given below: Phenotypes wildtype eyes and wildtype bristles (set, sbt) # of Progeny 334 widltype eyes and stubble bristles (set, sb) 162 sepia eyes and wildtype bristles (se, sb+) 158 sepia eyes and stubble bristles (se, sb) 346 What is the genetic distance (in map units) between these two genes? Are the alleles in the heterozygous female in the cis (coupling) or trans (repulsion) conformation? Are the two genes in this problem unlinked, completely linked or incompletely linked?arrow_forwardQuestion 1 The possession of one of two types of earlobes (hanging or attached) is sometimes used to study the inheritance of characteristics in humans. The pedigree shows the different types of earlobes present in three generations. KEY male with hanging earlobes II female with hanging earlobes male with attached earlobes female with attached earlobes III Discuss the type of inheritance shown in the pedigree. In your answer, include reference to the alleles involved using standard notation.arrow_forwardPrinciples of Heredity 667 Activity 1 Working Out Crosses Involving Dominant and Recessive Genes For each of the following crosses, draw your own Punnett square and use the technique outlined above to determine the genotypes and phenotypes of the pea plant offspring 2. Genotypes of parents: Tt (3) × Tt (Q) % of each genotype: 1. Genotypes of parents: Tt (3) × tt (9) % of each phenotype: % tall, % dwarf % of each genotype: 3. Genotypes of parents: TT (3) X Tt (2) % of each phenotype: % tall, % dwarf % of each genotype: % of each phenotype: % tall, % dwarf Incomplete Dominance uhot alleles exnress themselves in the offspring. The crosses arearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY