Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 3, Problem 22PDQ
When working out genetics problems in this and succeeding chapters, always assume that members of the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.
Which of Mendel's postulates are demonstrated by the pedigree in Problem 21? List and define these postulates.
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When working out genetics problems in this and succeeding chapters, always assume that members of the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.HOW DO WE KNOW? we focused on the Mendelian postulates, probability, and pedigree analysis. We also considered some of the methods and reasoning by which these ideas, concepts, and techniques were developed. On the basis of these discussions,
what answers would you propose to the followingquestion.
Question: Since experimental crosses are not performed in humans, how do we know how traits are inherited?
1:31
1 Drive
For each of the problems below, please make sure to...
Write a DETAILED KEY that explains all of your
symbols used.
Show your work on problems that ask. That means
make sure that you are showing at least one Punnett
square.
Interpret your answer. A Punnett square alone will
not suffice.
Indicate which types of problems or vocabulary are
difficult for you so that we can review them in
discussion.
Monohybrid cross: A single trait is crossed with only two
variations of the allele.
with
2.
In humans, brown eyes are usually dominant over
blue eyes. Suppose a blue-eyed man marries a
brown-eyed woman whose father was blue eyed.
What proportion of their children would you predict
would have blue eyes?
A brown-eyed man whose father was brown eyed
and whose mother was blue eyed married a blue
eyed woman whose father and mother were both
brown-eyed. The couple has a blue-eyed son. For
which of the individuals mentioned can you be sure
3.
of the genotypes? What are their genotypes?…
Question: On the basis of Mendel's hypothesis and observations, predict the results from the following crosses in garden peas: (a) a tall (dominant and homozygous) variety crossed with a dwarf variety: (b) the progeny of (a) selfed; (c) the progeny from (a) crossed with the original tall parent; (d) the progeny from (a) crossed with the original dwarf-parent variety.
Chapter 3 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - CASE STUDY | To test or not to test Thomas first...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...
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- Required information A single-factor cross is one in which the inheritance of only one character and its associated genotypes are followed. Punnett squares are often used to predict the outcomes of simple genetic crosses. Based on Mendel's laws, the genotypes of the parents can be used to predict the genes in their gametes and the resulting progeny. A Punnett square enables you to predict the types of offspring the parents are expected to produce and in what proportions. Sickle cell anemia is a recessive trait in humans. In a cross between two parents who are heterozygous for the gene, what are the gamete possibilities of the parer Mother's gamete possibilities Father's gamete possibilities of 19 Show All MacBook Air 田arrow_forwardQuestion: This is a normal 3 point test cross, except that instead of regular phenotypes, you are looking at DNA markers on a gel. One parent, according to the gel, is heterozygous at each marker. The other parent is homozygous for each marker. (Again, this means it is a test cross: AaEeHh x AAEEHH --but don't be confused by that, because these are not "dominant" and "recessive" per se; the phenotype is just a band on a gel). For each offspring, figure out its genotype (homozygous or heterozygous for each gene. Then, figure that one parent made only AEH gametes, so you can cross that out if it helps.) Then treat it pretty much the same as a 3 point test cross.arrow_forwardQuestion GROUP A: Genetics Problems In humans, red-green color blindness is caused by a recessive allele on the X chromosome. A male with normal vision and his color-blind wife have a child. If the child is male what is the probability that he will be color-blind? The female in the previous problem has a daughter that is color-blind. The husband claims that this cannot be his child. Can you support or refute his argument?arrow_forward
- Problem 4: Here are four human pedigrees. The black symbols represent an abnormal phenotype inherited in a simple Mendelian manner. 2 SODOCTO 566 7 588 166 560 a. For each pedigree, state whether the abnormal condition is dominant or recessive. Try to state the logic behind your answer. b. For each pedigree, describe the genotypes of as many persons as possible.arrow_forwardQUESTION 5. The pedigree below follows the appearance of a rare autosomal dominant condition resulting in malformation of limbs through a family. What is the penetrance of this trait? i.e., What is the ratio between the number of individuals in the pedigree who display the trait (numerator) and the number of individuals you know from the pedigree must have the trait-determining genotype (denominator)? Enter your answer in the form of a fraction without any spaces. e.g., If your answer is “one-fourth”, enter: 1/4arrow_forwardQUESTION 4 In Mendel's pea plants, round shape (R) is dominant to wrinkled shape (r), and yellow color (Y) is dominant to green color (y). The alleles for seed shape and seed color sort independently. In the parental generation, Mendel crossed a true-breeding round, yellow-seeded plant with a true-breeding wrinkled, green-seeded plant to create an F1 generation. He then crossed the F1 offspring to eachother to create the F2 generation. What is the probability Mendel would observe F2 plants with round and green seeds? O 3/16 O9/16 1/8 01/4 1/2 QUESTION 5 specific example of incomplete penetrance is the human bone disease osteogenesis imperfecta (OI). The majority of people with this disease have a dom utation in one of the hun nonce that produce hme 1 collagen COL1A1 or COL1A2 Raced on the DNA testing of a family with 15 membere amemhare he Save and Submit to save and submit. Click Save All Answers to save all answers. MacBook Airarrow_forward
- PLease help, double and triple check your answers, im using this to study, these questions are NOT graded they are PRACTICE problems. Please help with all 4 parts of this question!!!!!!! A. Your maternal grandpa is colorblind but both your mom and dad are not affected. What are the chances of your sister being colorblind? What are the chances of your brother being colorblind? (Colorblindness is X-linked recessive) B. Regarding the problem above, if your sister’s husband is colorblind, what are the chances that their first son will be colorblind? C. Two genes, A and X, exhibit incomplete linkage. The frequency of each parental gamete (AX and ax) is 45%. What is the approximate frequency of the Ax gamete? D. There are three genes located in the gene order A--B--C on a chromosome. Would you expect the recombination frequency to be higher between A and B or A and C?arrow_forwardQUESTION 6 In Drosophila, sepia eyes (se) and stubble bristles (sb) are recessive to the wildtype eyes and bristles (se* and sb+). A female heterozygous for both genes was test crossed to a male homozygous recessive for both genes. The progeny of this cross are given below: Phenotypes wildtype eyes and wildtype bristles (set, sbt) # of Progeny 334 widltype eyes and stubble bristles (set, sb) 162 sepia eyes and wildtype bristles (se, sb+) 158 sepia eyes and stubble bristles (se, sb) 346 What is the genetic distance (in map units) between these two genes? Are the alleles in the heterozygous female in the cis (coupling) or trans (repulsion) conformation? Are the two genes in this problem unlinked, completely linked or incompletely linked?arrow_forwardQuestion #1 a. Explain why there is a non-Mendelian 2:1 yellow/agouti phenotypic ratio in this cross. b. What is the Raly gene? What does it encode? How does it relate to the lethality of Ay? c. A heterozygous mouse AAy does not produce enough pigment and it is yellow. Homozygous individuals die during development, but AAy heterozygous do not. Why? You may use any graphic aid to explain this, if necessary. This means that you may use a Punnett square or a forking segregation diagram, or computations with fractions.arrow_forward
- QUESTION 1 In pea plants, round (R) is dominant to wrinkled (r), yellow (Y) is dominant to green (y), and tall (T) is dominant to short (t). A homozygous round, heterozygous yellow, short pea plant is crossed with a wrinkled, heterozygous yellow, heterozygous tall plant. Show the branching diagram, along with the probabilities of all genotypes. What is the probability (show work) and phenotype of the following genotype: Rryytt. Attach Filearrow_forwardQuestion 1 The possession of one of two types of earlobes (hanging or attached) is sometimes used to study the inheritance of characteristics in humans. The pedigree shows the different types of earlobes present in three generations. KEY male with hanging earlobes II female with hanging earlobes male with attached earlobes female with attached earlobes III Discuss the type of inheritance shown in the pedigree. In your answer, include reference to the alleles involved using standard notation.arrow_forwardquestion- Color blindness is inherited as a sex-linked recessive disease. A normal male marries a female who is heterozygous for the trait. What percentage of their sons will exhibit color blindness?arrow_forward
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How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY