The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Question
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Chapter 2.2, Problem 44E

(a)

To determine

To find: the percent of bags that weigh less than 9.02 ounces

(a)

Expert Solution
Check Mark

Answer to Problem 44E

Approximately 2.5% of bags weigh less than 9.02 ounces.

Explanation of Solution

Calculation:

The distribution of weights is approximately N (9.12, 0.05). Figure below is a sketch of the Normal density curve with the desired points labeled.

  The Practice of Statistics for AP - 4th Edition, Chapter 2.2, Problem 44E , additional homework tip  1

By the 68-95-99.7 rule, approximately 2.5% of bags weigh less than 9.02 ounces, because 9.02 is two standard deviations below the mean.

  The Practice of Statistics for AP - 4th Edition, Chapter 2.2, Problem 44E , additional homework tip  2

Conclusion:

Hence,approximately 2.5% of bags weigh less than 9.02 ounces

(b)

To determine

To find: the weight range where the middle 68% of bags fall

(b)

Expert Solution
Check Mark

Answer to Problem 44E

Approximately 68% of bags have weights between9.07 ounces and 9.17 ounces.

Explanation of Solution

Calculation:

By the 68-95-99 7 rules, approximately 68% of bags have weights between 9.120.05=9.07 ounces and 9.12+0.05=9.17 ounces.

  The Practice of Statistics for AP - 4th Edition, Chapter 2.2, Problem 44E , additional homework tip  3

Conclusion:

Therefore, approximately 68% of bags have weights between 9.07 ounces and 9.17 ounces.

(c)

To determine

To find: the percent of 9-ounce bags weigh between 8.97 and 9.17 ounces

(c)

Expert Solution
Check Mark

Answer to Problem 44E

Approximately 83.85% of bags have weight between 8.97 and 9.17 ounces.

Explanation of Solution

Calculation:

By the 68-95-99.7 rule, that is approximately 84% (0.68+0.16) of bags have weights lessthan 9.17 ounces, because 9.17 is one standard deviation above the mean. Approximately 0.15% of bags have weight less than 8.97 ounces, because 8.97 is three standard deviations below the mean. So approximately 84%0.15%=83.85% of bags have weight between 8.97 and 9.17 ounces.

  The Practice of Statistics for AP - 4th Edition, Chapter 2.2, Problem 44E , additional homework tip  4

Conclusion:

Therefore,83.85% of bags have weight between 8.97 and 9.17 ounces.

(d)

To determine

To find: the percentile of distribution which weighs 9.07 ounces

(d)

Expert Solution
Check Mark

Answer to Problem 44E

9.07 is the 16th percentile of the weights of these potatochips bags.

Explanation of Solution

Calculation:

The value 9.07 is one standard deviation below the mean. This means that the area to theleft of 9.07 is 0.16. In other words, 9.07 is the 16th percentile of the weights of these potato chips bags.

Conclusion:

Therefore, 9.07 is the 16th percentile of the weights of these potatochips bags.

Chapter 2 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 2.1 - Prob. 4.1CYUCh. 2.1 - Prob. 4.2CYUCh. 2.1 - Prob. 4.3CYUCh. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.2 - Prob. 1.1CYUCh. 2.2 - Prob. 1.2CYUCh. 2.2 - Prob. 1.3CYUCh. 2.2 - Prob. 2.1CYUCh. 2.2 - Prob. 2.2CYUCh. 2.2 - Prob. 2.3CYUCh. 2.2 - Prob. 2.4CYUCh. 2.2 - Prob. 2.5CYUCh. 2.2 - Prob. 3.1CYUCh. 2.2 - Prob. 3.2CYUCh. 2.2 - Prob. 3.3CYUCh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.2 - Prob. 49ECh. 2.2 - Prob. 50ECh. 2.2 - Prob. 51ECh. 2.2 - Prob. 52ECh. 2.2 - Prob. 53ECh. 2.2 - Prob. 54ECh. 2.2 - Prob. 55ECh. 2.2 - Prob. 56ECh. 2.2 - Prob. 57ECh. 2.2 - Prob. 58ECh. 2.2 - Prob. 59ECh. 2.2 - Prob. 60ECh. 2.2 - Prob. 61ECh. 2.2 - Prob. 62ECh. 2.2 - Prob. 63ECh. 2.2 - Prob. 64ECh. 2.2 - Prob. 65ECh. 2.2 - Prob. 66ECh. 2.2 - Prob. 67ECh. 2.2 - Prob. 68ECh. 2.2 - Prob. 69ECh. 2.2 - Prob. 70ECh. 2.2 - Prob. 71ECh. 2.2 - Prob. 72ECh. 2.2 - Prob. 73ECh. 2.2 - Prob. 74ECh. 2.2 - Prob. 75ECh. 2.2 - Prob. 76ECh. 2 - Prob. 1CRECh. 2 - Prob. 2CRECh. 2 - Prob. 3CRECh. 2 - Prob. 4CRECh. 2 - Prob. 5CRECh. 2 - Prob. 6CRECh. 2 - Prob. 7CRECh. 2 - Prob. 8CRECh. 2 - Prob. 9CRECh. 2 - Prob. 10CRECh. 2 - Prob. 11CRECh. 2 - Prob. 12CRECh. 2 - Prob. 1PTCh. 2 - Prob. 2PTCh. 2 - Prob. 3PTCh. 2 - Prob. 4PTCh. 2 - Prob. 5PTCh. 2 - Prob. 6PTCh. 2 - Prob. 7PTCh. 2 - Prob. 8PTCh. 2 - Prob. 9PTCh. 2 - Prob. 10PTCh. 2 - Prob. 11PTCh. 2 - Prob. 12PTCh. 2 - Prob. 13PT
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