Chapter 18, Problem 56A

Write a balanced chemical equation that represents the self-ionization of water.

Interpretation Introduction

Interpretation:

Balanced chemical equation that represents the self-ionization of water is to be written.

Concept introduction:

Balanced chemical equation is the equation in which number of atoms on both sides of each element is equal.

Answer to Problem 56A

$2H_{2}O\rightleftharpoons H_3{O}^{+}+O{H}^{-}$

Explanation of Solution

Self-ionization of water is given by:

$H_{2}O+H_{2}O\rightleftharpoons H_3{O}^{+}+O{H}^{-}$

One water molecule gain hydrogen ion and one molecule lose hydrogen ion. Therefore, it is self ionized.

Conclusion

Balanced equation of self-ionization of water is:

$2H_{2}O\rightleftharpoons H_3{O}^{+}+O{H}^{-}$