Chemistry: Matter and Change

1st Edition

ISBN: 9780078746376

Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher: Glencoe/McGraw-Hill School Pub Co

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Question

Chapter 18, Problem 10STP

Interpretation Introduction

Interpretation:

The gas which travels faster after releasing from long tube is to be determined.

Concept introduction:

Rate of effusion is inversely proportional to square root of mass of the gas and directly proportional to square root of temperature.

Expert Solution & Answer

Answer to Problem 10STP

Sulphur dioxide will travel farther after 5 seconds.

Explanation of Solution

Mass of sulphur dioxide = 32+16×2

= 64g/mol

Mass of xenon = 131g/mol

As sulphur dioxide has less mass so it will effuse faster and reach farther after 5 seconds.

Conclusion

Thus, the gas with less mass is released from the hole faster.

Chapter 18, Problem 9STP

Chapter 18, Problem 11STP

Chapter 18 Solutions

Chemistry: Matter and Change

Ch. 18.1 - Prob. 1PP Ch. 18.1 - Prob. 2PP Ch. 18.1 - Prob. 3PP Ch. 18.1 - Prob. 4PP Ch. 18.1 - Prob. 5SSC Ch. 18.1 - Prob. 6SSC Ch. 18.1 - Prob. 7SSC Ch. 18.1 - Prob. 8SSC Ch. 18.1 - Prob. 9SSC Ch. 18.1 - Prob. 10SSC

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The gas which travels faster after releasing from long tube is to be determined. Concept introduction: Rate of effusion is inversely proportional to square root of mass of the gas and directly proportional to square root of temperature.

Solution Summary: The author explains that the rate of effusion is inversely proportional to square root of mass of the gas, and directly proportionally to temperature. Sulphur dioxide will travel farther after 5 seconds.