Chapter 18, Problem 4STP

Interpretation Introduction

Interpretation:

Energy obtained from a candy bar containing 130gram glucose is to be calculated.

Concept introduction:

Mole concept is used to calculate the result.

According to it,

One mole of a substance is equal to its molar mass.

Answer to Problem 4STP

B

Explanation of Solution

The equation is given by:

$C_6{H}_{12}{O}_6+6O_2\to 6C{O}_2+6H_{2}O+38ATP$

One mole of glucose release 38 ATP

Each ATP releases $30.5kJ$ energy.

Therefore,

$\begin{array}{c}Energyreleasedbyonemoleglucose=38\times 30.5\\ =1159kJ\end{array}$

Molar mass of glucose is $180g/mol$

Therefore,

$\begin{array}{l}180gglu\cos eproducesenergy=1159kJ\\ 130gglu\cos ewillproduceenergy=\frac{1159}{180}\times 130\\ =837kJ\end{array}$

Conclusion

Mathematical calculations show that option B is correct.