Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 16.3, Problem 28SSC
Interpretation Introduction

Interpretation:

The relation between the exponents of rate equation for a chemical reaction and the coefficient in the chemical reaction needs to be explained.

Concept introduction:

The relationship between rate of a chemical reaction and concentration of reactants is expressed by rate law. Rate law is written using the concentration of reactants, each raised to a power which is experimentally determined and rate constant k.

Expert Solution & Answer
Check Mark

Answer to Problem 28SSC

The coefficient of the individual reactants is raised to the concentration in the rate equation.

Explanation of Solution

The exponents of rate equation are the coefficients of the reactants in the chemical equation.

For the reaction,

N2+3H22NH3

Here, the coefficient of N2 is one and the coefficient of H2 is 2. So, in the rate equation, every reactant is raised to the coefficient of them. So, the rate equation is,

Rate=k[N2][H2]3

Conclusion

In the rate equation, every reactant is raised to their coefficient in the chemical equation.

Chapter 16 Solutions

Chemistry: Matter and Change

Ch. 16.1 - Prob. 11SSCCh. 16.1 - Prob. 12SSCCh. 16.2 - Prob. 13SSCCh. 16.2 - Prob. 14SSCCh. 16.2 - Prob. 15SSCCh. 16.2 - Prob. 16SSCCh. 16.2 - Prob. 17SSCCh. 16.2 - Prob. 18SSCCh. 16.3 - Prob. 19PPCh. 16.3 - Prob. 20PPCh. 16.3 - Prob. 21PPCh. 16.3 - Prob. 22PPCh. 16.3 - Prob. 23SSCCh. 16.3 - Prob. 24SSCCh. 16.3 - Prob. 25SSCCh. 16.3 - Prob. 26SSCCh. 16.3 - Prob. 27SSCCh. 16.3 - Prob. 28SSCCh. 16.3 - Prob. 29SSCCh. 16.3 - Prob. 30SSCCh. 16.4 - Prob. 31PPCh. 16.4 - Prob. 32PPCh. 16.4 - Prob. 33PPCh. 16.4 - Prob. 35SSCCh. 16.4 - Prob. 36SSCCh. 16.4 - Prob. 37SSCCh. 16.4 - Prob. 38SSCCh. 16.4 - Prob. 39SSCCh. 16 - Prob. 40ACh. 16 - Explain what is meant by the average rate of a...Ch. 16 - How would you express the rate of the chemical...Ch. 16 - What is the role of the activated complex in a...Ch. 16 - Suppose two molecules that can react collide....Ch. 16 - Prob. 45ACh. 16 - If AB is exothermic, how does the activation...Ch. 16 - In the gas-phase reaction, I2+Cl22ICl,[I2]...Ch. 16 - Prob. 48ACh. 16 - Prob. 49ACh. 16 - Prob. 50ACh. 16 - In general, what is the relationship between...Ch. 16 - Apply collision theory to explain why increasing...Ch. 16 - Prob. 53ACh. 16 - Prob. 54ACh. 16 - Apply collision theory to explain why powdered...Ch. 16 - Hydrogen peroxide decomposes to water and oxygen...Ch. 16 - Prob. 57ACh. 16 - Prob. 58ACh. 16 - Prob. 59ACh. 16 - Prob. 60ACh. 16 - Prob. 61ACh. 16 - Prob. 62ACh. 16 - Prob. 63ACh. 16 - Prob. 64ACh. 16 - Prob. 65ACh. 16 - Prob. 66ACh. 16 - Prob. 67ACh. 16 - Prob. 68ACh. 16 - Prob. 69ACh. 16 - Prob. 70ACh. 16 - Prob. 71ACh. 16 - Prob. 72ACh. 16 - Prob. 73ACh. 16 - Prob. 74ACh. 16 - Prob. 75ACh. 16 - Prob. 76ACh. 16 - Prob. 77ACh. 16 - Prob. 78ACh. 16 - Prob. 79ACh. 16 - Prob. 80ACh. 16 - Prob. 81ACh. 16 - Prob. 82ACh. 16 - Prob. 83ACh. 16 - Differentiate between the shaded areas in Figure...Ch. 16 - Apply the method of initial rates to determine the...Ch. 16 - Prob. 86ACh. 16 - Prob. 87ACh. 16 - Prob. 88ACh. 16 - Create a table of concentrations, starting with...Ch. 16 - Prob. 90ACh. 16 - Prob. 91ACh. 16 - Prob. 92ACh. 16 - Prob. 93ACh. 16 - Prob. 94ACh. 16 - Prob. 95ACh. 16 - Prob. 96ACh. 16 - Prob. 97ACh. 16 - Prob. 99ACh. 16 - Prob. 100ACh. 16 - Prob. 101ACh. 16 - Prob. 102ACh. 16 - Prob. 1STPCh. 16 - Prob. 2STPCh. 16 - Prob. 3STPCh. 16 - Prob. 4STPCh. 16 - Prob. 5STPCh. 16 - Prob. 6STPCh. 16 - Prob. 7STPCh. 16 - Prob. 8STPCh. 16 - Use the diagram below to answer Questions 8 and 9....Ch. 16 - Prob. 10STPCh. 16 - Prob. 11STPCh. 16 - Prob. 12STPCh. 16 - Prob. 13STPCh. 16 - Prob. 14STPCh. 16 - Prob. 15STPCh. 16 - Prob. 16STPCh. 16 - Prob. 17STPCh. 16 - Prob. 18STPCh. 16 - Prob. 19STP
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