Interpretation:
The mass of iron (III) chloride needed to prepare 1.00 L of a 0.22 M solution needs to be determined.
Concept introduction:
The molarity of a solution is given by the formula,
Answer to Problem 95A
The mass of iron (III) chloride needed to prepare 1.00 L of a 0.22 M solution is 14.2 g.
Explanation of Solution
Given, volume of solution = 1.00 L
Molarity=0.22 M
We have to first calculate the value of moles of solute in order to calculate the mass of iron (III) chloride using the formula, ‘
Using the given value of molarity and volume in the above formula we calculate the mass of iron (III) chloride.
So,
So, required number of moles of iron (III) chloride is 0.255 mol.
So, we multiply 0.255 mol by the molar mass of
Therefore,
The required mass of iron (III) chloride is 14.2 g.
Chapter 16 Solutions
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