Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 15, Problem 4PDQ
Summary Introduction
To determine: The reason behind no detection of observable
Introduction: The mutations are defined as the variation caused in the
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A mutation creates a dominant negative allele of a particular gene. The gene encodes a protein that forms a trimer within the cell. If one or more of the subunits has the mutant structure, the entire trimeric protein is inactive. In a heterozygous cell, if the proteins of both alleles are present at the same levels, what percent of the trimers present in the cell will be active?
A) 100%
B) 5%
C) 50%
D) 33%
E) 5%
“In an organism that reproduces asexually, there is no difference between a somatic cell mutation and a germ line mutation.” Is this statement true? Explain.
The oncogenic protein BETA promotes entry into the S phase of the cell cycle. Phosphorylation of BETA at the amino acid Tyr98 causes BETA to be degraded by the proteasome, thus limiting its abundance. A mutation in the codon encoding Tyr98 changes this residue to Cys, which cannot be phosphorylated. What is the best description of this mutant allele?a) antimorphb) hypermorphc) hypomorphd) amorphe) neomorph
Chapter 15 Solutions
Concepts of Genetics (12th Edition)
Ch. 15 - If a point mutation occurs within a human egg cell...Ch. 15 - One of the most famous cases of an X-linked...Ch. 15 - The cancer drug melphalan is an alkylating agent...Ch. 15 - Geneticists often use the alkylating agent...Ch. 15 - Six months pregnant, an expectant mother had a...Ch. 15 - Six months pregnant, an expectant mother had a...Ch. 15 - HOW DO WE KNOW? In this chapter, we focused on how...Ch. 15 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 15 - What is a spontaneous mutation, and why are...Ch. 15 - Prob. 4PDQ
Ch. 15 - Prob. 5PDQCh. 15 - Why is a random mutation more likely to be...Ch. 15 - Most mutations in a diploid organism are...Ch. 15 - What is the difference between a silent mutation...Ch. 15 - Describe a tautomeric shift and how it may lead to...Ch. 15 - Contrast and compare the mutagenic effects of...Ch. 15 - Why are frameshift mutations likely to be more...Ch. 15 - Why are X rays more potent mutagens than UV...Ch. 15 - DNA damage brought on by a variety of natural and...Ch. 15 - Contrast the various types of DNA repair...Ch. 15 - Mammography is an accurate screening technique for...Ch. 15 - A significant number of mutations in the HBB gene...Ch. 15 - Describe how the Ames test screens for potential...Ch. 15 - Prob. 18PDQCh. 15 - Compare DNA transposons and retrotransposons. What...Ch. 15 - Prob. 20PDQCh. 15 - In maize, a Ds or Ac transposon can alter the...Ch. 15 - Prob. 22PDQCh. 15 - In a bacterial culture in which all cells are...Ch. 15 - Presented here are hypothetical findings from...Ch. 15 - Prob. 25ESPCh. 15 - Prob. 26ESPCh. 15 - What evidence indicates that mutations in human...Ch. 15 - Among Betazoids in the world of Star Trek, the...Ch. 15 - Skin cancer carries a lifetime risk nearly equal...Ch. 15 - It has been noted that most transposons in humans...Ch. 15 - Mutations in the IL2RG gene cause approximately 30...
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