Concept explainers
(a)
To find: Thenumber of members that used the centres fitness facilities during the month.
(a)
Answer to Problem 8CFU
The number of members is 120.
Explanation of Solution
Given:
The table for the given data set is shown in the Table 1
Table 1
Visits | 1-5 | 5-9 | 9-13 | 13-17 | 17-21 | 21-25 | 25-29 | 29-33 |
Members | 2 | 8 | 15 | 6 | 38 | 31 | 13 | 7 |
Calculation:
Consider the sum of the number of members is,
As, the sum of the number of member is
(b)
To find: The mean of the data.
(b)
Answer to Problem 8CFU
The mean of the data is
Explanation of Solution
Consider the table shown in Table 2
Table 2
Visits | 1-5 | 5-9 | 9-13 | 13-17 | 17-21 | 21-25 | 25-29 | 29-33 |
Members | 2 | 8 | 15 | 6 | 38 | 31 | 13 | 7 |
Mid values | 3 | 7 | 11 | 15 | 19 | 23 | 27 | 31 |
6 | 56 | 165 | 90 | 722 | 713 | 351 | 217 |
From the above table consider the value of the mean is obtained by the formula,
(c)
To find: The median class of the data.
(c)
Answer to Problem 8CFU
Thus, the median is
Explanation of Solution
Consider the table shown in Table 1, as the scores 120 in the frequency distribution and the 60 scores are below the median and 60 are above the median.
Then, from the Table 1, the least cumulative frequency that is more than or equal to the 60 to 69 is
(d)
To find: The median of the data.
(d)
Answer to Problem 8CFU
The value of the mode is
Explanation of Solution
Consider the proportion to find the value of the medina by finding the ratio of the differences the cumulative frequencies and the upper limits of the classes.
Consider the figure for the proportion is shown in Figure 1
Figure 1
Then, by taking the proportion the mode is,
Then, the mode is,
Chapter 14 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
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